LM Guide THK - Industrial Technologies

Индастриал Технолоджис www.industrial‐technologies.com.ua +38 044 498 21 94[Load Applied to the LM Block]Calculate the load applied to each LM block.• During uniform motion•Applied load in the radial direction Pnm1g m1g•l 2 m1 g•l3 m2gP1 = + – + + = +2891N4 2•l 0 2•l1 4m1g m1g•l 2 m1 g•l3 m2gP2 = + + + + = +4459N4 2•l 0 2•l1 4m1g m1g•l 2 m1g•l3 m2gP3 = + + – + = +3479N4 2•l 0 2•l1 4m1g m1g•l 2 m1g•l3 m2gP4 = + – – + = +1911N4 2•l 0 2•l1 4• During leftward acceleration•Applied load in the radial direction Pl anPla1Pla2Pla3Pla4m1•α1•l 52•l 0m1•α1•l 52•l 0m1•α1•l 52•l 0m1•α1•l 52•l 0m2•α1•l 42•l 0m2•α1•l 42•l 0m2•α1•l 42•l 0m2•α1•l 42•l 0= P1 – – = – 275.6 N= P2 + + = + 7625.6 N= P3 + + = + 6645.6 N= P4 – – = – 1255.6 N•Applied load in the lateral direction Ptlanm1•α1•l 3Ptla1 = – = – 333.3 N2•l 0m1•α1•l 3Ptla2 = + = + 333.3 N2•l 0m1•α1•l 3Ptla3 = + = + 333.3 N2•l 0m1•α1•l 3Ptla4 = – = – 333.3 N2•l 0• During leftward deceleration•Applied load in the radial direction Pl dnPld1Pld2Pld3Pld4m1•α3•l 52•l 0m1•α3•l 52•l 0m1•α3•l 52•l 0m1•α3•l 52•l 0m2•α3•l 42•l 0m2•α3•l 42•l 0m2•α3•l 42•l 0m2•α3•l 42•l 0= P1 + + = + 3946.6 N= P2 – – = + 3403.4 N= P3 – – = + 2423.4 N= P4 + + = + 2966.6 NIndustrial TechnologiesA1-80