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RTS-P-XIII-11-AIP-Pre-3TEST SERIES FOR AIPMT-PRE(FULL SYLLABUS)Time : 3 : 00 Hrs. MAX MARKS: 800Name : ______________________________________Roll No. : ____________________ Date : _____________________Instructions to CandidatesGENERAL:1. This paper contains 200 Qs. in all. All questions are compulsory.2. There is Negative Marking. Guessing of answer is harmful.3. Write your Name, Roll No. & Date in the space provided on this cover page of question paper.4. The question paper contains blank space for your rough work. No additional sheet will be providedfor rough work.5. The answer sheet, machine readable Optical Mark Recognition (OMR) is provided separately.6. Do not break the seals of the question paper booklet before being instructed to do so by theinvigilator.7. Blank papers, Clipboards, Log tables, Slide Rule, Calculators, Cellular Phones, Pagers andElectronic Gadgets in any form are not allowed to be carried inside the examination hall.SEALMARKING SCHEME:1. Each Question has four options, only one option is correct. For each incorrect response, one-mark wouldbe deducted.2. In Physics : Q. 1 - 50 carry 4 marks each,In Chemistry : Q. 51 - 100 carry 4 marks each,In Biology : Q. 101 - 200 carry 4 marks each,CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.)Ph: 0744-3040000, Fax (0744) 3040050email : info@careerpointgroup.com ; Website : www.careerpointgroup.comNow, Schedule practice questions are available on internet also, Visit www.examtayari.com


PHYSICSQ.1 A cubical block of wood 10cm on a side floats atthe interface between oil and water with its lowersurface horizontal and 4cm below the interface. Thedensity of oil is 0.6gcm –3 . The mass of block isQ.1 ydM+h dk ,d ?kukdkj CykWd ftldh ,d Hkqtk 10cmdh gS] rsy rFkk ty dh vUrZi`"B ij bl izdkj rSjjgk gS fd bldh fupyh lrg {kSfrt jgs rFkkvUrZi`"B ls 4cm uhps gksA rsy dk ?kuRo 0.6gcm –3 gSACykWd dk nzO;eku gS&Block6cm4cmBlock6cm4cm(1) 706 g (2) 607 g (3) 760 g (4) 670 gQ.2 A small spherical solid ball is dropped from a greatheight in a viscous liquid. Its journey in the liquidis best described in the diagram given below by the(1) 706 g (2) 607 g (3) 760 g (4) 670 gQ.2 ,d NksVh xksykdkj Bksl xsan cgqr vf/kd Å¡pkbZ ls,d ';ku nzo esa fxjk;h tkrh gSA nzo esa bldh ;k=kkdks Js"B n'kkZus okyk xzkQ fuEu esa ls dkSulk gS&Velocity (v)Time (t)ABCD(1) Curve A (2) Curve B(3) Curve C (4) Curve DVelocity (v)ABCDTime (t)(1) oØ A (2) oØ B(3) oØ C (4) oØ DQ.3 The maximum height attained by a projectile isincreased by 10% by increasing its speed ofprojection, without changing the angle of projection.The percentage increase in the horizontal range will be(1) 5 % (2) 10 % (3) 15 % (4) 20 %Q.4 Trajectories of two projectiles are shown in figure.Let T 1 and T 2 be the time periods and u 1 and u 2 theirspeeds of projection. Then -yQ.3 ,d iz{ksI; }kjk izkIr vf/kdre Å¡pkbZ bldh iz{ksi.kpky dks c u 2 (4) u 1 < u 2(1) T 2 > T 1 (2) T 1 = T 2(3) u 1 > u 2 (4) u 1 < u 2CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 2


Q.5 At the instant a motor bike starts from rest in agiven direction, a car overtakes the motor bike, bothmoving in the same direction. The speed-timegraphs for motor bike and car are represented byOAB and CD respectively.Speed (in ms –1 )60C4020AO 3 6 9 12 15 18 21 24Time (in s)(1) at t = 18 s the motor bike and car are 180 mapart(2) at t = 18 s the motor bike and car are 720 mapart(3) the relative distance between motor bike andcar reduces to zero at t = 27 s and both are1080 m far from origin(4) the relative distance between motor bike andcar always remains sameQ.6 In a loop-the-loop, a body starts at a heighth = 2R. The minimum speed with which the bodymust be pushed down initially in order that it maybe able to complete the vertical circle is -(1) 2 gR (2) gR (3) 3 gR (4) 2 gRQ.7 A body cools from 75°C to 65°C in 5 minutes ina room where the temperature is 25°C. Thetemperature of the body at the end of next 5minutes will be -(1) 55°C (2) 56°C (3) 57°C (4) 58°CQ.8 In which of the following processes is the heattransfer promarily due to radiation ?(1) Boiling of water(2) Land and sea breezes(3) Heating of a metal rod placed over a flame(4) Heating of the glass surface of an electricbulb due to current in its filamentQ.9 A vessel contains a mixture of 1 mole of oxygenand two moles of nitrogen at 300 K. The ratio ofthe rotational kinetic energy per O 2 molecule tothat per N 2 molecule is -(1) 1 : 1(2) 1 : 2(3) 2 : 1(4) depends on the moment of inertia of the twomoleculesBDQ.5 fdlh {k.k ij ,d eksVj ckbd ,d nh xbZ fn'kk esafojke ls izkjEHk gksrh gS] ,d dkj eksVj ckbd dksvksoj Vsd djrh gS] nksuksa leku fn'kk esa xfrekugSA eksVj ckbd rFkk dkj ds fy, pky&le; xzkQØe'k% OAB o CD }kjk iznf'kZr fd;s x;s gSASpeed (in ms –1 )60C4020AO 3 6 9 12 15 18 21 24Time (in s)(1) t = 18 s ij eksVj ckbd rFkk dkj ijLij 180 mij gS(2) t = 18 s ij eksVj ckbd rFkk dkj ijLij 720 mij gS(3) eksVj ckbd rFkk dkj ds e/; vkisf{kd nwjht = 27 s ij ?kVdj 'kwU; gks tkrh gS rFkk nksuksaewy fcUnq ls 1080 m dh nwjh ij gS(4) eksVj ckbd rFkk dkj ds e/; vkisf{kd nwjhlnSo leku cuh jgrh gSAQ.6 ,d o`Ùkh; ywi esa ,d oLrq h = 2R Å¡pkbZ ls izkjEHkgksrh gSA U;wure pky ftlls oLrq dks izkjEHk esa uhps/kdsyk tkuk pkfg;s rkfd ;g Å/okZ/kj o`Ùk iw.kZ djlds] gS&(1) 2 gR (2) gR (3) 3 gR (4) 2 gRQ.7 ,d oLrq ,d dejs esa tgk¡ rki 25°C gS] 75°C ls65°C rd 5 feuV esa B.Mh gksrh gSA vxys5 feuV ds vUr esa oLrq dk rki gksxk&(1) 55°C (2) 56°C (3) 57°C (4) 58°CQ.8 fuEu esa ls fdl izØe esa Å"ek lapj.k fofdj.k dsdkj.k gksrk gS ?(1) ty dk mcyuk(2) /kjrh rFkk leqnz dh gok,sa(3) ,d /kkfRod NM+ dks Tokyk ij j[kdj xeZ djuk(4) fo|qr cYc dh dk¡p dh lrg dk bldsfQykeasV eas /kkjk izokg ds dkj.k xeZ gksukQ.9 ,d ik=k esa 300 K ij 1 eksy vkWDlhtu dk rFkk nkseksy ukbVªkstu dk feJ.k fo|eku gSA izfr O 2 v.kq?kw.kZu xfrt ÅtkZ dk izfr N 2 v.kq ?kw.kZu xfrtÅtkZ ls vuqikr gS&(1) 1 : 1(2) 1 : 2(3) 2 : 1(4) nksuksa v.kqvksa ds tM+Ro vk?kw.kZ ij fuHkZj djrk gSBDCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 3


Q.10 The ratio of adiabatic bulk modulus andisothermal bulk modulus of a gas is (γ = C p /C v )(1) 1 (2) γ(3)γ(γ –1)( γ –1)(4)γQ.11 Which one of the following statements is NOTtrue about the evaporation process ?(1) Evaporation takes place from the surface of aliquid at all temperatures(2) The rate of evaporation depends upon the areaof the exposed surface of the liquid, nature ofthe liquid and its temperature(3) The rate of evaporation is independent of thepressure to which the liquid is subjected(4) The cooling produced in evaporation is aconsequence of the fact that a liquid haslatent heatQ.12 In figure curves AB and CD represent the relationbetween pressure P and volume V of an ideal gas.One of the curves represents an isothermalexpansion and the other represents an adiabaticexpansion. Which curve represents an adiabaticexpansion ?CPAQ.10 ,d xSl ds #)ks"eh; vk;ru izR;kLFkrk xq.kkad rFkklerkih; vk;ru izR;kLFkrk xq.kkad dk vuqikr gS&(γ = C p /C v )(1) 1 (2) γγ( γ –1)(3)(4)(γ –1)γQ.11 ok"iu izfØ;k ds fo"k; eas fuEu esa ls dkSulk dFkulgh ugha gS ?(1) lHkh rkiksa ij ,d nzo dh lrg ls ok"iu gksuk(2) ok"iu dh nj nzo dh [kqyh lrg ds {ks=kQy] nzodh izd`fr rFkk blds rki ij fuHkZj djrh gS(3) ok"iu dh nj nzo ij yxk;s x;s nkc ls Lora=kgksrh gS(4) ok"iu esa mRiUu 'khryu bl rF; ij vk/kkfjrgS fd ,d nzo dh xqIr Å"ek gksrh gSQ.12 fp=k esa oØ AB o CD ,d vkn'kZ xSl ds nkc P ovk;ru V ds chp lEcU/k dks iznf'kZr djrs gSA ,doØ lerkih; izlkj dks tcfd nwljk #)ks"eh;izlkj dks O;Dr djrk gSA dkSulk oØ #)ks"eh;izlkj dks O;Dr djrk gS ?CPABDV(1) curve AB (2) curve CD(3) both (4) neitherQ.13 A uniform rope of length L resting on africtionless horizontal surface is pulled at one endby a force F. What is the tension in the rope at adistance l from the end where the force is applied -⎛ l ⎞(1) F (2) F ⎜1+ ⎟⎝ L ⎠(3) LF⎛ l ⎞(4) F ⎜1– ⎟⎝ L ⎠BDV(1) oØ AB (2) oØ CD(3) nksuksa (4) dksbZ ughaQ.13 ?k"kZ.k jfgr {kSfrt lrg ij fojke eas fLFkr ,dleku psu ds ,d fljs dks F cy yxkdj [khapktkrk gSA ;fn psu dh yEckbZ L gS] rks bl fljs lsl nwjh ij ruko cy gksxk&⎛ l ⎞(1) F (2) F ⎜1+ ⎟⎝ L ⎠(3) LF⎛ l ⎞(4) F ⎜1– ⎟⎝ L ⎠CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 4


Q.14 A mass of 20 kg moving with speed of 10 m/scollides with another stationary mass of 5 kg as aresult of the collision the two masses sticktogether. The kinetic energy of composite mass is -(1) 600 J (2) 1000 J(3) 800 J (4) 1200 JQ.15 A body is falling under gravity. When it loses agravitational potential energy by U, its speed is V.The mass of the body shall be -(1)2UV(2)U2V(3)2UV2(4)U22VQ.16 A neutron moving with velocity U collideselastically with an atom of mass number A. If thecollision is head on and the initial kinetic energyof neutron is E then final kinetic energy of theneutron after the collision is -2⎛ A + 1⎞(1) ⎜ ⎟⎠ E⎛(2) ⎜⎝ A –1⎝AA +– 1⎞⎟⎠1⎛ A –1⎞(3) ⎜ ⎟ E⎛ A + 1⎞(4) ⎜ ⎟ E⎝ A +1 ⎠ ⎝ A –1 ⎠Q.17 A ball falls on stationary horizontal floor fromheight 'h'. If the coefficient of restitution is e.Then the total time taken by the ball beforebecoming to rest -1+ e 2h1– e 2h(1)(2)e g1+e g1+ e 2h(3)1– e g2E1+e 2h(4)2e gQ.18 A uniform chain of length L and mass M is lyingon a smooth table and one fifth of its hangingvertically down the edge of table. The workrequired to pull the hanging part on the table -(1)MgL18(2)MgL50Q.19 Acceleration of the block is -MgL(3) 200(4) ZeroQ.14 20 kg dk ,d fi.M 10 m/s dh pky ls 5 kg dsfLFkj fi.M ls iw.kZr% vizR;kLFk VDdj djrk gSAVDdj ds i'pkr~ la;qDr fi.M dh xfrt ÅtkZgksxh&(1) 600 J (2) 1000 J(3) 800 J (4) 1200 JQ.15 xq#Roh; {ks=k esa ,d oLrq fxjrh gSA tc fLFkfrtÅtkZ esa gkfu U gS] rks bldk osx V gSA bldknzO;eku gksxk&2U(1) V(2)U2V(3)2UV 2VQ.16 ,d U;wVªkWu U osx ls xfr djrk gqvk nzO;eku la[;kA ds ,d ijek.kq ls izR;kLFk #i ls Vdjkrk gSA;fn VDdj lEeq[k gS rFkk U;wVªkWu dh izkjfEHkdxfrt ÅtkZ E gks] rc VDdj ds i'pkr~ U;wVªkWu dhvfUre xfrt ÅtkZ gksxh&2⎛ A + 1⎞(1) ⎜ ⎟⎠ E⎛ A – 1⎞(2) ⎜ ⎟⎠ E⎝ A –1⎝ A + 1⎛ A –1⎞(3) ⎜ ⎟ E⎛ A + 1⎞(4) ⎜ ⎟ E⎝ A +1 ⎠ ⎝ A –1 ⎠Q.17 ,d xSan {kSfrt lrg ij 'h' Å¡pkbZ ls fxjkbZ tkrhgSA ;fn izR;koLFkku xq.kkad e gSA rks fLFkj voLFkk easvkus esa xsan le; ysxh&1+ e 2h1– e 2h(1)(2)e g1+e g1+ e 2h(3)1– e g22(4)1+e 2h(4)2e gQ.18 L yEckbZ ,oa M nzO;eku dh ,d le#i psu ,dfpduh est ij fLFkr gS rFkk bldh yEckbZ dk 1/5Hkkx est ds dksus ls Å/okZ/kj uhps yVd jgk gSAyVds gq;s Hkkx dks est ij [khapus esa fd;k x;kvko';d dk;Z gS&MgL MgL MgL(1) (2) (3) (4) 'kwU;18 50 200Q.19 CykWd dk Roj.k gksxk&U26kg 12kg(1) g/3 (2) 4g (3) g (4) 2g6kg 12kg(1) g/3 (2) 4g (3) g (4) 2gCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 5


