Solution - Career Point

SOLUTION FOR MOCK TESTIIT-JEE (PAPER - I)1.[A]CHEMISTRYO||C 6 H 5 – CH 3 CC || OC||OCH 3C –C 6 H 5||O2.[B] A ⎯⎯⎯⎯→B3.[D]4.[C]⎯ OzonolysisOrientation foraldol condensationNH2OH,H2SO⎯⎯⎯⎯ ⎯⎯ →∆⎯4oximeformation followed by Beckmann rearrangement.C –NH–CH 3O ||N-methyl benzamideSo, B isA isandCCH | = O3CCH | = C3 CH |3K Cr2O7,H(CH 3 ) 3 CCH 2 CH 2 OH ⎯⎯⎯2 ⎯ → +H O, HeatSOCl ⎯⎯→⎯ 2(CH 3 ) 3 CC H 2 CH 2 N(CH 3 ) 2(D)2(CH 3 ) 3 CCH(A)2(CH 3 ) 3 CCH 2 COCl(B)(CH 3 ) 2 NHCOOHO(CH 3 ) 3 CCH2C || N(CH 3 ) 2(C)LiAlH4,ether← ⎯⎯⎯ ⎯⎯H OAttack of nucleophile is a rate determining stepO OF 3 CIOII2CH 35.[A]6.[D]7.[B]8.[A]I is more electron deficient and facilitates a fasterattack.As water introduces, water dissolves HCl(g) and apress drop is produced Liquid level in thecapillary rises.The energy of AOs depends on the(n + l) values n + l value of (n – 1) d = n + 1 ;n + l value of ns = n(n + l) value of (n + 1)d = n + 3 ; n + l value of nf= (n + 3)But due to lower value of principle quantum no.energy of nf < (n + 1) d∴ energy of (n + 2) s < nf.A, B and C are magnesium ,aluminium andsilicon. Magnesium form ionic oxide, MgO ;Aluminium forms amphoteric oxide ,Al 2 O 3 andsilicon forms a giant molecule SiO 2 .9.[ B,C,D] Due to resonance cyclohexatriene cation isaromatic which causes it's stability.10.[ A,B,D] Catalyst lower the activation energy offorward reaction & backward direction keepingthe same enthalpy of reaction.11.[ A,B,C] Greater the value of (IE – ∆ eg H) greater is theelectronegativity E.N. ofP = (1680 + 340)/(4.18) (125) ~ – 412.[A,B,C] H = E + PV⎛ dH ⎞ ⎛ dE ⎞⎜ ⎟⎠ = ⎜ ⎟⎠⎝ dP ⎝ dPT⎛ dH ⎞For liquid, ⎜ ⎟⎠⎝ dPTT⎛ dV ⎞+ P ⎜ ⎟⎠⎝ dP⎛ dE ⎞= ⎜ ⎟⎠⎝ dVTT+ V⎛ dV ⎞⎜ ⎟⎠⎝ dPT+⎛ dV ⎞P ⎜ ⎟⎠⎝ dP⎛ dV ⎞For incompressible liquid, ⎜ ⎟⎠ – ~ 0.⎝ dP⎛ dH ⎞∴ ⎜ ⎟⎠⎝ dPT~ – VTT+ VXtraEdge for IIT-JEE 87APRIL 2010