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Calibration of a Terrestrial Laser Scanner - Institute of Geodesy and ...

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40323 o.o; 50545 aT [jjs] 1.0().2 St[s] :1.20 :1.28 2.49 osi().02 ().06 0.02100 5. Kinematic <strong>Laser</strong> Scanningcomputer is derived as follows. A first time tag is stored, when the rotation is started. And a second timetag is stored, when the rotation is stopped. The difference <strong>of</strong> these two time pointsdefines the total time t.However, there is an uncertainty in this total time. A delay is obviously present, especially between startingthe rotation, defined by clicking a button 'start', <strong>and</strong> reaching the specified angular velocity, defined bycounting the number <strong>of</strong> vertical pr<strong>of</strong>iles. This time delay St is a specific constant for each angular velocity<strong>and</strong> can, therefore, be modeled mathematically.The modified relation is:T = t-St(5.11)Considering Equation (5.11), an adjustment problemcan be formulated. The observation is the total time t<strong>and</strong> the unknowns are the rotation time T as well as the time delay St. Based on the treatment <strong>of</strong> the number<strong>of</strong> rotations n, a different adjustment problem is achieved: either (1) Gauss-Markov, i.e. n represents aconstant, or (2) Gauss-Helmert, i.e. nrepresents an observation. The resulting functional models are:f(t,CÜ,St)t = n-T + St(5.12)f(t,n,uj,6t)(t -St)-(n-T)=0(5.13)Both adjustment problems yieldthe same results. Theadvantage<strong>of</strong> Gauss-Markov is that no initial valuefor the unknown is required. In addition, Gauss-Helmert needs initial values. To determine the unknownrotation time T, several measurements were carried out. They cover a total time <strong>of</strong> one minute, ten minutes<strong>and</strong> one hour. Table 5.8 gives an overview <strong>of</strong> both the measurements <strong>and</strong> the results <strong>of</strong> the adjustments.Table 5.8: Results <strong>of</strong> both types <strong>of</strong> adjustment for deriving the rotation time T <strong>and</strong> the time <strong>of</strong>fset St indirectly. Aprecision for the rotation time T '<strong>of</strong> aT « 1 ms can be seen.12.5 rps 25 rps 33 rpsn t[s] n t[s] n t[s]730 59.012 1422 59.710 1909 58.343728 58.819 1426 59.854 1909 58.278lmin 728 58.874 1426 59.694 1909 58.311726 58.673 1426 59.837 1911 58.391727 58.722 1426 59.759 1913 58.4237433 599.433 14872 599.672 19619 599.3687435 599.552 14866 599.369 19616 599.18110min 7435 599.541 14879 599.934 19617 599.1807433 599.361 14868 599.523 19617 599.2127439 599.912 14947 602.704 19613 599.06844688 3603.738 89382 3603.859 117975 3603.51044693 3604.002 89391 3604.370 117973 3603.44760min 44691 3603.802 89382 3604.538 117971 3603.52644691 3603.980 89408 3605.488 119940 3663.51744691 3603.898 89382 3603.914 117973 3603.478T[s] 0.080638 0.0

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