Q.20 A small coin is resting on the bottom of a beakerfilled with a liquid. A ray of light from the cointravels upto the surface of the liquid and movesalong its surface (see figure).3cmQ.20 ,d NksVk flDdk nzo ls Hkjs ,d chdj dh ryh ijfLFkj j[kk gSA flDds ls ,d izdk'k fdj.k nzo dhlrg rd lapfjr gksrh gS rFkk mldh lrg dsvuqfn'k xfr djrh gS (fp=k ns[ksa)A3cm4cm4cmCoinHow fast is the light travelling in the liquid ?(1) 1.8 × 10 8 m/s (2) 2.4 × 10 8 m/s(3) 3.0 × 10 8 m/s (4) 1.2 × 10 8 m/sQ.21 The focal length of a spherical mirror is -(1) maximum for red light(2) maximum for blue light(3) maximum for white light(4) same for all lightsQ.22 Which mirror is to be used to obtain a parallelbeam of light from a small lamp ?(1) Plane mirror (2) Convex mirror(3) Concave mirror (4) Any one of theseQ.23 A stream of photons is impinging normally on acompletely absorbing screen in vacuum. Ifirradiance (energy/area/time) is I, then thepressure on the screen is -Ic(1) (2) c I(3) cI (4) zeroQ.24 How many red photons (wavelength λ) must strikea totally reflecting screen per second at normalincidence, if the exerted force is to be 1 N ?(1) hλ(2)2λh(3)λ2h(4) infinityQ.25 A metal surface of work function 1.07 eV isirradiated with light of wavelength 332 nm. Theretarding potential required to stop the escape ofphoto-electrons is -(1) 4.81 eV (2) 3.74 eV(3) 2.66 eV (4) 1.07 eVCoinnzo esa izdk'k fdruh rsth ls xeu djrk gS \(1) 1.8 × 10 8 m/s (2) 2.4 × 10 8 m/s(3) 3.0 × 10 8 m/s (4) 1.2 × 10 8 m/sQ.21 ,d xksyh; niZ.k dh Qksdl nwjh gksrh gS-(1) yky izdk'k ds fy, vf/kdre(2) uhys izdk'k ds fy, vf/kdre(3) 'osr izdk'k ds fy, vf/kdre(4) lHkh izdk'k ds fy, lekuQ.22 dkSulk niZ.k ,d NksVs ySEi ls izkIr izdk'k ds ,dlekUrj iqat dks izkIr djus esa iz;qDr gksrk gS ?(1) lery niZ.k (2) mÙky niZ.k(3) vory niZ.k (4) buesa ls dksbZ HkhQ.23 QksVkWuks dh ,d /kkjk fuokZr esa ,d iw.kZ vo'kks"kdinsZ ij vfHkyEcr~ Vdjkrh gSA ;fn fdj.ku(ÅtkZ/{ks=kQy/le;) I gS] rc insZ ij nkc gS&Ic(1) (2) c I(3) cI (4) 'kwU;Q.24 fdrus yky QksVkWu (rjaxnS/;Z λ) ,d iw.kZr% ijkorZdinsZ ij izfr lsd.M vfHkyEc #i ls vkifrr gksuspkfg;s] ;fn vkjksfir cy 1 N gS ?(1) hλ(2)2λh(3)λ2h(4) vuUrQ.25 1.07 eV dk;ZQyu okyh ,d /kkfRod lrg dks 332nm rjaxnS/;Z ds izdk'k ls fdj.khr fd;k tkrk gSAQksVksbysDVªkWuksa ds iyk;u dks jksdus ds fy,vko';d foHko gS&(1) 4.81 eV (2) 3.74 eV(3) 2.66 eV (4) 10.7 eVCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 6


Q.26 The de-Broglie wavelength of a 1 kg objectmoving with speed of 1 ms –1 is -(1) 6.6 × 10 –34 m (2) 6.0 × 10 –34 m(3) 6.6 × 10 –10 m (4) 6.0 × 10 –10 mQ.27 The phenomenon inverse to photoelectric effect is -(1) Compton effect (2) Raman effect(3) Pair production (4) Production of X-raysQ.28 Of the following properties, the photon does notpossess -(1) rest mass (2) momentum(3) energy (4) frequencyQ.29 The frequency of fork A is 2% more than thefrequency of standard fork whereas the frequencyof fork B is 2% less. The fork A and B produce 4beat per second. The frequency of standard forkwill be -(1) 100 Hz (2) 106 Hz(3) 103 Hz (4) 112 HzQ.30 Two waves of intensities I and 4I produceinterference. Then the intensity at constructiveand destructive interference respectively is -(1) 3I, 5I (2) 5I, 3I(3) I, 9I (4) 9I, IQ.31 The correct relation between phase difference (δ)and path difference (∆) is -2πλ(1) δ = ∆ (2) δ = ∆λ2π∆(3) δ = (4) δ = ∆λλQ.32 A simple pendulum performs simple harmonicmotion about x = 0 with an amplitude a and timeperiod T. The speed of the pendulum atx = a/2 will be :(1)πa(3)Tπa 3T(2)(4)πa 32T3π2 aTQ.26 1 ms –1 dh pky ls xfreku 1kg dh ,d oLrq dhMh&czksXyh rjaxnS/;Z gS&(1) 6.6 × 10 –34 m (2) 6.0 × 10 –34 m(3) 6.6 × 10 –10 m (4) 6.0 × 10 –10 mQ.27 izdk'k fo|qr izHkko dh foijhr ?kVuk gS&(1) dkWEiVu izHkko (2) jeu izHkko(3) ;qXe mRiknu (4) X-fdj.kksa dk mRiknuQ.28 fuEu fo'ks"krkvksa esa ls QksVksu ugha j[krk gS&(1) fojke nzO;eku (2) laosx(3) ÅtkZ (4) vko`fÙkQ.29 Lofj=k A dh vko`fÙk ,d ekud Lofj=k dh vko`fÙkls 2% vf/kd gS tcfd Lofj=k B dh vko`fÙk 2%de gSA Lofj=k A o B, 4 foLiUn izfr lsd.MmRiUu djrs gSA ekud Lofj=k dh vko`fÙk gksxh&(1) 100 Hz (2) 106 Hz(3) 103 Hz (4) 112 HzQ.30 I rFkk 4I rhozrkvksa dh nks rjaxs O;frdj.k mRiUudjrh gSA laiks"kh rFkk fouk'kh O;frdj.k dh rhozrkØe'k% gS&(1) 3I, 5I (2) 5I, 3I(3) I, 9I (4) 9I, IQ.31 dykUrj (δ) rFkk iFkkUrj (∆) ds e/; lgh lEcU/k gS&2πλ(1) δ = ∆ (2) δ =λ2π∆(3) δ = (4) δ = ∆λλQ.32 ,d ljy yksyd x = 0 ds lkis{k a vk;ke rFkk TvkorZdky ds lkFk ljy vkorZ xfr djrk gSAx = a/2 ij yksyd dh pky gksxh&(1)πa(3)Tπa 3T(2)(4)πa 32T3π2 aT∆CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 7


Q.33 Which one of the following equations of motionrepresents simple harmonic motion ?(1) Acceleration = kx(2) Acceleration = – k 0 x + k 1 x 2(3) Acceleration = – k (x + a)(4) Acceleration = k(x + a)Where k, k 0 , k 1 and a are all positiveQ.34 The electric field part of an electromagnetic wavein a medium is represented by :E x = 0N ⎡E y = 2.5 cos⎛ 6 rad ⎞⎢⎣ ⎜2π×10 ⎟t–⎛ ⎞ ⎤⎜ π×− rad10 2 ⎟x⎥ C ⎝ m ⎠ ⎝ s ⎠ ⎦E z =0. The wave is :(1) Moving along –x direction with frequency 10 6Hz and wavelength 200m(2) Moving along y direction with frequency2π×10 6 Hz and wavelength 200m(3) Moving along x direction with frequency 10 6Hz and wavelength 100m(4) Moving along x direction with frequency10 6 Hz and wavelength 200mQ.35 A bar magnet having a magnetic moment of2 × 10 4 JT –1 is free to rotate in a horizontal plane.A horizontal magnetic field B = 6 × 10 –4 T existsin the space. The work done in taking the magnetslowly from a direction parallel to the field to adirection 60º from the field is :(1) 2 J (2) 0.6 J (3) 12 J (4) 6 JQ.36 The magnetic force acting on a charged particleof charge – 2µC in a magnetic field of 2T actingin y direction, when the particle velocity is( 2î + 3ĵ) × 10 6 ms –1 , is :(1) 8N in z - direction(2) 8N in – z - direction(3) 4N in z - direction(4) 8N in y - directionQ.33 xfr dh fuEu lehdj.kksa esa ls dkSulh ljy vkorZxfr dks O;Dr djrh gS ?(1) Roj.k = kx(2) Roj.k = – k 0 x + k 1 x 2(3) Roj.k = – k (x + a)(4) Roj.k = k(x + a)tgk¡ k, k 0 , k 1 rFkk a lHkh /kukRed gSQ.34 fdlh ek/;e esa ,d fo|qr pqEcdh; rjax ds ,dfo|qr {ks=k ds Hkkx fuEu izdkj iznf'kZr fd;s x;s gSAE x = 0N ⎡E y = 2.5 cos⎛ 6 rad ⎞⎢⎣ ⎜2π×10 ⎟t–⎛ ⎞ ⎤⎜ π×− rad10 2 ⎟x⎥ C ⎝ m ⎠ ⎝ s ⎠ ⎦E z = 0, rjax gS&(1) –x fn'kk esa xfreku ftldh vko`fÙk 10 6 Hz rFkkrjaxnS/;Z 200m gS(2) y-fn'kk esa xfreku ftldh vko`fÙk 2π×10 6 HzrFkk rjaxnS/;Z 200m gS(3) x fn'kk esa xfreku ftldh vko`fÙk 10 6 Hz rFkkrjaxnS/;Z 100m gS(4) x fn'kk eas xfreku ftldh vko`fÙk 10 6 Hz rFkkrjaxnS/;Z 200m gSQ.35 ,d NM+ pqEcd ftldk pqEcdh; vk?kw.kZ2 × 10 4 JT –1 gS] ,d {kSfrt ry esa ?kweus dks Lora=kgSA ,d {kSfrt pqEcdh; {ks=k B = 6 × 10 –4 T vkdk'kesa fo|eku gSA pqEcd dks {kS=k ds lekUrj fn'kk ls{kS=k ls 60º dh fn'kk rd /khjs ls ys tkus esa fd;kx;k dk;Z gS&(1) 2 J (2) 0.6 J (3) 12 J (4) 6 JQ.36 y fn'kk esa dk;Zjr 2T ds pqEcdh; {ks=k esa – 2µCvkos'k ds ,d vkosf'kr d.k ij dk;Zjr pqEcdh;cy] tc d.k osx ( 2î + 3ĵ)× 10 6 ms –1 gSa] gS&(1) 8N, z - fn'kk esa(2) 8N, –z - fn'kk esa(3) 4N, z - fn'kk esa(4) 8N, y - fn'kk esaCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 8


Q.37 A conducting circular loop is placed in a uniformmagnetic field 0.04T with its plane perpendicularto the magnetic field. The radius of the loop startsshrinking at 2 mm/s. The induced emf in the loopwhen the radius is 2 cm is :(1) 1.6 πµV (2) 3.2 πµV(3) 4.8 πµV (4) 0.8 πµVQ.38 Power dissipated in an LCR series circuitconnected to an a.c. source of emf ε is :Q.37 ,d o`Ùkkdkj pkyd ywi 0.04T ds ,dlekupqEcdh; {ks=k eas blizdkj j[kk gS fd bldk rypqEcdh; {ks=k ds yEcor~ gSA ywi dh f=kT;k 2 mm/sdh nj ls fldqM+uk izkjEHk gksrh gSA tc f=kT;k2 cm gS] rks ywi esa izsfjr fo-ok-cy gS&(1) 1.6 πµV (2) 3.2 πµV(3) 4.8 πµV (4) 0.8 πµVQ.38 ε fo- ok- cy ds ac L=kksr ls tqM+s ,d LCR Js.khifjiFk esa 'kfDr O;; gS&(1)2ε R22 ⎛ 1 ⎞R + ⎜Lω − ⎟⎝ Cω⎠(1)2ε R22 ⎛ 1 ⎞R + ⎜Lω − ⎟⎝ Cω⎠(2)2ε R⎡2 ⎤2 ⎛ 1 ⎞⎢R+ ⎜Lω − ⎟ ⎥⎢⎣⎝ Cω⎠ ⎥⎦(2)2ε R⎡2 ⎤2 ⎛ 1 ⎞⎢R+ ⎜Lω − ⎟ ⎥⎢⎣⎝ Cω⎠ ⎥⎦⎡21(3)2 2 ⎛ ⎞ ⎤ε ⎢R+ ⎜Lω−⎟ ⎥ R⎢⎣⎝ Cω⎠ ⎥⎦(4)⎡22 2 ⎛ 1 ⎞⎤ε ⎢R+ ⎜Lω − ⎟ ⎥⎢ C⎣⎝ ω ⎠ ⎥⎦RQ.39 A rectangular, a square, a circular and anelliptical loop, all in the (x - y) plane, are movingout of a uniform magnetic field with a constantrvelocity, V = v ⋅ î . The magnetic field is directedalong the negative z-axis direction. The inducedemf, during the passage of these loops, come outof the field region, will not remain constant for :(1) any of the four loops(2) The rectangular, circular and elliptical loops(3) The circular and the elliptical loops(4) Only the elliptical loopQ.40 A p-n photodiode is fabricated from asemiconductor with a band gap of 2.5 eV. It candetect a signal of wavelength :(1) 496 Å (2) 6000 Å(3) 4000 nm (4) 6000 nm⎡21(3)2 2 ⎛ ⎞ ⎤ε ⎢R+ ⎜Lω − ⎟ ⎥ R⎢⎣⎝ Cω⎠ ⎥⎦(4)⎡22 2 ⎛ 1 ⎞⎤ε ⎢R+ ⎜Lω − ⎟ ⎥⎢ C⎣⎝ ω ⎠ ⎥⎦RQ.39 ,d vk;rkdkj] ,d oxkZdkj] ,d o`Ùkkdkj rFkk ,dnh?kZo`Ùkkdkj ywi lHkh (x - y) ry esa gS] ;s ,drle#i pqEcdh; {ks=k ls ckgj fu;r osx V = v ⋅ î lsxfr dj jgs gSA pqEcdh; {ks=k _.kkRed z-fn'kk dsvuqfn'k funsZf'kr gSA bu ywiksa ds xqtjdj {ks=k lsckgj vkus ds nkSjku izsfjr fo-ok-cy fdlds fy,fu;r ugha jgsxk&(1) pkjksa ywiksa esa ls fdlh ds Hkh fy,(2) vk;rkdkj] o`Ùkkdkj rFkk nh/kZo`Ùkkdkj ywiksa ds fy,(3) o`Ùkkdkj rFkk nh?kZo`Ùkkdkj ywiksa ds fy;s(4) dsoy nh?kZo`Ùkkdkj ywi ds fy,Q.40 ,d p-n QksVksMk;ksM 2.5 eV ds cS.M vUrjky okys,d v/kZpkyd ls cuk;k tkrk gSA ;g fdlrjaxnS/;Z dk ladsr lalqfpr dj ldrk gS&(1) 496 Å (2) 6000 Å(3) 4000 nm (4) 6000 nmCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 9


