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Calculus II, Worksheet 2 Name: Please answer the following ...

Calculus II, Worksheet 2 Name: Please answer the following ...

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<strong>Calculus</strong> <strong>II</strong>, <strong>Worksheet</strong> 2<strong>Name</strong>:<strong>Please</strong> <strong>answer</strong> <strong>the</strong> <strong>following</strong> questions in <strong>the</strong> spaces provided, or on your own paper. You mayuse your textbook, but do not consult any o<strong>the</strong>r sources or with each o<strong>the</strong>r. This worksheetis due on July 30th. As you have plenty of time for this, you will not receive credit forillegible or excessively disorganized work.1. (20 pts) It is often difficult to find exact values for series, but with sufficient ingenuity,∞∑ (−1) k+1methods can be found. This exercise outlines one way to show that= ln 2.kn∑ 1(a) Define <strong>the</strong> sequence a n = − ln n. Use <strong>the</strong> Bounded Monotone Convergencekk=1Theorem to show that γ = lim a n exists. You don’t need to find its value, but itn→∞so happens that γ ≈∫ 0.57722.ndx(Hint: Note ln n =1 x . Interpret a n geometrically, similarly to <strong>the</strong> picture in#30 of Section 10.2)k=1n∑ (−1) k+1n∑ 1(b) Define s n =. Define h n =kk . Show that h n = h 2n − s 2n .k=1k=1(Hint: Start with <strong>the</strong> right-hand side and simplify to <strong>the</strong> left-hand side.)


(c) Note that algebraic manipulation of (b) givess 2n = (h 2n − ln(2n)) − (h n − ln n) + ln(2n) − ln n.Using <strong>the</strong> result from (a), show that(Hint: What is limn→∞s 2n ?)∞∑ (−1) k+1k=1k= ln 2.

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