SECTION – IVInteger answer typeThis section contains 8 questions. The answer to each ofthe questions is a single-digit integer, ranging from 0 to9. The appropriate bubbles below the respectivequestion numbers in the ORS have to be darkened. Forexample, if the correct answers to question numbers X,Y, Z and W (say) are 6, 0, 9 and 2, respectively, thenthe correct darkening of bubbles will look like thefollowing :X Y Z W0123456789012345678912. 3 ampere current was passed through an aqueoussolution of an unknown salt of Pd for one hour,2.977g of Pd n+ was deposited at cathode. Find n.(At. wt. of Pd = 106.4)13. Consider the following reaction sequenceCa(OH)⎯⎯⎯∆⎯ 201234567890123456789NH NH2KOH / glycolO / H2O23O ⎯⎯⎯⎯ →W ⎯⎯⎯→X→ YC 5H COOOH6⎯⎯⎯⎯⎯→ZHow many carbons are present in the final product Z?14. For the reaction in the plant cells6CO 2 (g) + 12H 2 O (l) → C 6 H 12 O 6 (s) + 6O 2 (g)+ 6H 2 O(l) ∆ r Gº = 3000 kJ/mol3–ATP → ADP + PO 4 ∆ r Gº = – 30 kJ/molGlucose is stored in the plant cell as starch,(C 6 H 10 O 5 ) n . To produce 162 g of starch how manymoles of ATP are minimum required ? Give youranswer after divide actual answer by 100.15. The relative lowering of the vapour pressure of anaqueous solution containing a non-volatile solute is0.0125. What is the molality of the solution. Giveyour answer after multiplying actual answer by 10.16. A polyvalent metal weighing 0.1g and having atomicweight 51 reacted with dil. H 2 SO 4 to give 43.9 ml ofhydrogen at STP. The solution containing the metalin this lower oxidation state(X), was found to require58.8 mL of 0.1 N KMnO 4 for complete oxidation.What is the higher oxidation state (Y) of the metal ?17. The stopcock, connecting the two bulbs of volumes5 litres and 10 litres containing an ideal gas at 9 atmand 6 atm respectively, is opened. What is the finalpressure (in atm) in the two bulbs if the temperatureremained the same ?18. Sum of lone pairs present in XeOF 4 and XeO 3 is ….. .19. Total number of isomers are possible in [Co(en) 2 Cl 2 ]and [Co(C 2 O 4 ) 2 (NH 3 ) 2 ] – is.MATHEMATICSSECTION – IStraight Objective TypeThis section contains 4 multiple choice questions. Eachquestion has 4 choices (A), (B), (C) and (D), out ofwhich ONLY ONE is correct.n41. Let ∑ r = f (n) , thenr=1∑ ( 2r −1)r=1is equal to(A) f(2n) – 16 f(n) (B) f (2n) – 7f (n)(C) f(2n – 1) – 8 f(n) (D) None of these⎛ α α ⎞2. If f r (α) = ⎜cos + isin ⎟ ×2 2⎝ r r ⎠thenn →nn⎛ 2α2α⎞ ⎛ α α ⎞⎜cos + isin ⎟ …. ⎜cos+ isin ⎟22⎝ r r ⎠ ⎝ r r ⎠lim f (π) equals∞(A) –1 (B) 1(C) – i(D) i3. If α, β, γ, δ are four complex numbers such that δγ isreal and αδ – βγ ≠ 0, then z =t ∈ R represents a(A) circle(C) ellipse4(B) parabola(D) straight lineα + βt,γ + δt4. The inflection points on the graph of functionxy =∫( t −1)(t− 2) 2 dt are0(A) x = –1 (B) x = 3/2(C) x = 4/3 (D) x =1SECTION – IIMultiple Correct Answers TypeThis section contains 5 multiple correct answer(s) typequestions. Each question has 4 choices (A), (B), (C) and(D), out of which ONE OR MORE is/are correct.XtraEdge for IIT-JEE 64APRIL 2010