Q.41 The symbolic representation of four logic gatesare given below :(i)Q.41 pkj rdZ }kjksa dk lkadsfrd izLrqrhdj.k uhps fn;kx;k gS&(i)(ii)(ii)(iii)(iii)(iv)The logic symbols for OR, NOT and NAND gatesare respectively :(1) (i), (iii), (iv)(2) (iii), (iv), (ii)(3) (iv), (i), (iii)(4) (iv), (ii), (i)Q.42 A transistor is operated in common-emitterconfiguration at V C = 2V such that a change in thebase current from 100 µA to 200 µA produces achange in the collector current from5 mA to 10 mA. The current gain is :(1) 50 (2) 75 (3) 100 (4) 150Q.43 An ellipsoidal cavity is curved within a perfectconductor. A positive charge q is placed at thecentre of the cavity. The points A and B are onthe cavity surface as shown in figure. Then:(iv)OR, NOT rFkk NAND }kjksa ds fy, rdZ ladsrØe'k% gS&(1) (i), (iii), (iv)(2) (iii), (iv), (ii)(3) (iv), (i), (iii)(4) (iv), (ii), (i)Q.42 ,d VªkaftLVj V C = 2V ij mHk;fu"B mRltZdfoU;kl esa dk;Z djrk gS ftlls fd vk/kkj /kkjk dks100 µA ls 200 µA esas ifjofrZr djus ij laxzkgd/kkjk 5 mA ls 10 mA gks tkrh gSA /kkjk ykHk gS&(1) 50 (2) 75 (3) 100 (4) 150Q.43 ,d vkn'kZ pkyd ds Hkhrj ,d nh?kZ o`Ùkh; xqfgdkfLFkr gSA xqfgdk ds dsUnz ij ,d /kukRed vkos'k q j[kkgSA xqfgdk dh lrg ij nks fcUnqA vkSj B gSA rc&AqBAqB(1) electric field near A in the cavity = electricfield near B in the cavity(2) charge density at A = charge density at B(3) potential at A ≠ potential at B(4) total electric field flux throught he suface ofthe cavity is q/ε 0(1) xqfgdk esa fcUnq A ds lehi oS|qr {kS=k = xqfgdk esafcUnq B ds lehi oS|qr {ks=k(2) fcUnq A ij vkos'k ?kuRo = fcUnq B ij vkos'k?kuRo(3) fcUnq A ij foHko = fcUnq B ij foHko(4) xqfgdk dh lrg esa ls xqtjus okyk dqy oS|qryDl q/ε 0 gSCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 10


Q.44 nks ,d leku la/kkfj=k A o B ifjiFk fp=k esa iznf'kZrQ.44 Two identical capacitors A and B shown in the1 1(3) ampere (4) ampere1 1(3) ,fEi;j (4) ,fEi;j2 8 2 8given circuit are joined in series with a battery. IfgS] tks ,d cSVjh ds lkFk Js.khØe eas tqM+s gSA ;fna dielectric slab of dielectric constant K is slippedK ijkoS|qrkad dh ,d ijkoS|qr ifêdk la/kkfj=k Bbetween the plates of capacitor B and batteryremains connected, then the energy to capacitor Adh IysVksa ds e/; Mky nh tk;s rFkk cSVjh dks tqM+kwill:j[kk tk;s] rc la/kkfj=k A dh ÅtkZ&A+A+K –K –BB(1) decrease(1) ?kVsxh(2) increase(2) c


Q.48 By how many per cent will the power in a lampdecrease if the current drop by 1 per cent ?(1) 0.01 per cent (2) 1 per cent(3) 2 per cent (4) 4 per centQ.49 If 100 kWh of energy is consumed at 33V in acopper voltameter, what is the mass of copperliberated ? (Electrochemical equivalent of copperis 0.33 × 10 –6 kg/C)(1) 1 mg (2) 3.6 kg (3) 3.3 kg (4) 1 kgQ.50 A 200 W and a 100 W bulbs, both meant foroperation at 220 V are connected in series, to a220 V supply, the power consumed by themwill be:100W220V200W220VQ.48 ,d ySEi esa 'kfDr esa fdrus izfr'kr dh deh gksxh;fn /kkjk esa 1 izfr'kr dh fxjkoV vkrh gS ?(1) 0.01 izfr'kr (2) 1 izfr'kr(3) 2 izfr'kr (4) 4 izfr'krQ.49 ;fn ,d dkWij oksYVkehVj esa 100 kWh dh ÅtkZ33V ij O;; gksrh gS] rks dkWij dh nh xbZ ek=kkD;k gS \ (dkWij dk fo|qr jklk;fud rqY;kad0.33 × 10 –6 kg/C)(1) 1 mg (2) 3.6 kg (3) 3.3 kg (4) 1 kgQ.50 200 W rFkk 100 W ds cYc nksuksa 220 V ij dk;Zdjrs gS] bUgsa 220 V dh lIykbZ ls Js.khØe esa tksM+kx;k gSA muds }kjk O;; 'kfDr gksxh&100W220V200W220V220V(1) 33 W (2) 66 W(3) 100 W (4) 300 W~220V(1) 33 W (2) 66 W(3) 100 W (4) 300 W~CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 12


Q.51 How many electrons in S (At. No. = 16) haven + l = 3 ?(1) 8 (2) 16 (3) 4 (4) 2CHEMISTRYQ.51 S (ijek.kq Øekad = 16) esa n + l = 3 ;qDr fdrusbysDVªkWu gS ?(1) 8 (2) 16 (3) 4 (4) 2Q.52 The fifth electron in B (At. No. = 5) will occupy -(1) 2p x(2) 3s(3) 2p y(4) Any of 2p x , 2p y , 2p zQ.53 Which one of the following is true for a reactionwhich is spontaneous at all temperatures ?(1) ∆H = –ve, ∆S = +ve(2) ∆H = +ve, ∆S = –ve(3) ∆H = –ve, ∆S = –ve(4) ∆H = +ve, ∆S = +veQ.54 The initial concentration of A is 1.0 M after 1 min theconcentration of A decreases to 0.9982 M in a linearfashion. The rate of reaction in mol L –1 min –1 is -(1) 1.8 × 10 –3 (2) 3.6 × 10 –4(3) 4.2 × 10 –6 (4) 6.5 × 10 –5Q.55 The number of Faradays, required to deposit 1 moleof Cu from a solution of CuSO 4 will be -(1) 0.1 (2) 0.2(3) 1 (4) 2Q.56 Which of the following 0.10 M aqueous solutionswill have the lowest freezing point ?(1) C 6 H 12 O 6 (2) C 12 H 22 O 11(3) Al 2 (SO 4 ) 3 (4) KIQ.57 The solubility of PbCl 2 is -(1) K sp(2) 3K(3) 3 sp4K sp(4) 8 KspQ.58 A weak acid of dissociation constant 10 –5 is beingtitrated with aqueous NaOH solution. The pH at thepoint of one-third neutralization of the acid willbe -(1) 5 + log 2 – log 3 (2) 5 – log 2(3) 5 – log 3 (4) 5 – log 6Q.59 0.1 M HCl and 0.1 M H 2 SO 4 , each of volume 2 mlare mixed and the volume is made up to 6 ml byadding 2 ml of 0.01 N NaCl solution. The pH of theresulting mixture is -(1) 1.17 (2) 1.0(3) 0.3 (4) log 2 – log 3Q.52 B (ijek.kq Øekad = 5) esa ikpoka bysDVªkWu tk,xk -(1) 2p x(2) 3s(3) 2p y(4) 2p x , 2p y , 2p z esa ls fdlh esa HkhQ.53 ,d vfHkfØ;k ds fy, fuEu esa ls dkSulk lR; gS] tksfd lHkh rkiksa ij Lor% gksrh gS ?(1) ∆H = –ve, ∆S = +ve(2) ∆H = +ve, ∆S = –ve(3) ∆H = –ve, ∆S = –ve(4) ∆H = +ve, ∆S = +veQ.54 A dh izkjfEHkd lkUnzrk 1.0 M gS] 1 feuV ds i'pkrA dh lkUnzrk lefer :Ik ls ?kV dj 0.9982 M jgtkrh gS] mol L –1 min –1 esa vfHkfØ;k dk osx gksxk -(1) 1.8 × 10 –3 (2) 3.6 × 10 –4(3) 4.2 × 10 –6 (4) 6.5 × 10 –5Q.55 CuSO 4 ds ,d foy;u ds 1 eksy Cu ds fu{ksi.k dsfy, vko';d QSjkMs dh la[;k gS -(1) 0.1 (2) 0.2(3) 1 (4) 2Q.56 fuEu esa ls dkSuls 0.10 M tyh; foy;u dk fgekadlcls de gksxk ?(1) C 6 H 12 O 6 (2) C 12 H 22 O 11(3) Al 2 (SO 4 ) 3 (4) KIQ.57 PbCl 2 dh foys;rk gS -(1) K sp(2) 3K(3) 3 sp4K sp(4) 8 KspQ.58 fo;kstu fLFkjkad 10 –5 ds ,d nqcZy vEy dks tyh;NaOH foy;u ds lkFk vuqekfir fd;k tkrk gSA tcvEy dk ,d frgkbZ mnklhuhdj.k gks tkrk gS rksfoy;u dh pH gksxh -(1) 5 + log 2 – log 3 (2) 5 – log 2(3) 5 – log 3 (4) 5 – log 6Q.59 0.1 M HCl rFkk 0.1 M H 2 SO 4 izR;sd ds 2 mlvk;ru esa fefJr gS rFkk 0.01 N NaCl foy;u 2 mlfeykus ls vk;ru 6 ml gks tkrk gSaA ifj.kkeh feJ.kdh pH gS -(1) 1.17 (2) 1.0(3) 0.3 (4) log 2 – log 3CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 13


Q.60 Number of unit cells in 4 g of X (atomic mass = 40).Which crystallizes in bcc pattern is -(1) 0.1 N A (2) 2 × 0.1 N A0.1NA(3)2(4) 2 × N AQ.61 The vapour pressure of pure solvent is 0.8 mm ofHg at a particular temperature. On addition of anon-volatile solute 'A' the vapour pressure ofsolution becomes 0.6 mm of Hg. The mole fractionof component 'A' is -(1) 0.25 (2) 0.75(3) 0.5 (4) 0.35Q.62 A first order reaction is 50% complete in 69.3minutes. Time required for 90% completion forthis reactions is -(1) 100 minutes (2) 230 minutes(3) 2303 minutes (4) 125 minutesQ.63 0.32 g of metal gave on treatment with an acid 112mL of hydrogen at NTP. Calculate the equivalentweight of the metal -(1) 58 (2) 32(3) 11.2 (4) 24Q.64 The total number of atoms of all elements presentin 1 mole of ammonium dichromate is -(1) 19 (2) 6.023 × 10 23(3) 114.437 × 10 23 (4) 84.322 × 10 23Q.65 If CO 2 is allowed to escape from this reaction atequilibrium (reaction) :CO 2 + H 2 O H + + HCO 3–(1) pH will decrease(2) pH will remain constant(3) pH will increase(4) forward reaction will be favouredQ.66 Equal volumes of 0.1 M AgNO 3 and 0.2 M NaCl ismixed. The concentration of NO –3 in the mixedsolution will be -(1) 0.1 M (2) 0.05 M(3) 0.2 M (4) 0.15 MQ.67 Which of the following has minimum gold number -(1) starch(2) sodium oleate(3) gum arabic(4) gelatinQ.60 X (ijek.kq nzO;eku = 40) ds 4 g esa bdkbZ dksf"Bdkvksadh la[;k] tks fd dk; dsfUnzr ?ku es fØLVyhd`rgksrk gS -(1) 0.1 N A (2) 2 × 0.1 N A0.1NA(3)(4) 2 × N A2Q.61 ,d fuf'pr rki ij 'kq) foyk;d dk ok"i nkc 0.8mm Hg gSA ,d vok"i'khy foys; 'A' dks feykus ijfoy;u dk ok"i nkc 0.6 mm Hg gks tkrk gSAvo;o 'A' dh eksy fHkUu gS -(1) 0.25 (2) 0.75(3) 0.5 (4) 0.35Q.62 ,d izFke dksfV vfHkfØ;k 69.3 feuV esa 50% iw.kZgksrh gSA bl vfHkfØ;k ds 90% iw.kZ gksus ds fy,vko';d le; gS -(1) 100 feuV (2) 230 feuV(3) 2303 feuV (4) 125 feuVQ.63 NTP ij gkbMªkstu ds 112 mL, ,d vEy ds lkFkmipkfjr djus ij 0.32 g /kkrq nsrs gSa /kkrq dk rqY;kadhHkkj Kkr dhft, -(1) 58 (2) 32(3) 11.2 (4) 24Q.64 veksfu;e MkbØksesV ds 1 eksy esa mifLFkr lHkh rRoksds ijek.kqvksa dh dqy la[;k gS -(1) 19 (2) 6.023 × 10 23(3) 114.437 × 10 23 (4) 84.322 × 10 23Q.65 ;fn fuEu lkE; ij CO 2 dks fu"dkflr dj fn;ktk;s rks CO 2 + H 2 O H + + HCO 3 – -(1) pH ?kVsxk(2) pH fLFkj jgsxk(3) pH c


Q.68 tyh; ek/;e esa lksfM;e Fkk;kslYQsV dh I ds lkFkQ.68 In the reaction of sodium thiosulphate with I 2 in(4) ionic interaction between [BH 4 ] + and [BH 2 ] – (4) [BH 4 ] + rFkk [BH 2 ] – ds e/; vk;fud vUr%fØ;kaqueous medium the equivalent weight of sodiumthiosulphate is equal to -(1) molar mass of sodium thiosulphate(2) the average of molar masses of Na 2 S 2 O 3 and I 2(3) half the molar mass of sodium thiosulphate(4) molar mass of sodium thiosulphate × 22vfHkfØ;k esa] lksfM;e Fkk;kslYQsV dk rqY;kadh HkkjfuEu ds cjkcj gksrk gS -(1) lksfM;e Fkk;kslYQsV ds eksyj nzO;eku ds(2) Na 2 S 2 O 3 rFkk I 2 ds eksyj nzO;ekuks ds vkSlr ds(3) lksfM;e Fkk;kslYQsV ds eksyj nzO;eku dk vk/kk(4) lksfM;e Fkk;kslYQsV ds eksyj nzO;eku × 2Q.69 Which of the following compounds does not contain Q.69 fuEu esa ls dkSuls ;kSfxd esa fØLVyhd`r ty ughwater of crystallization ?gksrk gS ?(1) CaCl 2 (2) BeCl 2(1) CaCl 2 (2) BeCl 2(3) MgCl 2 (4) NaCl(3) MgCl 2 (4) NaClQ.70 Calcium carbide is produced by heating -Q.70 fuEu dks xeZ djus ij dSfY'k;e dkckZbM curk gS -(1) CaO and CH 4 at 200°C(1) 200°C ij CaO rFkk CH 4(2) CaO and C at 2000°C(3) Ca and C at 1000°C(4) CaNCN and C at 800°C(2) 2000°C ij CaO rFkk C(3) 1000°C ij Ca rFkk C(4) 800°C ij CaNCN rFkk CQ.71 Anhydrous AlCl 3 is prepared by the reactionbetween -(1) alumina and dilute HCl(2) heated aluminium and dry Cl 2 (g)(3) aluminium and dilute HCl solution(4) AllQ.71 futZy AlCl 3 fuEu ds e/; vfHkfØ;k }kjk fufeZrgksrk gS -(1) ,Y;wfeuk rFkk ruq HCl(2) xeZ ,Y;wfefu;e rFkk 'kq"d Cl 2 (g)(3) ,Y;wfefu;e rFkk ruq HCl foy;u(4) lHkhQ.72 Which of the following octahedral complex ions is Q.72 fuEu esa ls dkSulk v"VQydh; ladqy vk;udiamagnetic ?izfrpqEcdh; gksrk gS ?(1) [Cr(CO) 6 ] (2) [Mn(CN) 6 ] –2(1) [Cr(CO) 6 ] (2) [Mn(CN) 6 ] –2(3) [Ni(NH 3 ) 6 ] 2+ (4) [CoF 6 ] 3–(3) [Ni(NH 3 ) 6 ] 2+ (4) [CoF 6 ] 3–Q.73 Intra-molecular hydrogen bonding is found in - Q.73 fuEu esa vUr% v.kqd gkbMªkstu ca/k ik;k tkrk gS -(1) hydrofluoric acid (2) water(1) gkbMªksyksfjd vEy (2) ty(3) methanol (4) o-nitrophenol(3) esFksukWy (4) o-ukbVªksfQuksyQ.74 The type of isomerism present in Q.74 [Co(NH 3 ) 3 (ONO)Cl 2 ] rFkk [Co(NH 3 ) 3 (NO 2 )Cl 2 ] esa[Co(NH 3 ) 3 (ONO)Cl 2 ] and [Co(NH 3 ) 3 (NO 2 )Cl 2 ] is -(1) hydrate isomerism(2) ionization isomerism(3) linkage isomerism(4) geometrical isomerismmifLFkr leko;ork dk izdkj gS-(1) gkbMªsV leko;ork(2) vk;uu leko;ork(3) ca/ku leko;ork(4) T;kferh; leko;orkQ.75 The molecular structure of B 2 H 6 consists of -(1) four B–H terminal bonds and two B–H–BQ.75 B 2 H 6 dh vkf.od lajpuk esa mifLFkr gS -(1) pkj B–H vUrLFk ca/k rFkk nks B–H–B lsrq ca/kbridge bonds(2) N% B–H vUrLFk ca/k rFkk ,d B–B ca/k(2) six B–H terminal bonds and one B–B bond(3) four B–H terminal bonds, two B–H–B bridge(3) pkj B–H vUrLFk ca/k] nks B–H–B lsrq ca/k rFkkbonds and a B–B bond,d B–B ca/kCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 15


