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18 Cr rRo dk bySDVªkfud foU;kl ------------------------------------ gksxkA<br />
24<br />
The electronic configuration of element 24 Cr will be ........................<br />
19 Ni dk bySDVªkfud foU;kl gksxk --------------------------------<br />
28<br />
The electronic configuration of 28 Ni will be ............<br />
20 gq.M dk vf/kdre cgqyrk fu;e gS ----------------<br />
The hund’s rule of maximum multiplicity is ................<br />
21 fdlh d{kk n esa bySDVªkuksa dh la[;k vf/kdre 2n 2 gksus dh O;oLFkk ------<br />
oSKkfud us nh FkhA<br />
........................ scientist had given maximum number of electrons in any orbital<br />
n according to 2n 2<br />
22 Cu dk bySDVªkfud foU;kl -------------------------------------- gksxkA<br />
29<br />
The electronic configuration of 29 Cu will be .....................................<br />
,d ,d 'kCn@okD; 'kCn@okD; esa esa mRrj mRrj nhft;sA<br />
nhft;sA<br />
,d 'kCn@okD; esa mRrj nhft;sA Answer in one word / sentence.<br />
23 bySDVªku dh [kkst fdlus dh Fkh\<br />
Who discovered electron?<br />
24 bySDVªku dk nzO;eku gS \<br />
The mass of electron is?<br />
25 Mh&czkxyh lehdj.k gS\<br />
de–Broglie equation is?<br />
26 fnxa'kh DokUVe la[;k dks n'kkZrs gSa\<br />
Azimuthal quantum number is denoted by?<br />
27 gkbtu oxZ ds vfuf'prrk ds fl)kUr dk lw= gS\<br />
The formula for Heisenberg’s uncertainity principle is?<br />
28 3d d{kd ls iwoZ bySDVªku 4s d{kd esa izos'k djus dk dkj.k gS \<br />
The reason for entering electrons into 4s before going into 3d orbital is?<br />
29 6 C12 dk bySDVªkfud foU;kl gksxk\<br />
The electronic configuration for 6 C 12 will be ?<br />
11