LM Guide THK - Industrial Technologies

Индастриал Технолоджис www.industrial‐technologies.com.ua +38 044 498 21 94•Applied load in the lateral direction PtrdnPtrd1 = –m1•α3•l 32•l 0= – 111.1 NPtrd2 = +m1•α3•l 32•l 0= + 111.1 NPtrd3 = +m1•α3•l 32•l 0= + 111.1 NPtrd4 = +m1•α3•l 32•l 0= – 111.1 N[Combined Radial And Thrust Load]• During uniform motion:PE1 = P1 = 2891 NPE2 = P2 = 4459 NPE3 = P3 = 3479 NPE4 = P4 = 1911 N• During leftward accelerationPEla1 = | Pl a1 | + | Ptl a1 | = 608.9 NPEla2 = | Pl a2 | + | Ptl a2 | = 7958.9 NPEla3 = | Pl a3 | + | Ptl a3 | = 6978.9 NPEla4 = | Pl a4 | + | Ptl a4 | = 1588.9 N• During leftward decelerationPEld1 = | Pl d1 | + | Ptl d1 | = 4057.7 NPEld2 = | Pl d2 | + | Ptl d2 | = 3514.5 NPEld3 = | Pl d3 | + | Ptl d3 | = 2534.5 NPEld4 = | Pl d4 | + | Ptl d4 | = 3077.7 N• During rightward accelerationPEra1 = | Pra1 | + | Ptra1 | = 6390.9 NPEra2 = | Pra2 | + | Ptra2 | = 1625.7 NPEra3 = | Pra3 | + | Ptra3 | = 645.7 NPEra4 = | Pra4 | + | Ptra4 | = 5410.9 N• During rightward decelerationPErd1 = | Prd1 | + | Ptrd1 | = 1946.5 NPErd2 = | Prd2 | + | Ptrd2 | = 5625.7 NPErd3 = | Prd3 | + | Ptrd3 | = 4645.7 NPErd4 = | Prd4 | + | Ptrd4 | = 966.5 N[Static Safety Factor]As indicated above, the maximum load is applied to the LM Guide during the leftward acceleration ofthe second LM block. Therefore, the static safety factor (fs) is obtained in the following equation.C0 81.410 3fS = = = 10.2PEl a2 7958.9Industrial TechnologiesA1-82