Q.76 ftad ukbVªsV dk rkih; fo?kVu nsrk gS -Q.76 Thermal decomposition of zinc nitrate gives -(4) [Co(H 2 O) 4 (en)] 3+ (4) [Co(H 2 O) 4 (en)] 3+(1) Zn (2) ZnO(1) Zn (2) ZnO(3) Zn(NO 2 ) 2 (4) NO(3) Zn(NO 2 ) 2 (4) NOQ.77 Which of the following is a non-directional bond ?(1) Metallic bond(2) Covalent bond(3) Coordinate bone(4) All are directionalQ.77 fuEu esa ls dkSulk ,d vfn'kkRed ca/k gS ?(1) /kkfRod ca/k(2) milgla;ksth ca/k(3) lgla;kstd ca/k(4) lHkh fn'kkRed gSQ.782–The number of antibonding electron pairs in O 2molecular ion on the basis of moleculare orbitaltheory is (Atomic number of O is 8) -Q.782–v.kq d{kd fl)kUr ds vk/kkj ij O 2 vkf.od vk;uesa vcaf/kr bysDVªkWu ;qXeks dh la[;k gS (O dk ijek.kqØekad 8) -(1) 3 (2) 2(1) 3 (2) 2(3) 5 (4) 4(3) 5 (4) 4Q.79 The increasing order of the crystal field splittingpower of some common ligand is -(1) H 2 O < OH – < Cl – < F – < CN –Q.79 dqN lkekU; fyxS.M dh fØLVy {ks=k foikVu {kerkdk c


Q.84 Which method is not correct for refining of crudemetals ?(1) Liquation : Tin(2) Zone refining : Silicon(3) Mond process : Aluminium(4) Electrolytic refining : blister copperQ.85 All the carbon-carbon bond lengths are equal in -(1) 1-butene (2) benzene(3) 2-butene (4) propyneQ.86 Which of the following compounds cannot formintermolecular hydrogen bonds among its ownmolecules but can do so with donor compounds ?(1) CH 3 CH 2 OH (2) CH 3 OCH 3(3) CH 3 CH 2 NH 2 (4) CH 3 COOHQ.87 Which of the following shows the correct order ofdecreasing acidity ?(1) PhCO 2 H > PhSO 3 H > PhCH 2 OH > PhOH(2) PhSO 3 H > PhOH > PhCO 2 H > PhCH 2 OH(3) PhCO 2 H > PhOH > PhCH 2 OH > PhSO 3 H(4) PhSO 3 H > PhCO 2 H > PhOH > PhCH 2 OHQ.88 Give the correct order of increasing basicity of thefollowing compoundsMe Me Me MeNH 2 NH 2 NNMe MeQ.84 v'kq) /kkrqvksa ds 'kks/ku ds fy, dkSulh fof/k lgh ughagS ?(1) nzO;hZdj.k : fVu(2) {ks=k ifj"dj.k : flfydkWu(3) eks.M izØe : ,Y;wfefu;e(4) oS|qqrvi?kV; 'kks/ku : QQksysnkj rk¡ckQ.85 fuEu fdlesa lHkh dkcZu –dkcZu ca/k yEckbZ;k¡ cjkcjgksrh gS -(1) 1-C;wVhu (2) csathu(3) 2-C;wVhu (4) izksikbZuQ.86 fuEu esa ls dkSuls ;kSfxd vius v.kqvksa ds e/;vUrjkf.od gkbMªkstu ca/k ugha cuk ldrs ysfdu nkrk;kSfxdksa ds lkFk ,slk dj ldrs gS \(1) CH 3 CH 2 OH (2) CH 3 OCH 3(3) CH 3 CH 2 NH 2 (4) CH 3 COOHQ.87 fuEu esa ls dkSulk iznf'kZr Øe vEyh;rk dk lgh?kVrk Øe gS \(1) PhCO 2 H > PhSO 3 H > PhCH 2 OH > PhOH(2) PhSO 3 H > PhOH > PhCO 2 H > PhCH 2 OH(3) PhCO 2 H > PhOH > PhCH 2 OH > PhSO 3 H(4) PhSO 3 H > PhCO 2 H > PhOH > PhCH 2 OHQ.88 fn, x;s fuEu ;kSfxdksa dh {kkjh;rk dk lgh c


Q.91 An alkyl bromide reacts with sodium with ether toform 4, 5-diethyloctane. The alkyl bromide is -(1) CH 3 (CH 2 ) 2 CH 2 Br(2) CH 3 (CH 2 ) 4 CH 2 Br(3) CH 3 (CH 2 ) 3 CHBrCH 3(4) CH 3 (CH 2 ) 2 CHBrCH 2 CH 3Q.92 Consider the following reaction -+ HCl ?The major product of the reaction is -(1) Cl(2)(3)Cl(4) ClClQ.91 ,d ,fYdy czksekbM] lksfM;e rFkk bZFkj ds lkFk fØ;k dj4, 5-Mkb,fFky vkWDVsu cukrk gSA ,fYdy czksekbM gS -(1) CH 3 (CH 2 ) 2 CH 2 Br(2) CH 3 (CH 2 ) 4 CH 2 Br(3) CH 3 (CH 2 ) 3 CHBrCH 3(4) CH 3 (CH 2 ) 2 CHBrCH 2 CH 3Q.92 fuEu vfHkfØ;k Ikj fopkj dhft, &+ HCl ?vfHkfØ;k dk eq[; mRikn gS -(1) Cl(2)(3)Cl(4) ClClQ.93 The monomer unit of the given polymer is -Q.93 fn;s x;s cgqyd dh ,dyd bdkbZ gS -CH 3(1)HC=CH 2CH 3(3) CCH 2CHnCH 3(2) C=CCH 3CH 3CH 2 (4)HC=CHCH 3HQ.94 The major product formed in the reaction is -CH 3OHCH=CH 2CH 3(1)HC=CH 2CH 3nCH 3(2) C=CCH 3CH 3CH 3 H(3) CCH 2 CH CH 2 (4)HC=CCH=CH 2Q.94 fuEu vfHkfØ;k esa fufeZr eq[; mRikn gS &CH 3OHHH 2 SO 4 ?OHCH 3H 2 SO 4 ?OHCH 3(1)CH 3(2)CH 3CH 3C–CH 3O(1)CH 3(2)CH 3CH 3C–CH 3O(3)CH 3CH 3 (4)OCH 2CH 2(3)CH 3CH 3 (4)OCH 2CH 2CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 18


Q.95 1-Bromobutane is treated with pottasium ethoxidein ethanol. The major product obtained is -(1) 1-butene(2) 1-ethoxybutane(3) cis-2-butene(4) trans-2-buteneQ.96 Carboxylic acids, (RCOOH) furnish H + ions to waterforming H 3 O + and carboxylate ions (RCOO – ).Themajor reason for this acidic behaviour is that -(1) the carboxylate ion is stabilized by solvationwith H 2 O(2) the carboxylic acid is stabilized by resonance(3) the carboxylate ion is stabilized by resonance(4) the carboxylate ion is more stasbilized than thecarboxylic acidQ.97 Consider the following sequence of reactions,OCH 3 CH 3+ HCN ——→(A) ⎯H 2⎯⎯ O →(B)( 1eq)CHOThe end product (B) is -HO COOHCH 3 CH 3(1)CHOCOOHCH 3 CH 3(2)CHOOCH 3 CH 3(3)CHOHCOOHHO COOH(4) CH 3 CH 3CHOHCOOHQ.95 1-czkseksC;wVsu] ,FksukWy esa ikSVsf'k;e ,FkkWDlkbM ds lkFkmipkfjr fd;k tkrk gS] izkIr eq[; mRikn gS -(1) 1-C;wVhu(2) 1-bZFkkWDlh C;wVsu(3) fll-2-C;wVhu(4) Vªkal-2-C;wVhuQ.96 dkcksZfDlfyd vEy (RCOOH), H + vkW;u ty dks nsdjH 3 O + rFkk dkcksZfDlysV vk;u (RCOO – ) cukrk gSA blvEyh; O;ogkj ds fy, eq[; dkj.k ;g gksrk gS fd -(1) dkcksZfDlysV vkW;u ty }kjk foys; gksdj LFkk;hgks tkrk gS(2) dkcksZfDlfyd vEy vuqukn }kjk LFkk;h gksrk gSA(3) dkcksZfDlysV vkW;u vuqukn }kjk LFkk;h gksrk gS(4) dkcksZfDlysV vkW;u] dkcksZfDlfyd vEy ls vf/kdLFkk;h gksrk gSAQ.97 vfHkfØ;kvksa ds fuEu Øe Ikj fopkj dhft, ,OCH 3 CH 3CHO+ HCN ——→(A) ⎯H 2⎯→ ⎯O (B)( 1rqY;kad)vfUre mRikn (B) gS -(1)HO COOHCH 3 CH 3CHOCOOHCH 3 CH 3(2)CHOOCH 3 CH 3(3)HOCHOHCOOHCOOH(4) CH 3 CH 3CHOHCOOHCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 19


Q.98 Which of the following compounds does not reactwith benzoyl chloride -(1)OH(2)OH(3)N(4)NQ.99 Which does not show connizzaro reaction ?(1) CH 3 C H (2) CHOO(3) H C C D (4) H C C HO OO OQ.100 Rubber is heated with sulphur for its modification. Theprocess is known as -(1) sulphonation (2) vulcanization(3) sensitization (4) NoneQ.98 fuEu esa ls dkSulk ;kSfxd csUtkW;y DyksjkbM ds lkFkfØ;k ugha djrk gS -OHOH(1)(2)(3)N(4)Q.99 dkSu dSfutkjks vfHkfØ;k ugh n'kkZrk gS ?(1) CH 3 C HO(3) H C COODN(2) CHO(4) H C CQ.100 jcj dks lYQj ds lkFk xeZ djds bldk :ikUrj.kfd;k tkrk gSa bl fØ;k dks dgrs gS -(1) lYQksuhdj.k (2) oYduhdj.k(3) laosnhdj.k (4) dksbZ ughaOOHCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 20


BIOLOGYQ.101 Which of the following is a motile structure(1) Zoospore of albugo(2) Male gamete of cycas(3) Microspore of pinus(4) (1) & (2) bothQ.102 Variation in the length of anther filament within aflower is present in(1) Chinarose (2) Mustard(3) Salvia (4) 2 & 3 bothQ.103 Which is not correct for the inflorescence shown infigureQ.101 fuEu esa ls dkSulh ,d xfr'khy lajpuk gS(1) ,Ycqxks dk py chtk.kq(2) lkbdl dk uj ;qXed(3) ikbul dk y?kqchtk.kq(4) (1) o (2) nksuksaQ.102 ,d gh iq"i esa iqrarq dh yEckbZ esa fofHkUurk ikbZtkrh gS(1) xqM+gy esa (2) ljlks esa(3) lkfYo;k esa (4) nksuksa 2 o 3Q.103 fp=k esa n'kkZ;s x, iq"iØe ds fy, dkSulk lgh ughagS(1) Length of peduncle is unlimited(2) Acropetal order of flower(3) Flower is present at tip(4) Both (2) & (3)Q.104 Which of the following is mismatchedPlantUse(1) Tobacco Fumigatory(2) Chilli Vegetable(3) Aloe Cosmatics(4) Asparagus VegetableQ.105 Dicot stem can not be differentiated from monocotstem on the basis of(1) Types of vascular bundle(2) Arrangement of vascular bundle(3) Conjunctive tissue and no. of vascular bundle(4) 1 & 2 both(1) iq"ikoyh oÙr dh yEckbZ vlhfer(2) iq"Ik dk vxzkfHklkjh foU;kl(3) 'kh"kZ ij iq"Ik mifLFkr(4) nksuksa (2) o (3)Q.104 fuEu esa ls dkSulk csesy gSiknimi;ksx(1) rEckdw /kqed(2) fepZ lCth(3) XokjikBk lkSUn;Z izlk/ku(4) 'krkoj lCthQ.105 fdl ds vk/kkj ij f}chti=kh LrEHk dks ,dchti=khLrEHk ls foHksfnr ugha fd;k tk ldrk(1) laogu iwy ds izdkj(2) laogu iwy dk foU;kl(3) la;ksth Ård ,oa laogu iwy dh la[;k(4) nksuksa 1 o 2CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 21


