Quasilinear parabolic problems with nonlinear boundary conditions
Quasilinear parabolic problems with nonlinear boundary conditions
Quasilinear parabolic problems with nonlinear boundary conditions
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[29, Section 2.1]) we have gµ(A) = µ(µ + A α ) −1 ; the problem is to show that the family<br />
{gµ(A) : µ ∈ Σφα } ⊂ B(X) is R-bounded.<br />
To this purpose we consider first appropriate approximations of A. For ε > 0 set<br />
Aε = (ε + A)(1 + εA) −1 . Then Aε is bounded, sectorial and invertible, for each ε > 0,<br />
and φAε ≤ φA, see [29, Prop. 1.4]. Furthermore, Aε is also R-sectorial <strong>with</strong> R-angle<br />
φR Aε ≤ φR A , and the R-bounds RAε(φ) are uniformly <strong>with</strong> respect to ε > 0, for each fixed<br />
φ < π − αφR A . To see this verify that the subsequent relation is valid.<br />
λ(λ + Aε) −1 = λ<br />
λ + ε ϕε(λ)(ϕε(λ) + A) −1 + ελ<br />
1 + ελ A(ϕε(λ) + A) −1 , λ ∈ Σφ,<br />
where ϕε(λ) = (ε + λ)/(1 + ελ). Here it is essential that the functions ϕε leave all<br />
sectors Σφ invariant. The claim follows then by the rule R(T1 + T2) ≤ R(T1) + R(T2)<br />
and Kahane’s contraction principle, cf. [29, Section 3.1].<br />
We next show that RA α ε (φα) ≤ C < ∞ uniformly w.r.t. ε > 0. To this end we<br />
employ the following representation formula for the operators gµ(Aε), cf. the proof of<br />
Theorem 2.3 in [29].<br />
gµ(Aε) = µ<br />
2πi<br />
� ∞ e<br />
(<br />
0<br />
iθα − ei(θ−2π)α (µ + rαeiα(θ−2π) )(µ + rαeiαθ ) )rαe iθ (re iθ − Aε) −1 dr<br />
n�<br />
+ µ<br />
j=1<br />
λ 1−α<br />
j (λj − Aε) −1 /α. (2.7)<br />
This formula is obtained by contracting the contour Γψ from the Dunford integral for<br />
gµ(Aε) to a suitable halfray Γα = [0, ∞)eiθ , <strong>with</strong> φR A < ψ < θ ≤ π, and using Cauchy’s<br />
theorem as well as residue calculus. The numbers λj = λj(µ), j = 1, . . . , n denote the<br />
zeros of µ + λα ; note that there are only finitely many of them, and n = 0 means that<br />
there are none. The angle θ = θ(µ) is chosen such that for some δ > 0, we have <strong>with</strong><br />
ϕ = arg µ the inequalities |ϕ−αθ(µ)−(2k+1)π| ≥ δ and |ϕ+2απ−αθ(µ)−(2k+1)π| ≥ δ<br />
for all µ ∈ Σφα and k ∈ Z. From (2.7) we get <strong>with</strong> µ+λα j = 0 and the change of variables<br />
r = (|µ|s) 1/α<br />
� ∞<br />
gµ(Aε) =<br />
0<br />
−<br />
e iϕ (e i(2π−θ)α − e −iθα )(1 + s) 2<br />
2παi (e i(ϕ−αθ) + s)(e i(ϕ+2απ−αθ) + s)<br />
� �� �<br />
| · |≤C<br />
n�<br />
λj(λj − Aε) −1 /α.<br />
j=1<br />
(|µ|s) 1<br />
α e iθ ((|µ|s) 1<br />
α e iθ −Aε) −1<br />
ds<br />
(1 + s) 2<br />
Hence gµ(Aε) ∈ C0aco ({λ(λ + Aε) −1 : λ ∈ Σπ−ψ}), where aco (T ) means the closure in<br />
the strong operator topology of the absolute convex hull of the family T . Proposition<br />
3.8 in [29] and the above observation concerning the R-bounds RAε(φ) then yield<br />
RA α ε (φα) ≤ 2C0RAε(ψ) ≤ C < ∞,<br />
uniformly w.r.t. ε > 0.<br />
The assertion RA α(φα) < ∞ can now be established by the following approximation<br />
argument, which relies on gµ(Aε)x → gµ(A)x as ε → 0+ on D(A) ∩ R(A), which is a<br />
dense subset of X, see [29, Thm. 2.1]. Set T = {gµ(A) : µ ∈ Σφα } and Tε = {gµ(Aε) :<br />
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