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According to Aufbau principle electrons after 4d, if available will be filled in–<br />
(a) 5f (b) 5p (c) 3d (d) None of these<br />
9 Cr +3 dk bySDVªWkfud foU;kl gksxk&<br />
(a) 1s 2 , 2s 2 p 6 , 3s 2 p 5 , d 4 (b) 1s 2 , 2s 2 p 6 , 3s 2 p 6 d 3<br />
(c) 1s 2 , 2s 2 p 6 , 3s 2 p 6 , d 7 (d) buesa ls dksbZ ugha<br />
Electronic configuration of Cr +3 will be–<br />
(a) 1s 2 , 2s 2 p 6 , 3s 2 p 5 , d 4 (b) 1s 2 , 2s 2 p 6 , 3s 2 p 6 d 3<br />
(c) 1s 2 , 2s 2 p 6 , 3s 2 p 6 , d 7 (d) None of these<br />
10 Cl – dk bySDVªWkfud foU;kl gksxk&<br />
(a) 1s 2 , 2s 2 p 6 , 3s 2 p 5 (b) 1s 2 , 2s 2 p 6 , 3s 2 p 6 d 1<br />
(c) 1s 2 , 2s 2 p 6 , 3s 2 p 6 (d) buesa ls dksbZ ugha<br />
Electronic configuration of Cl –3 will be–<br />
(a) 1s 2 , 2s 2 p 6 , 3s 2 p 5 (b) 1s 2 , 2s 2 p 6 , 3s 2 p 6 d 1<br />
(c) 1s 2 , 2s 2 p 6 , 3s 2 p 6 (d) None of these<br />
11 Na + rFkk Ne rRo ds e/; leku gksaxh&<br />
(a) bysDVªku dh la[;k (b) izksVku dh la[;k<br />
(c) U;wVªku dh la[;k (d) ijek.kq nzO;eku<br />
Na + ion and Ne element will have same–<br />
(a) Number of electrons (b) Number of protones<br />
(c) Number of neutrons (d) Atomic mass<br />
12 ;fn fdlh ijek.kq esa n=3 rFkk l=2 gS] rc m ds fy;s laHkkfor eku gksaxs&<br />
(a) 2 – 1 = 1 & 3 + 2 = 5 (b) +2, +1, ±0, –1, –2<br />
(c) +½ and –½ (d) buesa ls dksbZ ugh<br />
The value an atom is n=3 and l=2, then value of m will be–<br />
(a) 2 – 1 = 1 & 3 + 2 = 5 (b) +2, +1, ±0, –1, –2<br />
(c) +½ and –½ (d) None of these<br />
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