Q.106 During the formation of the primary plant body,specific regions of apical meristem produce(1) Dermal tissue(2) Ground tissue(3) Vascular tissue(4) All of the aboveQ.107 Apical bud is not present in(1) Main stem of Pinus(2) Long shoot of Pinus(3) Dwarf shoot of Pinus(4) All of the aboveQ.108 It is said that elemental composition of livingorganisms and that of inanimate objects (likeearth's crust) are similar in the sence that all themajor elements are present in both. Then whatwould be the difference between these twogroups ? Choose a correct answer from amongthe following(1) Living organisms have more gold in themthan inanimate objects(2) Living organisms have more water in theirbody than inanimate objects.(3) Living organisms have more carbon. oxygenand hydrogen per unit mass than inanimateobjects.(4) Living organisms have more calcium in themthan inanimate objects.Q.109 In the hexaploid wheat, the haploid(n) andbasic(x) numbers of chromosomes are:(1) n = 21 and x = 7(2) n = 7 and x = 21(3) n = 21 and x = 21(4) n = 21 and x = 14Q.110 Lysozyme that is present in perspiration, salivaand tears, destroys:(1) Most virus – infected cells(2) Certain fungi(3) Certain types of bacteria(4) All virusesQ.106 izkFkfed ikni 'kjhj fuekZ.k ds nkSjku 'kh"kZLFkfoHkT;ksÙkd ds fof'k"B {ks=k ls mRiUUk gksrk gS(1) Roph; Ård(2) Hkj.k Ård(3) loagu Ård(4) mijksDr lHkhQ.107 'kh"kZLFk dfydk mifLFkr ugha gksrh gS(1) ikbul ds eq[; rusa esa(2) ikbul ds nh?kZ izjksg esa(3) ikbul ds ckSus izjksg esa(4) mijksDr lHkhQ.108 ;g ekuk tkrk gS fd thfor thoksa dk RkRoh;laxBu o blds fuftZo inkFkZ ¼i`Foh ds dksj dsleku½ {kerk esa leku gksrs gS] nksuksa esa lHkh nh?kZrRo mifLFkr gksrs gSA bu nksuksa leqgksa ds e/; D;kvUrj gksxk] fuEu esa ls lgh mÙkj dk p;u dhft,A(1) fuftZo inkFkksZ dh vis{kk] thfor thoksa esa vf/kdlksuk gksrk gSA(2) fuftZo inkFkksZ dh vis{kk] thfor thoksa ds 'kjhjesa vf/kd ty gksrk gSA(3) fuftZo inkFkksZ dh vis{kk] thfor thoksa esa dkcZu]vkDlhtu o gkbMªkstu izfr bZdkbZ nzO;ekuvf/kd gksrs gSA(4) fuftZo inkFkksZ dh vis{kk] thfor thoksa esadsfY'k;e vf/kd gksrk gSAQ.109 "kV~xqf.kr xsgw¡ eas xq.klw=kksa dh vxqf.kr (n) rFkk ewyHkwr(x) la[;k,¡ D;k gSa \(1) n = 21 rFkk x = 7(2) n = 7 rFkk x = 21(3) n = 21 rFkk x = 21(4) n = 21 rFkk x = 14Q.110 gekjs ilhus] ykj rFkk vkalqvksa eas ik;k tkus okykykblkstkbe fdldks u"V djrk gS \(1) vf/kdka'k fo"kk.kq – laØfer dksf'kdkvksa dk(2) dqN [kkl dodksa dk(3) dqN izdkj ds thok.kqvksa dk(4) lHkh fo"k.kqvksa dkCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 22


Q.111 The population of an insect species shows anexplosive increase in numbers during rainyseason followed by its disappearance at the end ofthe season. What does this show ?(1) The population of its predators increasesenormously(2) S-shaped or sigmoid growth of this insect(3) The food plants mature and die at the end ofthe rainy season(4) Its population growth curve is of J-typeQ.112 In pea plants, yellow seeds are dominant to green.If a heterozygous yellow seeded plant is crossedwith a green seeded plant, what ratio of yellowand green seeded plants would you expect in F 1generation ?(1) 3 : 1 (2) 50 : 50(3) 9 : 1 (4) 1 : 3Q.113 Differentiation of organs and tissues in adeveloping organism, is associated with-(1) Deletion of genes(2) Developmental mutations(3) Differential expression of genes(4) Lethal mutationsQ.114 In maize, hybrid vigour is exploited by:-(1) Inducing mutations(2) Bombarding the seeds with DNA(3) Crossing of two inbred parental lines(4) Harvesting seeds from the most productiveplantsQ.115 Two genes R and Y are located very close on thechromosomal linkage map of maize plant. WhenRRYY and rryy genotypes are hybridized, the F 2segregation will show:-(1) Higher number of the parental types(2) Higher number of the recombinant types(3) Segregation in the expected 9 : 3 : 3 : 1 ratio(4) Segregation in 3 : 1 ratioQ.116 During transcription, RNA polymeraseholoenzyme binds to a gene promoter andassumes a saddle-like structure. What is it's DNAbindingsequence ?(1) TATA (2) TTAA(3) AATT (4) CACCQ.111 ,d dhV tkfr dh lef"V dh la[;k o"kkZ _rqds nkSjku foLQksVd :Ik ls c


Q.117 The formula for exponential population growth is-(1) dt/dN = rN (2) dN/rN = dt(3) rN/dN = dt (4) dN/dt = rNQ.118 Which antibiotic inhibits interaction betweentRNA and mRNA during bacterial proteinsynthesis ?(1) Erythromycin (2) Neomycin(3) Streptomycin (4) TetracyclineQ.119 In which mode of inheritance do you expect morematernal influence among the offspring ?(1) Autosomal (2) Cytoplasmic(3) Y-linked (4) X-linkedQ.120 Phenotype of an organism is the result of-(1) Mutations and linkages(2) Cytoplasmic effects and nutrition(3) Environmental changes and sexual dimorphism(4) Genotype and environment interactionsQ.121 How many different kinds of gametes will beproduced by a plant having the genotypeDDAABbCC ?(1) Three (2) Four(3) Nine (4) TwoQ.122 Amino acid sequence, in protein synthesis isdecided by the sequence of-(1) tRNA (2) mRNA(3) cDNA (4) rRNAQ.123 In Mendel's experiments with garden pea, roundseed shape (RR) was dominant over wrinkledseeds (rr), yellow cotyledon (YY) was dominantover green cotyledon (yy). What are the expectedphenotypes in the F 2 generation of the crossRRYY × rryy ?(1) Only round seeds with green cotyledons(2) Only wrinkled seeds with yellow cotyledons(3) Only wrinkled seeds with green cotyledons(4) Round seeds with yellow cotyledons, andwrinkled seeds with yellow cotyledonsQ.117 pj?kkrkadh tula[;k o`f) dk lw=k D;k gS \(1) dt/dN=rN (2) dN/rN=dt(3) rN/dN=dt (4) dN/dt=rNQ.118 og dkSulk izfrtSfod gS tks thok.kq izksVhu la'Yks"k.kds nkSjku tRNA rFkk mRNA ds chp ijLij fØ;kdk laneu djrk gS \(1) ,fjFkzksekblhu (2) uhvksekblhu(3) LVªsIVksekblhu (4) VsVªklkbDyhuQ.119 fdl oa'kkxfr fof/k eas larkuksa eas vf/kd ekr`d izHkkoik;k tkrk gS \(1) vfyaxlw=kh (2) dksf'kdknzO;h(3) Y-lgyXurk (4) X-lgyXurkQ.120 fdlh tho dk y{k.kiz:Ik fdldk ifj.kke gksrk gS \(1) mRifjorZu rFkk lgyXurk,¡(2) dksf'kdknzO;h; izHkko rFkk iks"k.k(3) Ik;kZoj.kh; ifjorZu rFkk ySafxd f}:irk(4) thuiz:Ik rFkk Ik;kZoj.k dh ijLij fØ;k,¡Q.121 ,d ikS/ks ls ftldk thuizk:Ik DDAABbCC gSfdrus fHkUu izdkj ls ;qXed cusaxs -(1) rhu (2) pkj(3) ukS (4) nksQ.122 izksVhu la'ys"ks.k esa ,sehuks vEy vuqØe fdldsvuqØe }kjk fuf'pr gksrk gS \(1) tRNA (2) mRNA(3) cDNA (4) rRNAQ.123 m|ku] eVj ij fd;s x;s esaMy ds iz;ksxkas esa xksycht vkd`fr (RR) >qjhZnkj chtksa (rr) ij rFkk ihykchti=k (YY) gjs chti=k (yy) ij izHkkoh FksARRYY × rryy ladj.k ls F 2 ih


Q.124 Cri-du-chat syndrome in humans is caused bythe-(1) Fertilization of an XX egg by a normalY-bearing sperm(2) Loss of half of the short arm of chromosome 5(3) Loss of half of the long arm of chromosome 5(4) Trisomy of 21 st chromosomeQ.125 Many elements are found in living organisms eitherfree or in the form of compounds. One of thefollowing is not, found in living organisms(1) Silicon (2) Magnesium(3) Iron (4) SodiumQ.124 ekuoksa esa ØkbZ-Mq-pSV flaMªkse fdlds dkj.k iSnk gksrk gS\(1) XX v.Ms dk lkekU; Y-/kkjd 'kqØk.kq }kjk fu"kspu(2) xq.klw=k 5 dh Yk?kq Hkqtk ds vk/ks Hkkx dh gkfu(3) xq.klw=k 5 dh nh?kZ Hkqtk ds vk/ks Hkkx dh gkfu(4) 21osa xq.klw=k dh f=klw=krk (,dkf/klw=krk)Q.125 vusd rRo thfor thoksa eas ;k rks eqDr vFkok;kSfxd dh voLFkk esa ik;sa tkrs gS fuEu esa ls ,dthfor thoksa esa ugha ik;k tkrk gS(1) flfydkWu (2) esfXuf'k;e(3) vk;ju (4) lksfM;eQ.126 Many organic substances are negatively chargese.g., acetic acid, while others are positivelycharged e.g., ammonium ion. An aminoacidunder certain conditions would have bothpositive and negative charges simultaneously inthe same molecule. Such a form of aminoacid iscalled(1) Positively charged form(2) Negatively charged form(3) Neutral form(4) Zwitterionic formQ.127 Sickle cell anemia has not been eliminated fromthe African population because-(1) It is controlled by recessive genes(2) It is not a fatal disease(3) It provides immunity against malaria(4) It is controlled by dominant genesQ.128 G-6-P dehydrogenase deficiency is associatedwith haemolysis of -(1) Leucocytes (2) Lymphocytes(3) Platelets (4) RBCsQ.129 In order to find out the different types of gametesproduced by a pea plants having the genotypeAaBb, it should be crossed to a plant with thegenotype -(1) AaBb (2) aabb(3) AABB (4) aaBBQ.126 vf/kdÙkj tSfod inkFkZ _.kkRed vkosf'kr gksrs gSmnkgj.k ,flfVd vEy] tcfd vU; /kukRedvkosf'kr gksrs gS mnk- veksfu;e vk;uA leku v.kqesa fuf'pr voLFkkvksa ds vUrZxr vehuks vEy esa/kukRed o _.kkRed vkos'k lkFk&lkFk gksrs gSAvehuks vEy dh ,slh voLFkk dgykrh gSA(1) /kukRed vkosf'kr voLFkk(2) _.kkRed vkosf'kr voLFkk(3) mnkflu voLFkk(4) TohVj vk;fud voLFkkQ.127 nk=k dksf'kdk vjDrrk vÝhdh vkcknh esa ls blfy;sugha lekIr gks ikbZ] D;ksafd -(1) ;g vizHkkoh thuksa }kjk fu;af=kr gksrh gSA(2) ;g ?kkrd jksx ugha gSA(3) blds }kjk eysfj;k ls izfrj{kk izkIr gksrh gSA(4) ;g izHkkoh thuksa }kjk fu;af=kr gksrh gSAQ.128 G-6-P MhgkbMªksftust vYirk dk laca/k fdlds:f/kj y;u ls gS -(1) 'osrk.kq (2) ylhdk.kq(3) ifV~Vdk.kq (4) yky :f/kj df.kdk,aQ.129 eVj ds ,d ikS/ks dk thu iz:Ik AaBb gSA mlesafdl çdkj ds fHkUu ;qXed cusaxs] ;g irk yxkus dsfy, mldk fdl çdkj ds thu ç:i okys ikS/ks dslkFk çladj.k fd;k tkuk pkfg, &(1) AaBb (2) aabb(3) AABB (4) aaBBCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 25


Q.130 Carbohydrates, the most abundant biomoleculeson earth, are produced by -(1) Some bacteria, algae and green plant cells(2) All bacteria, fungi and algae(3) Fungi, algae and green plants cells(4) Viruses, fungi and bacteriaQ.131 A homopolymer has only one type of buildingblock called monomer repeated 'n' number oftimes. A heteropolymer has more than one typeof monomer. Proteins are heteropolymers madeof aminoacids. While a nucleic acid like DNA orRNA is made of only 4 types of nucleotidemonomers, proteins are made of -(1) 20 types of monomers(2) 40 types of monomers(3) 3 types of monomers(4) Only one type of monomersQ.132 A pure protein should normally have(1) Two ends (2) One end(3) Three ends (4) No endsQ.133 AIDS is caused by HIV that principally infects(1) CD-8 cells(2) T4 lymphocytes(3) Cytotoxic T cells(4) All lymphocytesQ.134 In taxonomic hierarchy as we go higher fromspecies to kingdom which type of characteristicsgoes on decreasing ?(1) Generalized characteristics(2) Common characteristics(3) Morphological characteristic(4) Taxonomic characteristicsQ.135 Which is incorrect match(1) Bacteria – Diverse metabolism(2) Mycoplasma – Can servive withoutoxygen(3) Cyanobacteria – Primitive type DNAtransfer(4) Archebacteria – Symbiotic ruminantQ.130 i`Foh ij ik, tkus okys lcls izpqj tSo-v.kqdkcksZgkbMªsV~l fduds }kjk cuk, tkrs gS -(1) dqN thok.kq] 'kSoky rFkk gjh ikni dksf'kdk,a(2) lHkh thok.kq ] dod rFkk 'kSoky(3) dod 'kSoky rFkk gjh ikni dksf'kdk,a(4) fo"kk.kq] dod rFkk thok.kqQ.131 ,d lecgqyd esa ,d izdkj ds lajpukRed [k.Mgksrs gS tks fd dgh ckj iqujko`Ùkhr ,dyd 'n'dgykrs gSA ,d fo"ke cgqyd esa ,d ls vf/kdizdkj ds ,dyd gksrs gS izksVhu fo"kecgqyd gksrhgS tks fd vfeuks vEyks ls fufeZr gksrh gS] tcfdU;wfDy;d vEy tSls DNA vFkok RNA dsoy 4izdkj ds U;wfDy;ksVkbM ,dydksa ls fufeZr gksrh gSizksVhu fufeZr gksrh gS -(1) 20 izdkj ds ,dydksa ls(2) 40 izdkj ds ,dydksa ls(3) 3 izdkj ds ,dydksa ls(4) dsoy 1 izdkj ds ,dydksa lsQ.132 ,d 'kq) izksfVu esa lkekU;r% gksrs gS(1) nks fljs (2) ,d fljk(3) rhu fljs (4) dksbZ fljk ughaQ.133 AIDS dk gksuk HIV ds }kjk gksrk gS tks eq[;r%laØe.k djrk gS % &(1) CD-8 dksf'kdkvksa dk(2) T4 ylhdk.kqvksa dk(3) dksf'kdkfo"kh T dksf'kdkvksa dk(4) lHkh ylhdk.kqvksa dkQ.134 ofxZdh inkuqØe esa ge tSls&tSls tkfr ls txrdh vksj Åij tkrs gS oSls gh fdl izdkj ds xq.kksaesa deh vkrh gS ?(1) lkekU; xq.kks esa(2) leku xq.kksa esa(3) vkdkfjdh; xq.kksa esa(4) ofxZdh; xq.kksa esaQ.135 dkSulk xyr lqesfyr gS(1) thok.kq – mikip; fofo/krk(2) ekbdksIykTek – vkDlhtu ds fcukthfor jg ldrs gS(3) lk;uksthok.kq – DNA dk iqjkruLFkkukUrj.k(4) vkdsZthok.kq – lgthoh :ehusUVCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 26


