7.03 Problem Set 1 Solutions 1. 2.
7.03 Problem Set 1 Solutions 1. 2.
7.03 Problem Set 1 Solutions 1. 2.
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. cM = (100) x (fraction of gametes that crossover between gene 1 and gene 2)fraction of gametes that crossover = cM/100fraction of gametes that will NOT crossover = 1 – (cM/100)p(aabb child) = p(a b chromosome from mom) and p(a b chromosome from dad)= (1/2) x (1-[cM/100]) x (1/2)= (1/4) x (1 – [cM/100])c. X a = trait 1 X b = trait 2 X ab = traits 1 and 2 X + = wtDad’s genotype = X a+ YMom’s genotype = X ab X ++*Mom’s father was X ab Y, so she received the X ab chromosome from him, but must beheterozygous for both traits since she’s unaffectedp(X ab Y child) = p(X ab from mom)= (1/2) x (0.9) = 0.45d. p(X ab X ab child) = p(X ab from mom) and p(X ab from dad)= (.45) x 0= 0
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