LM Guide THK - Industrial Technologies

Индастриал Технолоджис www.industrial‐technologies.com.ua +38 044 498 21 94Point of SelectionCalculating the Applied LoadConditionApplied Load Equation910Vertical mountwith inertial 0P1TP2TP1Speed V (m/s)P2t1 t2 t3 Time (s)Velocity diagramE.g.: Conveyance liftNote) Load is positive in the direction of the arrow.Fl 1P4l 2mgl 3αHorizontal mount with external forcel 5FF1l 4F2F3l 2P4l 1 l 3P4TP3l 0 P3TE.g.: Drill unit,Milling machine,Lathe,Machining centerand other cutting machineDuring accelerationm (g+α 1) l 2P1 = P4 = –2•l 0m (g+α 1) l 2P2 = P3 =2•l 0m (g+α 1) l 3P1T = P4T =2•l 0m (g+α 1) l 3P2T = P3T = –2•l 0During uniform motionmg•l 2P1 = P4 = –2•l 0mg•l 2P2 = P3 =2•l 0mg•l 3P1T = P4T =2•l 0mg•l 3P2T = P3T = –2•l 0During decelerationm (g – α 3) l 2P1 = P4 = –2•l 0m (g – α 3) l 2P2 = P3 =2•l 0m (g – α 3) l 3P1T = P4T =2•l 0m (g – α 3) l 3P2T = P3T = –2•l 0Under force F1P1 = P4 = –P2 = P3 =F1•l 52•l 0F1•l 52•l 0P1T = P4T = F1•l 12•l 0P2T = P3T = – F1•l 12•l 0Under force F2P1 = P4 =F2P2 = P3 =4 –Under force F3F3•l 3P1 = P2 =2•l 1F3•l 3P3 = P4 = –P1T = P4T = –P2T = P3T = –F24 +2•l 1F2•l 22•l 0F2•l 22•l 0F3 F3•l 24 – 2•l 0F3 F3•l 24 + 2•l 0LM GuideIndustrial TechnologiesA1-69