Q.136 Mostly marine and photosynthetic organismappear blue or red coloured depanding onpigments, release toxins which cause death ofmarine animals.(1) Rhodophyceae (2) Cynophyceae(3) Pyrrophyceae (4) ChrysophyceaeQ.137 Choose the correct match(1) Rhizopus – Aseptate, Coenocytic,Conidia(2) Sacharomyces – Saprophytic, Branched,Septate, Zoospore(3) Puff balls – Branched, Septate,Ascospore(4) Trichoderma – Branched, Septate,ConidiaQ.138Q.136 vf/kdka'kr% leqnzh o izdk'k la'ys"kh tho lewg tkso.kZdksa ds vk/kkj ij uhyk ;k yky jax iznf'kZr djrsgS ,oa buls L=kkfor tho&fo"k lewnzh thoks dh e`R;qdk dkj.k curk gS] og lewg gS(1) jksMksQk;lh (2) lk;uksQkblh(3) ikbjksQk;lh (4) Øk;lksQkblhQ.137 lgh feyku dk p;u dhft,(1) jkbtksil – viVh;] cgqdsUnzhr,dksfufM;k(2) lsdsjksek;lhl – e`riks"kh] 'kkf[kr]iVh;] ptchtk.kq(3) iQ ckWy – 'kkf[kr] iVh;],Ldkschtk.kq(4) VªkbdksMekZ – 'kkf[kr] iVh;]dksfufM;kQ.138(1) (2)(1) (2)(3) (4)Identify the correct match based on the givenfigures(1) Marchantia – Antherediophore(2) Funaria – Independent sporophyte(3) Sphagnum – Monoecious(4) Chara – Heterotrichous, DioeciousQ.139 Heterosporus plant have sporophylls arrangedspirally on stem form cone, produce reduced fewcelled male gametophyte develop insidemicrosporangium(1) Selaginella (2) Salvinia(3) Ginkgo (4) Both (1) and (2)(3) (4)fn;s x;s fp=kksa ds vk/kkj ij lgh feyku dh igpkudhft,(1) ekdsZU'kh;k – iwa/kkuh/kj(2) ;wusfj;k – LorU=k chtk.kqn~fHkn(3) LQsXue – mHk;fyaxkJ;h(4) dkjk – fo"kerUrqdh] f}fyaxkJ;hQ.139 fo"kechtk.kqd ikni ftuesa chtk.kqi.kZ lfiZy dh rjgrus ij l?ku 'kadq cukrs gS] tks U;wuhd`r] dqNdksf'kdkvksa rd lhfer uj ;qXedksn~fHkn larfr dkfodkl y?kq chtk.kq/kkuh esa djrs gS] og gS(1) lsysftusyk (2) lkYohfu;k(3) fxUdks (4) nksuksa (1) o (2)CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 27


Q.140 Name the blank spaces A, B, C and D from thetable given belowType of Scientific Product MedicalMicrobes nameapplication(i) Fungus A CyclosporinB(ii) C Monascus Statin Dpurpureus(1) A-Yeast (Fungus),B-Lowering of blood cholesterol,C- Trichoderma polyspora,D- Organ transplant patients(2) A- Lowering of blood cholesterol,B- Trichoderma polyspora,C- Organ transplant patients,D-Yeast (Fungus)(3) A-Trichoderma polyspora,B-Organ transplant patients,C-Yeast (Fungus),D-Lowering of blood cholesterol(4) A-Organ transplant patients,B-Yeast (Fungus),C-Lowering of blood cholesterol,D- Trichoderma polysporaQ.141 a young infant may be feeding entirelyon mother's milk which is white in colourbut the stools which the infant passes outis quite yellowish. What is this yellow colour dueto ?(1) Pancreatic juice poured into duodenum(2) Intestinal juice(3) Bile pigments passed through bile juice(4) Undigested milk protein caseinQ.140 uhps nh xbZ rkfydk es fjDr LFkku A, B, C o D dkuke nhft,lq{etho oSKkfud mRikn fpfdRlh;dk uke ukevuqiz;ksx(i) dod A lkbDyks& BLiksjhu(ii) C eksuLdl LVsfVu DijI;wjhvl(1) A-;hLV ¼dod½B-jDr dkWysLVªky dks ?kVkukC-VªkbdksMekZ ikWyhLiksje,C-vax izR;kjksi.k ejht,(2) A-jDr dkWysLVªky dks ?kVkukB-VªkbdksMekZ ikWyhLiksje,C-vax izR;kjksi.k ejht,D-;hLV ¼dod½(3) A-VªkbdksMekZ ikWyhLiksje,B-vax izR;kjksi.k ejht,C-;hLV ¼dod½D-jDr dkWysLVªky dks ?kVkuk(4) A-vax izR;kjksi.k ejht,B-;hLV ¼dod½]C-jDr dkWysLVªky dks ?kVkukD-VªkbdksMekZ ikWyhLiksjeQ.141 ,d cM+k f'k'kq dsoy viuh ek¡ ds nw/k dk gh lsoudjrk gS tks lQsn jax dk gksrk gS exj f'k'kq tksfo"Bk ckgj fudkyrk gS & mldk jax ihyk gksrkgSA ;g ihyk jax fdlds dkj.k mRiUu gksrk gS ?(1) xzg.kh esa NksM+k x;k vXuk'k; jl(2) vak=k jl(3) fiÙk jl esa ls vk;s gq, fiÙk o.kZd(4) vikfpr nw/k izksVhu dslhuCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 28


Q.142 Given below are three statements (A-C) each withone or more blanks. Select the option whichcorrectly fills the blanks in the statements –Statements :A. ______ a traditional drink of some parts ofSouth India is made by fermenting sap frompalmsB. Citric acid is obtained through thefermentation carried out by ______ and______ on sugary syrups.C. In ______ the fungus forms a mantole on thesurface of the roots.(1) A-Toddy; B-Aspergillus niger, Mucor;C-Ectomycorrhiza(2) A-Wine; B-Aspergillus niger, Mucor;C-Ectomycorrhiza(3) A-Beer; B-Aspergillus niger, Mucor;C-Ectomycorrhiza(4) A-Rum; B-Aspergillus niger, Mucor;C-EctomycorrhizaQ.143 During the propagation of a nerve impulse, theaction potential results from the movement of:(1) K + ions from intracellular fluid toextracellular fluid(2) Na + ions from extracelluar fluid tointracellular fluid(3) K + ions from extracellular fluid tointracellular fluid(4) Na + ions from intracellular fluid toextracellular fluidQ.144 What will happen if the secretion of parietal cellsof gastric glands is blocked with an inhibitor?(1) In the absence of HCI secretion, inactivepepsinogen is not converted into the activeenzyme pepsin(2) Enterokinase will not be released from theduodenal mucosa and so trypsinogen is notconverted to trypsin(3) Gastric juice will be deficient in chymosin(4) Gastric juice will be deficient in pepsinogenQ.142 izR;sd esa ,d vFkok vf/kd fjDr LFkku lfgr uhpsrhu dFku (A-C) fn;s x;s gS fodYi dk p;ufdft, tks fd dFkuks esa lgh iwfrZ djsarF; :A. nf{k.kh Hkkjr ds dqN Hkkxksa esa ,d ijEijkxris; ______ gSa bls rkM jl ds fd.ou lsfufeZr fd;k tkrk gSAB. flVªhd vEy 'kdZjk ;qDr lhji ij ______ ,oa______ ds fd.ou ls izkIr gksrk gSAC. ______ esa dod] tM+ dh lrg ij esUVkWyfufeZr djrs gSA(1) A-VkWMh; B-,Lijftyl ukbxj, E;wdj;C-cká dod ewy(2) A-okbu; B-,Lijftyl ukbxj, E;wdj;C-cká dod ewy(3) A-ch;j; B-,Lijftyl ukbxj, E;wdj;C-cká dod ewy(4) A-je; B-,Lijftyl ukbxj, E;wdj;C-cká dod ewyQ.143 raf=kdk vkosx ds çs{k.k ds nkSjku fØ;kRed foHko] fdldhxfr dk ifj.kke gksrk gS ?(1) var dksf'kdh; rjy ls K + vk;uksa dh dksf'kdkckárjy esa dksA(2) dksf'kdk cká rjy ls Na + vk;uksa dh var%dksf'kdh;rjy esa dksA(3) dksf'kdkcká rjy ls K + vk;uksa dh var% dksf'kdh;rjy esas dksA(4) var% dksf'kdh; rjy ls Na + vk;uksa dh dksf'kdkckárjy esa dksAQ.144 ;fn tBj xazfFk;ksa dh ifj/kh; (parietal) fHkÙkh; dksf'kdkvksads lzo.k dks fdlh ,d laned ds }kjk jksd fn;k tk, rksD;k ifj.kke gksxk ?(1) HCI ds L=kko dh vuqifLFkfr esa] fuf"Ø; isfIlukstulfØ; isfIlu esa ifjofrZr ugha gksxkA(2) xzg.kh 'ys"erk ls ,aVsjksdkbust ugha fudysxk vkSj blrjg fVªfIlukstsu dk fVªfIlu esa ifjorZu ugha gksik;sxkA(3) tBj jl esa dkbeksflu dk vHkko gksxkA(4) tBj jl esa isfIlukstsu dk vHkko gksxkACAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 29


Q.145 During the transmission of nerve impulse througha nerve fibre, the potential on the inner side of theplasma membrane has which type of electriccharge ?(1) First positive, then negative and again back topositive(2) First negative, then positive and again back tonegative(3) First positive, then negative and continue tobe negative(4) First negative, then positive and continue tobe positiveQ.146 Pollen grains of angiosperms are resistant to hightemperature, strong acids and alkalis due to(1) Callose (2) Exine(3) Intine (4) GermporeQ.147 Perisperm is present in seeds of(1) Black peeper (2) Papaya(3) Beet (4) Both (1) and (3)Q.148 After entering into embryo sac, the pollen tuberelease two male gametes into cytoplasm of(1) Central cell (2) Synergid cell(3) Antipodal cell (4) Egg cellQ.149 Plants with following features of flowers show(a) Large flower (b) Colourfull(c) Rich in nector (d) Fragrant(1) Anemophilly (2) Ornithophilly(3) Entomophilly (4) HydrophillyQ.150 Plant part of a plant which taken out and grown intest tube, in special nutrient medium is called(1) Callus (2) Explant(3) Suspension culture (4) SomocloneQ.151 India is mainly an agricultural country.Agriculture accounts for approximately …..A….percent of India's GDP and employs ….B….percent of the population. 'A' and 'B' arerespectively.(1) 25, 50 (2) 33, 62 (3) 62, 33 (4) 30, 60Q.145 raf=kdk vkosx ds lapj.k ds nkSjku IykTek f>YYkh dsHkhrjh vksj fdl izdkj dk fo|qr vkos'k gksrk gS \(1) igys /kukRed] fQj _.kkRed vkSj fQj ls/kukRed(2) igys _.kkRed] fQj /kukRed vkSj fQj ls_.kkRed(3) igys /kukRed] fQj _.kkRed vkSj yxkrkj_.kkRed dh vksj lrr~ gks tkrk gSA(4) igys _.kkRed] fQj /kukRed vkSj yxkrkj/kukRed gh cuk jgrk gSAQ.146 fdlds dkj.k vko`Ùkchth;ksa ds ijkxd.k] mPprkieku] izcy vEy o {kkjks ds izfr izfrjks/kh gksrs gS(1) dsykst (2) ckápksy(3) vUr%pksy (4) tuu fNnzQ.147 fdlds chtks esa ifjHkzw.kiks"k mifLFkr gksrk gS -(1) dkyhfepZ (2) iihrk(3) pqdqUnj (4) (1) o (3) nksuksaQ.148 Hkzw.kdks"k esa izos'k ds Ik'pkr] ijkxuyh nks uj ;qXedfdlds dksf'kdk nzO; eas eqDr djrh gS(1) dsUnzh; dksf'kdk (2) lgk;d dksf'kdk(3) izfreq[kh dksf'kdk (4) v.Mdksf'kdkQ.149 iq"Ik ds fuEu y{k.kksa ;qDr ikni n'kkZrs gS(a) cM+s iq"Ik(b) jaxhu(c) edjUn eas izpwj (d) xU/k ;qDr(1) ok;q ijkx.k (2) i{kh ijkx.k(3) dhV ijkx.k (4) tyijkx.kQ.150 ikni dk Hkkx ftldks i`Fkd djds fof'k"V iks"kd ek/;e;qDr ij[kuyh esa o`f) djok;k tkrk gS] dgykrk gS(1) dSyl (2) drksZÙkd(3) fuyEcu loZ)u (4) lkseksDyksuQ.151 Hkkjr ,d d`f"k iz/kku ns'k gSA Hkkjr dh GDP dkyxHkx …..A…. izfr'kr d`f"k ls vkrk gS rFkktula[;k ds ….B…. izfr'kr dkexkj yksx d`f"kZ lstqMs gSA 'A' rFkk 'B' Øe'k% gksrs gSA(1) 25, 50 (2) 33, 62 (3) 62, 33 (4) 30, 60CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 30


Q.152 Which of the following is not a variety of Rice(1) IR-8 (2) Taichung native(3) Oryaza nivera (4) RatnaQ.153 Single cell proteins are fantastic substitute of(1) Carbohydrate (2) Fat(3) Protein (4) Nucleic acidQ.154 Which of the following is mismatched(1) Ophrys orchid – Ophrys bee(2) Fungi – Green algae(3) Cattle egret – Grazing cattle(4) Sea anemone – Clawn fishQ.155 Several plants posses hairy leaves, solid stem,nectorless and smooth leaves. These areadaptations against -(1) Competetion(2) Parasitism(3) Predator animal(4) Phytophagous insectsQ.156dN =rN⎛⎜dt ⎝k− N ⎞⎟ , Show the logistic growthk ⎠form of population. here 'K' is(1) Population density at time 't'(2) Intrinsic rate of natural increase(3) Carrying capacity(4) Base of natural logarithmsQ.157 Diapause in some insects and fishes differ fromhibernation / aestivation in -(1) Metabolic inactiveness(2) Suspended embryo development(3) Over come infavorable condition(4) Physiological state of dormancyQ.158 Which of the following is not a feature ofcompetition in a community(1) Fitness of one species is lower in presence ofanother species(2) When resources are limited competitivelysuperior will eliminate the other specis(3) Two species compete for some resourcereduce competition by resource portioning(4) Carnivores are more affected than herbivoresby competitionQ.152 fuEu esa ls dkSulh pkoy dh fdLe ugha gS -(1) IR-8 (2) rkbZpqax usVho(3) vksjkbtk fuosjk (4) jrukQ.153 ,dy dksf'kdk izksVhu fdldk mRd`"V fodYi gS(1) dkcksZgkbMªsV (2) olk(3) izksVhu (4) U;wfDy;d vEyQ.154 fuEu esa ls dkSulk lgh lqesfyr ugha gS(1) vkWQhjl vkdhZM & vkQhjl eD[kh(2) dod & gjk 'kSoky(3) pkSik;k & pjus okyk pkSik;k(4) leqUnzh ,fueksu & Dykmu eNyhQ.155 vusd ikniksa esa jksfey ifÙk;k¡] Bksl LrEHk] edjUnjfgr o rh{k.k ifÙk;ka gksrh gSA ;s fdlds fo:)vuqdwyu gS -(1) izfrLiZ)k(2) ijthfork(3) ijHk{kh tUrq(4) ikni Hk{kh dhVQ.156dN =rN⎛⎜dt ⎝k− N ⎞⎟ , lef"V dh y?kqx.kdh; voLFkkk ⎠dks n'kkZrk gSA ;gk¡ 'K' gS(1) le; 't' ij lef"V ?kuRo(2) izkd`frd o`f) dh vkUrfjd nj(3) /kkj.k {kerk(4) izkd`frd y?kqx.kd dk vk/kkjQ.157 dqN dhVks o eNfy;ksa esa mijfr 'khr @ xzh"efuf"Ø;rk ls fdlesa fHkUUk gksrh gS(1) mikip;h fu"Øh;rk esa(2) fuyfEcr Hkwz.k ifjo/kZu esa(3) izfrdwy voLFkkvksa dks xqtkjus esa(4) dkf;Zdh; izlqIrh voLFkk esaQ.158 fuEu esa ls dkSulk leqnk; esa izfrLiZ)k dk y{k.kugha gS(1) vU; tkfr dh mifLFkfr esa ,d tkfr dhv'kun{krk U;wu gksrh gSA(2) tc lalk/ku lhfer gksrs gS rks izfrLi)hZ :i lsJs"B tkfr vU; tkfr dks gVk nsrh gSA(3) leku lalk/kukas das fy, nks tkfr;k¡ izfrLi)kZdjrh gS rks lalk/ku lk>snkjh ds }kjk izfrLi)kZesa deh ykrh gSA(4) 'kkdkgkfj;ksa dh vis{kk ek¡lkgkjh izfrLi)kZ lsvf/kd izHkkfor gksrs gSACAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 31