5. If A and B are two invertible matrices of the same order,then adj (AB) is equal to -(A) adj (B) adj (A) (B) |B| |A| B –1 A –1(C) |B| |A| A –1 B –1 (D) |A| |B| (AB) –1⎡ cosα6. If A (α , β) =⎢⎢− sin α⎢⎣0sin αcosα00 ⎤0⎥⎥, then⎥⎦βe(A) A (α, β)′ = A (– α, β)(B) A (α, β) –1 = A (–α, –β)(C) Adj (A (α, β)) = e –β A (–α, –β)(D) A (α, β)′ = A (α, – β)7. For a positive integer n, if the expansion ofn⎛ 5 4 ⎞⎜ + x ⎟ has a term independent of x, then n can2⎝ x ⎠be(A) 18 (B) 21(C) 27 (D) 998. If k is odd then k C r is maximum for r equal to(A) 21 (k – 1) (B) 21 (k + 1)(C)k – 19. Let a n = ( 111...1) , then14243n times(A) a 912 is not prime(C) a 480 is not prime(D) k(B) a 951 is not prime(D) a 91 is not primeSECTION – IIIMatrix - Match TypeThis section contains 2 questions. Each questioncontains statements given in two columns, which haveto be matched. The statements in Column I are labeledA, B, C and D, while the statements in Column II arelabeled p, q, r, s and t. any given statement in Column Ican have correct matching with ONE OR MOREstatements (s) in column II. The appropriate bubbledcorresponding to the answers to these questions have tobe darkened as illustrated in the following example :If the correct matches are A – p, s and t; B – q and r;C – p and q; and D – s and t; then the correctdarkening of bubbles will look like the following.p q r s tABCDppqqrrrsstt10. Match the followingColumn-1Column-IIEquationGeneral <strong>Solution</strong>s(A) 2 sin θ – 3 = 0 (p) nπ + (–1) n π3(B) 2 sin 2θ + 3π(q) 2nπ – 3= 2 sin θ + 2 3 cos θπ(C) sin 2θ + cos 2θ + 4 sin θ (r) 2nπ + 3= 1 + 4 cos θ(D) cos 2 θ = 41(s) nπ – 4π(t) nπ + 4π11. Match the following :Column- I(A) If three unequal numbers a, b, care in A.P. and b – c,c – b, a are in G.P., then3 3 3a + b + cis equal to3abc(B) Let x be the arithmetic meanand y,z be two geometricmeans between any twopositive numbers, theny3 3+ zis equal toxyz(C) If a, b, c be three positivenumber which form threesuccessive terms of a G.P. andc> 4b –3a, then the commonratio of the G.P. can be equal to(D)⎪⎧lim tan ⎨n→∞⎪⎩⎪is equal ton∑r=1tan−1⎛ 1⎜⎝ 2r2⎞⎪⎫⎟ ⎬⎠ ⎭SECTION – IVInteger answer typeColumn- II(p) 1/3(q) 1(r) 2(s) 3(t) 1/2This section contains 8 questions. The answer to each ofthe questions is a single-digit integer, ranging from 0 to9. The appropriate bubbles below the respectivequestion numbers in the ORS have to be darkened. Forexample, if the correct answers to question numbers X,Y, Z and W (say) are 6, 0, 9 and 2, respectively, thenthe correct darkening of bubbles will look like thefollowing :XtraEdge for IIT-JEE 65APRIL 2010
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Volume - 5 Issue - 10April, 2010 (M
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Volume-5 Issue-10April, 2010 (Month
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Hospital in Parel and ApolloHospita
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KNOW IIT-JEEBy Previous Exam Questi
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CHEMISTRY6. From the following data
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(ii)OHH + CH 3OH⊕PorClPClClOCH 3O
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16.[A]NH 2⎯ 0−5°C+ NaNO 2 + 2H
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11.[B]→ →∴ α & β are two mu
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1/ 21 -2∫2 x 2 dx⇒⇒01 2 - 3 2
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