Q.159 Which of the following is incorrect aboutecosystem(1) Continuous flow of enrgy in its bioticcomponents(2) Cycling of nutrient among it's biotic andabiotic components(3) Decompostion by decomposers regulatesnutrients cycling(4) It can succefully thrive well prolonged in theabsence of herbivoresQ.159 fuEu esa ls dkSulk ikfjrU=k ds ckjs eas xyr gS(1) blds tSfod ?kVdksa esa ÅtkZ dk lrr izokggksrk gS(2) blds tSfod o vtSfod ?kVdksa ds e/; iks"kdksadk pØ.k gksrk gSA(3) vi?kVdksa ds }kjk] vi?kVu iks"kd pØ.k dkfu;eu djrs gSA(4) 'kkdkgkfj;ksa dh vuqifLFkfr esa ;g lQyrkiwoZdnh?kZdky rd l{ke cuk jgsxk gSAQ.160Q.160The given pyramid represents -(1) Pyramid of energy in lake ecosystem(2) Pyramid of number in lake ecosystem(3) Pyramid of biomass in grassland ecosystem(4) Pyramid of biomass in lake ecosystemQ.161 At the climax stage of succession thephotosynthesis / Respiration Ratio (P/R ratio) ofcommunity is -(1) P = R (2) P > R(3) P < R (4) P ≠ RQ.162 A plant species is extinct from the forest near byto your village. Which is the probable cause ofthis biodiversity loss(1) Pollution (2) Alien species invasion(3) Habitat loss (4) CoextinctionQ.163 'FOAM' aims(1) Sanitation by Ecosan(2) Safe gaurding aracta marshes(3) World biodiversity conservation(4) Reducing green house gasesQ.164 'Bad Ozone' is present in(1) Stratosphere (2) Thermosphere(3) Troposphere (4) MesosphereQ.165 In aquatic ecosystems the micronutrients mainlyacts as limiting factor is -(1) N (2) P(3) Fe (4) Both (1) and (2)fn;k x;k fijkfeM n'kkZrk gS -(1) >hy ikfjrU=k eas ÅtkZ dk fijkfeM(2) >hy ikfjrU=k eas la[;k dk fijkfeM(3) ?kkl LFky ikfjrU=k eas tSoHkkj fijkfeM(4) >hy ikfjrU=k eas tSoHkkj fijkfeMQ.161 vuqØe.k dh pje voLFkk ij leqnk; dk izdk'kla'ys"k.k @ 'olu vuqikr (P/R vuqikr) gS -(1) P = R (2) P > R(3) P < R (4) P ≠ RQ.162 ,d ikni tkfr vkids xk¡o ds lehi ds taxy lsfoyqIr gks tkrh gSA bl tSofofo/krk gkfu dklaHkkfor dkj.k dkSulk gSA(1) iznw"k.k (2) fons'kh tkfr vkØe.k(3) vkokl {kfr (4) lg foyqfIrQ.163 'FOAM' dk mn~ns'; gSa(1) bdkslsu ds }kjk LoPNrk(2) vdsZVk ek'ksZ'k dh lqj{kk(3) fo'o tSofofo/krk laj{k.k(4) gfjr x`g xSlks esa dehQ.164 'csM vkstksu' mifLFkr gksrk gS(1) lerki e.My esa (2) rki e.My esa(3) {kksHk e.My esa (4) e/;e.My esaQ.165 tyh; ikfjrU=k esa lq{e iks"kd tks eq[;r% lhekdkjhdkjd dh rjg dk;Z djrk gS -(1) N (2) P(3) Fe (4) nksuksa (1) o (2)CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 32


Q.173 What is not true w.r.t. earthworm -(1) Photoreceptor are present(2) Hermophrodite, Testes and ovaries arepresent in same segment.(3) Two pairs of accessory glands are present in17 th & 19 th segment(4) Supra-oesophageal blood vessel is presentin 9 th & 13 th segmentQ.174 What is true w.r.t. cockroach -(1) Proventriculus has an outer layer of thickcircular muscles and thick inner cuticleforming six highly chitinous teeth.(2) Entire foregut is lined by cuticle(3) Haemocoel in filled with haemolymphhaving respiratory pigment(4) Both 1 & 2Q.175AQ.173 dspq, ds lUnHkZ esa D;k lR; ugha gS -(1) izdk'kxzkgh mifLFkr gksrs gS(2) mHk;fyaxh] o`"k.k o v.Mk'k; leku [k.M esamifLFkr gksrs gSA(3) lgk;d xzfFk;ksa ds nks ;qXe 17 th o 19 th [k.Mksa esamifLFkr gksrs gSA(4) lqizk&xzklukyh; jDr okfgdk 9 th o 13 th [k.Mksaesa mifLFkr gksrs gSAQ.174 frypV~Vs ds lUnHkZ esa D;k lR; gS -(1) izksosUVªhdqyl eas eksVh orqZy isf'k;k dh ckgjhijr rFkk eksVh vkUrfjd D;wVhdy gksrh gS tksfd N% mPp dkbfVuhd`r nk¡r cukrh gSA(2) lEiw.kZ vxzvkU=k D;wfVdy ls vkofjr gksrh gS(3) ghekslhy gheksfyEQ ls Hkjh gksrh gS blesa'oludkjh o.kZd gksrs gSA(4) 1 o 2 nksuksaQ.175ABBCIdentify lable (A), (B) and (C) -(1) Antennal socket, labrum, maxillary pulp(2) Ocellus, labium, labial pulp(3) Ocellus, mandible, labium(4) Ocellus, maxilla, labiumQ.176 Poikilotherms, having creeping or crawlingmode of locomotion and no external earopenings with internal fertilization -(1) Aptenodytes (2) Chelone(3) Ornithorhynchus (4) IchthyophisQ.177 What is not true w.r.t. chondrichthyes -(1) Placoid scales(2) Cold blooded(3) Males possess claspers(4) 6-15 pairs of gill slits without operculumukekadu (A), (B) o (C) dh igpku dhft, -(1) Jàxhdh; lkWdsV] yscze] esfDlyjh iYi(2) vkWflyl, ysfc;e, ysfc;y iYi(3) vkWflyl, esfUMcy, ysfc;e(4) vkWflyl, esfDlyk, ysfc;eQ.176 vlerkih ftuesa xfr dk izdkj jSxuk o Qqndukgksrk gS rFkk vkUrfjd fu"kspu ds lkFk cká d.kZfNnz gksrs gS -(1) ,IVsuksMk;Vl (2) dhyksu(3) vkfuZFkksjkbusdl (4) bfDFk;ksfQlQ.177 DokUMªhDFkht ds lUnHkZ esa D;k lR; ugha gS -(1) IysdkWbM 'kYd(2) 'khr :f/kj /kkjh ¼vlerkih½(3) uj eas eSFkqukax gksrs gS(4) vijdqye jfgr fxynjkjks ds 6-15 ;qXeCCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 34


Q.178 Match the columnColumn-IColumn-III. Golden Rice A. Cry proteinII. Bt toxin B. Rich in vit.AIII. RNAi C. First transgeniccowIV. Rosie D. Gene silencing(1) I-B, II-A, III-D, IV-C(2) I-B, II-A, III-C, IV-D(3) I-B, II-C, III-A, IV-D(4) I-D, II-A, III-B, IV-CQ.179 Which is incorrect match –(1) Platyhelminthes – Flat body, bilateralsymmetry(2) Aschelminthes – Pseudocoelomates,parasitic as well asnon-parasitic(3) Annelida – Metamerism(4) Mollusca – Exclusivelymarine with softbody surroundedby calcareous shellQ.178 LrEHk feyku dhft,LrEHk-ILrEHk-III. Lof.kZe pkoy A. ØkbZ izksVhuII. Bt fo"k B. foVkfeu A esaizpwjIII. RNAi C. IkzFke ijkthuh xk;IV. jksth D. thu lkbysfUlx(1) I-B, II-A, III-D, IV-C(2) I-B, II-A, III-C, IV-D(3) I-B, II-C, III-A, IV-D(4) I-D, II-A, III-B, IV-CQ.179 dkSulk xyr feyku gS –(1) IysVhgsYehuFkht – piVk 'kjhj]f}ik'oZlefer(2) ,LdsgsYehuFkht – dwVxwgh;] ijthohvFkok vijthoh(3) ,suhfyMk – dk;kUrj.k(4) eksyLdk – dsYlhd`r dop lsf?kjs gq;s eqyk;e'kjhj ;qDr dsoyleqUnzhQ.180 Which is correctly matched -(1) Australopithecus – 2 mya., lived incentral Europe,essentially atefruit.(2) Homo habilis – First human likehominid(3) Homo erectus – 1.5 m.ya. 900 cc(4) Neanderthalman– Lived in east &central asia witha brain size of1400 ccQ.180 dkSulk lgh lqesfyr gS -(1) vkLVªsyksfiFksdl – 2 mya., e/; ;wjksiesa jgrk Fkkvko';d :Ik lsQy [kkrk FkkA(2) gkseks gsfcfyl – izFke ekuo ln`';gkseksfuM(3) gkseks bjsDVl – 1.5 m.ya. 900 cc(4) fu,UMjFkyekuo– efLr"d dk vkdkj1400 cc ;qDr] iwohZo e/; ,f'k;k esajgrk Fkk ACAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 35


Q.181 Which is a wrong statement w.r.t. organicevolution -(1) Fitness is the end result of the ability toadapt and get selected by nature.(2) Natural selection and adaptive radiation arethe two key concepts of Darwinian theory.(3) When we describe the story of life on earthwe treat evolution as a consequence of aprocess called natural selection(4) Nature selects for fitness based oncharacteristics which are inherited.Q.182 Fill up the blanksAfter one month of pregnancy, the embryo's…..A…. is formed. By the end of the …..B…..month of pregnancy, the foetus develops limbsand digits. By the end of ….C…., most of themajor organ systems are formed for example,the limbs and external genital organs are welldeveloped.By the end of …..D…., the body iscovered with fine hair, eye-lids separate andeyelashes are formed.(1) A-heart, B-second, C-First trimester, D-Second trimester(2) A-heart, B-second, C-First month, D-Second month(3) A-heart, B-second, C-First week, D-Secondweek(4) A-heart, B-fourth, C-First trimester, D-Second trimesterQ.183 The lungs expand in inspiration / inhalationbecause -(1) Diaphragm contracts upward(2) The volume of thoracic cavity increases(3) External intercostals muscles relax(4) Diaphragm relaxesQ.184 Addition muscles for forceful breathing are -(1) Diaphragm and external intercostalsmuscles(2) Abdominal muscles and internal intercostalmuscles(3) Diaphragm and abdominal muscles(4) External and internal intercostal muscles.Q.181 dkcZfud mn~fodkl ds lUnHkZ esa dkSulk dFku xyrgS -(1) ;ksX;rk] vuqdwfyr gksus ds fy, {kerk dk vfUreifj.kke gS o izd`fr ls p;fur gks tkrh gSA(2) izkd`frd p;u o vuqdwyh fofdj.k MkfoZufl)kUr ds nks dqath fl)kar gSA(3) tc ge i`Foh ij thou dh dgkuh dk o.kZu djrsgS rks ge ekurs gS fd mn~fodkl ftl izfØ;k dkifj.kke gS og izkd`frd p;u dgykrh gSA(4) y{k.kksa ij vk/kkfjr ;ksX;rk ds fy, izd`fr p;udjrh gS] tks oa'kkxr gksrh gSAQ.182 ,d efgus dh xHkkZoLFkk ds Ik'pkr~ Hkwz.k dk…..A…. fufeZr gksrk gSA xHkkZoLFkk ds …..B…..efgus ds vURk rd Hkzw.k ds ikn o vaxqfy;k¡fodflr gksrh gS ….C…. ds vUr rd yxHkx lHkhizeq[k vax rU=kksa dh jpuk gks tkrh gSA mnkgj.k dsfy, ikn ,oa tuu vax vPNh rjg fodflr gkstkrs gSA …..D…. ds vURk rd 'kjhj dksey ckyksls


Q.185 Blood carries the CO 2 in 3 forms. The correctpercentages of CO 2 in these forms are -As carbamino-haemoglobinin RBCAsbicarbonatesDissolvedform inplasma(1) 20 - 25 % 70 % 7 %(2) 70 % 20 - 25 % 7 %(3) 20 - 25 % 7 % 70 %(4) 7 % 20 - 25 % 70 %Q.186 Which of the following statements is wrongabout lymph.I. Lymph is colourful as it has haemoglobinbut no RBCII. The fluid present in lymphatic system iscalled lymphIII. It contains specialized lymphocytes whichare responsible for immunity of the bodyIV. Lymph is an important carrier for nutrientand hormonesV. Fats are absorbed through lymph in thelacteals present in the intestinal villi.(1) Only I (2) III and IV(3) II and III (4) Only IVQ.187 Which of the following is correct about humanheart ?(1) The volume of both atria > the volume ofboth ventricles(2) The volume of both ventricle > The volumeof both atria(3) The volume of both atria = the volume ofboth ventricles(4) Ventricles are upper chambers and atria arelower chambers in our heartQ.188 Which one of the following is the correctmatching of the events ocuring during menstrualcycle ?(1) Proliferative phase : rapid regereration ofmyometrium and maturation of Graafianfollicle(2) Secretory phase : development of corpusluteum and increased secretion ofprogesterone(3) Menstruation : breakdown of myometriumand ovum not fertilised(4) Ovulation : LH and FSH attain peak leveland sharp fall in the secretion ofprogesteroneQ.185 jDr] 3 voLFkkvksa esa CO 2 dks ifjofgr djrk gSA buvoLFkkvksa esa CO 2 dk lgh izfr'kr gS -RBC easdkcsZehuks-&gheksXyksfcu dsckbdkcksZusVlds :i esaIykTek esa?kqfyrvoLFkk esa:i esa(1) 20 - 25 % 70 % 7 %(2) 70 % 20 - 25 % 7 %(3) 20 - 25 % 7 % 70 %(4) 7 % 20 - 25 % 70 %Q.186 fuEu esa ls dkSulk dFku yfldk ds ckjs esa xyr gSI. yfldk jaxhu gksrk gS] blesa gheksXyksfcu gksrk gSfdUrq RBC ughaII. yfldk rU=k esa tks nzo mifLFkr gksrk gS ogyfldk dgykrk gSAIII. blesa fof'k"V yfldk dksf'kdk,s gksrh gS tks fd'kjhj dh izfrj{kk ds fy, mÙkjnk;h gksrh gSAIV. yfldk] iks"kd o gkeksZUl ds fy, egRoiw.kZokgd gksrk gSV. vkU=kh; lq{ekdqaj esa mifLFkr ysfDV;y dhyfldk esa olk vo'kksf"kr gksrh gSA(1) dsoy I (2) III o IV(3) II o III (4) dsoy IVQ.187 fuEu eas ls dkSulk ekuo ân; ds ckjs eas lR; gS ?(1) nksuksa vkfyUnksa dk vk;ru > nksuksa fuy;ksa dkvk;ru(2) nksuks fuy;ksa dk vk;ru > nksuksa vkfyUnksa dksvk;ru(3) nksuksa vkfyUnksa dk vk;ru = nksuksa fuy;ksa dkvk;ru(4) fuy; Åijh d{k rFkk vkfyUn fupys d{kgksrs gSAQ.188 fuEu esa ls dkSulk] jt pØ ds nkSjku gksus okyh?kVukvksa dk lgh feyku gS ?(1) izpjksn~Hkou izkoLFkk : ek;ksesfVª;e dk rhozvi?kVu o xzkQh;u iqfVdkvksa dk ifjiDdou(2) L=kkoh izkoLFkk % dkiZl Y;wfV;e dk fodkl ,oaizkstsLVªksu dk L=kko c


Q.189 The below figure is the diagrammaticrepresentation of standard ECGRQ.189 uhps fn;s x;s fp=k LVs.MMZ ECG dk fpf=k; fu:i.kgSRP Q STP Q STColumn-I Column-IIA. P-wave I. Ventriculardepolarizationfollowed byventricular contractionB. QRScomplexII. Atrial depolarizationfollowed by systole ofboth atriaC. T-wave III. Ventricularrepolarizationfollowed byventricular relaxation(1) A-I, B-II, C-III (2) A-III, B-II, C-I(3) A-II, B-I, C-III (4) A-II, B-III, C-IQ.190 Which of the following statements is wrongabout the human excretory system ?(1) Excretory system consists of one pair of beanshaped kidneys, one pair of ureter, a urinarybladder and a urethra.(2) Kidneys are situated between the 12 ththoracic and 3 rd lumbar vertebrae close to thedorsal wall in abdominal cavity(3) Right kidney is at little higher level than theleft one(4) AllLrEHk-I LrEHk-IIA. P-rjax I. fuy; fo/kzqohdj.k orRi'pkr fuy; ladqpuB. QRS ladqy II. vkfyUn fo/kzqohdj.k orRi'pkr nksuksa vkfyUnksdk ladqpuC. T-rajx III. fuy;h iquZ/kzqohdj.k orRi'pkr fuy;hvuqf'kfFkyu(1) A-I, B-II, C-III (2) A-III, B-II, C-I(3) A-II, B-I, C-III (4) A-II, B-III, C-IQ.190 fuEu esa ls dkSulk ekuo mRlthZ rU=k ds ckjs esaxyr gS ?(1) mRltZu rU=k] lse ds vkdkj ds o`Ddksa ds ,d;qXe] ew=k ufydk ds ,d ;qXe] ,d eq=kk'k; ,oa,d eq=kekxZ ls fufeZr gksrk gSA(2) o`Dd mnjh; xqgk esa 12 th o{kh; ,oa 3 rd dfVd'ks:d ds e/; i`"B fHkfÙk ls layXu fLFkr gksrsgSA(3) nk;k¡ o`Dd ck¡;s dh vis{kk FkksM+k lk Åij gksrk gSA(4) lHkhQ.191 Which of the following is not correct ?(1) Blood vessel leading to glomerulus is calledafferent arteriole(2) Vasa recta, peritubular capillaries, Bowman'scapsule all have blood(3) Cortical nephron has no or highly reducedvasa recta(4) Vasa recta runs parallel to the Henle's loopin juxtamedullary nephrons but the flow ofblood inside them is in opposite directionQ.191 fuEu eas ls dkSulk lgh ugha gS ?(1) :f/kj okfgdk,sa tks Xykses:yl rd igq¡prh gSvfHkokgh /kefudk,sa dgykrh gSA(2) oklk jsDVk] ifjufydh; dsf'kdkvksa] cksmeulEiwV] lHkh esa jDr gksrk gSA(3) oYdqVh; usÝksu esa oklk jsDVk vR;f/kd NksVh ;kvuqifLFkr gksrh gSA(4) tDlVkesM~;wyjh usÝksUl esa oklk jsDVklekukUrj :Ik ls gsUys ds ik'k ds lkFk pyrs gSfdUrq mueas jDr izokg foijhr fn'kk esa gksrk gSCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 38


Q.192 IUDs -I. Increase phagocytosis of spermsII. Release Cu ions that suppress sperm motilityand fertilizing capacity of spermsIII. Make the uterus unsuitable for implantation.IV. Make the cervix hostile to spermsV. Prevent semen from entering the femalereproductive tract.(1) I, II, III, IV, V (2) I, II, III, IV(3) I, II (4) II, III, IVQ.193 The diagram represents a single nephron from amammalian kidney. Identify which of thenumbered regions isQ.192 IUDs -I. 'kqØk.kq ds Hk{k.k dks c


Q.195 Given below is the diagram of a malereproductive system. In which one of the optionsall the five parts A, B, C, D and E are correct ?Q.195 uhps fn;k x;k fp=k uj tuu rU=k dk gS ftlesa,d fodYi esa lHkh ikap Hkkx A, B, C, D o E lghgS ?(1) A-Rectum, B-Seminal Vesicle, C-Prostate,D-Urethra, E-Epididymis(2) A-Urinary bladder, B-Seminal Vesicle,C-Prostate, D-Urethra, E-Epididymis(3) A-Urinary bladder, B-Prostate, C-SeminalVesicle, D-Urethra, E-Epididymis(4) A-Urinary bladder, B-Seminal Vesicle,C-Prostate, D-Epididymis, E-UrethraQ.196 Following methodology has been used for cattle,Sheep, buffaloes etc.Cow is administrated with (1) hormone↓(2)↓6-8 eggs per cycle are derived↓Artificial insemination↓Fertilized eggs at 8-32cells are recovered↓(3)(1) 1-FSH, 2-Superovulation due to inducedfollicular maturation, 3-Transfer to surrogatemother(2) 1-GnRH, 2-Superovulation due to inducedfollicular maturation, 3-Transfer to surrogatemother(1) A-eyk'k;, B-'kqØk'k;, C-izksLVsV, D-ew=kekxZ,E-vf/ko`"k.k(2) A-ew=kk'k;, B-'kqØk'k;, C-izksLVsV, D-ew=kekxZ,E-vf/ko`"k.k(3) A-ew=kk'k;, B-izksLVsV, C-'kqØk'k;, D-ew=kekxZ,E-vf/ko`"k.k(4) A-ew=kk'k;, B-'kqØk'k;, C-izksLVsV, D-vf/ko`"k.k,E-ew=kekxZQ.196 fuEu fof/k] HkSlks] HksM+ks o pkSik;ksa ds fy, iz;qDrgksrh gSxk; gkeksZu (1) ls mipkfjr gksrh gS↓(2)↓6-8 v.Ms izfr pØ mRiUUk gksrs gS↓d`f=ke oh;Z lspu↓8-32 dksf'kdkvksa dh voLFkk ij fu"ksfpr v.Mks dklaxzg gksrk gS↓(3)(1) 1-FSH, 2-izsfjr iqVhdh; ifjiDou ds dkj.kvfrv.MksRltZu, 3-ljksxsV ekrk esa LFkkukUrfjr(2) 1-GnRH, 2-izsfjr iqVhdh; ifjiDou ds dkj.kvfrv.MksRltZu, 3-ljksxsV ekrk esa LFkkukUrfjrCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 40


(3) 1-Progesterone, 2-Superovulation due toinduced follicular maturation, 3-Transfer tosurrogate mother(4) 1-Estrogen, 2-Superovulation due toinduced follicular maturation, 3-Transfer tosurrogate motherQ.197 The following diagram refers to femalereproductive system of human, Identify A to F(3) 1-izkstsfLVjksu, 2-izsfjr iqVhdh; ifjiDou dsdkj.k vfrv.MksRltZu, 3-ljksxsV ekrk esaLFkkukUrfjr(4) 1-,LVªkstu, 2-izsfjr iqVhdh; ifjiDou dsdkj.k vfrv.MksRltZu, 3-ljksxsV ekrk esaLFkkukUrfjrQ.197 fuEu fp=k ekuo ds eknk tuu rU=k dks n'kkZrk gSA ls F rd igpku dhft,(1) A-Isthmus, B-Ampulla, C-Infundibulum,D-Fallopian tube, E-Ovary, F-Uterinefundus(2) A- Ampulla, B-Isthmus, C-Infundibulum,D-Fallopian tube, E-Ovary, F-Uterinefundus(3) A-Isthmus, B-Infundibulum, C- Ampulla,D-Fallopian tube, E-Ovary, F-Uterinefundus(4) A- Ampulla, B-Infundibulum, C-Isthmus,D-Fallopian tube, E-Ovary, F-UterinefundusQ.198 The following refers to spermatogenesis andoogenesis in human. Identify A to H correctly –(1) A-ldh.kZiFk, B-rqfEcdk, C-dhid,D-fMEcokfguh ufydk, E-v.Mk'k;, F-xHkkZ'k;hQaMl(2) A-rqfEcdk, B-ldh.kZiFk, C-dhid,D-fMEcokfguh ufydk, E-v.Mk'k;, F- xHkkZ'k;hQaMl(3) A-ldh.kZiFk, B-dhid, C-rqfEcdk,D-fMEcokfguh ufydk, E-v.Mk'k;, F- xHkkZ'k;hQaMl(4) A-rqfEcdk, B-dhid, C-ldh.kZiFk,D-fMEcokfguh ufydk, E-v.Mk'k;, F- xHkkZ'k;hQaMlQ.198 fuEukafdr fp=k euq";ksa esa 'kqØtud rFkk v.Mtuudks n'kkZrk gS A ls H rd igpkus –(1) A-Spermatogonia, B-Secondaryspermatocytes, C-Primary spermatocytes,D-Spermatids, E-Primary oocyte, F-Secondary oocyte, G-First polar body, H-second polar body(1) A-'kqØk.kqtu, B-f}rh;d 'kqØk.kq dksf'kdk,sa,C-izkFkfed v.Md dksf'kdk, D-'kqØk.kqizlw,E-izkFkfed v.Md, F-f}rh;d v.Md, G-izFke/kzqoh; dk;, H-f}rh;d /kzqoh;dk;CAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 41


(2) A-Spermatogonia, B-Primaryspermatocytes, C- Secondaryspermatocytes, D-Spermatids, E-Secondaryoocyte, F- Primary oocyte,G-First polar body, H-second polar body(3) A-Spermatogonia, B-Primaryspermatocytes, C-Secondary spermatocytes,D-Spermatids, E-Primary oocyte, F-Secondary oocyte, G-First polar body, H-second polar body(4) A-Spermatogonia, B-Primaryspermatocytes, C-Secondary spermatocytes,D-Spermatids, E-Primary oocyte, F-Secondary oocyte, G- second polar body,H- First polar bodyQ.199 Match the column A with the column BColumn-A Column-BI. Sericulture A. Bee keepingII. Pisciculture B. Rearing ofsilkwormIII. Apiculture C. MicropropagationIV. Tissue D. Rearing of fishescultureV. Green E. FishrevolutionVI. White F. Crop plantsrevolutionVII. BluerevolutionG. Milk(1) I-D, II-C, III-B, IV-A, V-F, VI-G, VII-E(2) I-D, II-A, III-B, IV-C, V-G, VI-F, VII-E(3) I-A, II-B, III-C, IV-D, V-F, VI-G, VII-E(4) I-B, II-D, III-A, IV-C, V-F, VI-G, VII-EQ.200 The figure below illustrates the changes takingplace during the human menstruation cycle.(2) A-'kqØk.kqtu, B-izkFkfed v.Mddksf'kdk, C- f}rh;d 'kqØk.kq dksf'kdk,, D-'kqØk.kqizlw, E-f}rh;d v.Md, F- izkFkfedv.Md,G- izFke /kzqoh; dk;, H- f}rh;d /kzqoh;dk;(3) A-'kqØk.kqtu, B-izkFkfed v.Mddksf'kdk, C- f}rh;d 'kqØk.kq dksf'kdk, D-'kqØk.kqizlw, E-izkFkfed v.Md, F-f}rh;dv.Md, G-izFke /kzqoh; dk;,, H- f}rh;d/kzqoh;dk;(4) A-'kqØk.kqtu, B-izkFkfed v.Md dksf'kdk,C-f}rh;d 'kqØk.kq dksf'kdk,, D-'kqØk.kqizlw,E-izkFkfed v.Md, F-f}rh;d v.Md,G-f}rh;d /kzqoh;dk;, H-izFke /kzqoh; dk;,Q.199 LrEHk A dk feyku LrEHk B ds lkFk dhft,LrEHk-A LrEHk -BI. lsjhdYpj A. e/kqeD[kh ikyuII. filhdYpj B. js'kedèh dkikyuIII. ,sihdYpj C. lq{e izoZ/kuIV. mÙkd loZ/ku D. eNyh ikyuV. gjh ØkfUr E. eNyhVI. 'osr ØkfUr F. Qly ikniVII. uhyh ØkfUr G. nqX/k(1) I-D, II-C, III-B, IV-A, V-F, VI-G, VII-E(2) I-D, II-A, III-B, IV-C, V-G, VI-F, VII-E(3) I-A, II-B, III-C, IV-D, V-F, VI-G, VII-E(4) I-B, II-D, III-A, IV-C, V-F, VI-G, VII-EQ.200 uhps fn;s x;s fp=k esa ekuo esa jtpØ ds nkSjkugksus okys ifjorZuksa dks n'kkZ;k x;k gSACAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 42


In each of the boxes shown in the figure writethe name of the hormone or hormonescontrolling the stage in the human menstrualcycle.(1) (i) FSH, (ii) LH, (iii) LH, (iv) Estrogen,(v) Progesterone(2) (i) LH, (ii) FSH, (iii) LH, (iv) Estrogen,(v) Progesterone(3) (i) FSH, (ii) LH, (iii) FSH, (iv) Estrogen,(v) Progesterone(4) (i) FSH, (ii) LH, (iii) LH, (iv) Progesterone,(v) Estrogenfp=k esa n'kkZ;s x;s izR;sd fMCcs esa gkeksZUk dk ukevFkok ekuo jt pØ esa voLFkk dks fu;fU=kr djusokys gkeksZu dk uke fy[ksA(1) (i) FSH, (ii) LH, (iii) LH, (iv) bLVªkstu,(v) izkstsLVhjksu(2) (i) LH, (ii) FSH, (iii) LH, (iv) bLVªkstu,(v) izkstsLVhjksu(3) (i) FSH, (ii) LH, (iii) FSH, (iv) bLVªkstu, (v)izkstsLVhjksu(4) (i) FSH, (ii) LH, (iii) LH, (iv) izkstsLVhjksu, (v)bLVªkstuCAREER POINT, CP Tower, Road No.1, IPIA, Kota (Raj.), Ph: 0744-3040000 Page # 43


Time : 3 : 00 Hrs. MAX MARKS: 800Name : ______________________________________Roll No. : ____________________ Date : _____________________fuEu funsZ'kksa dks /;kuiwoZd if

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