Solution - Career Point

15. What would be the structure of F if H gives negativeidoform test ?O||(A) (CH 3 ) 2 CHCH2COCHCH(CH3)2|CH3CH| 3O||(B) CH 3 (CH 2 ) 3 CH 2 COCHCH CH(CH 3 ) 2|CH3O||(C) CH 3 CH 2 CH 2 CHCOCHCH2CH 2 CH 3| |CH3CH3O||(D) CH 3 CH 2 CHCH2COCH 2CHCH2CH 3||CH3CH3Paragraph # 2 (Ques. 16 to 18)To the 100 ml of 10 –2 (M) aqueous solution of HCl0.1 (M) HA (K a = 10 –2 ) is added in such a way sothat the final pH of the solution become 1.7Given log 2 = 0.316. What was the pH of 10 –2 (M) aqueous solution ofHCl ?(A) pH = 2 (B) pH < 2(C) pH > 2 (D) pH = 1.717. What volume of 0.1 (M) HA was required to add inaqueous HCl to reduced the final pH equal to 1.7 ?(A) 175 ml(B) 100 ml(C) 10 4 ml(D) 75 ml18. Which of the following solution is isohydric with0.1(M) aqueous solution of HA ?(A) 0.01(M) aqueous solution of HB (K a = 10 –2 )(B) 0.01(M) aqueous solution of HC (K a =2×10 –1 )(C) 0.01(M) aqueous solution of HNO 3(D) 1(M) aqueous solution of HD (K a = 10 –3 )SECTION – IVMatrix – Match TypeThis section contains 2 questions. Each questioncontains statements given in two columns, which haveto be matched. The statements in Column I are labeledA, B, C and D, while the statements in Column II arelabeled p, q, r, s and t. any given statement in Column Ican have correct matching with ONE OR MOREstatements (s) in column II. The appropriate bubbledcorresponding to the answers to these questions have tobe darkened as illustrated in the following example :If the correct matches are A – p, s and t; B – q and r;C – p and q; and D – s and t; then the correctdarkening of bubbles will look like the following.p q r s tABCD19. Match the following :Column-I(A)CH 3 CH 2 CH 2 NH 2pp(B) CH 3 CH 2 NHCH 3(C)CH 3 –N − CH 3|CH 3qqrrrssttColumn-II(p)Treatment of NaNO 2 , HClgives N-nitroso compound(q)Treatment of NaNO 2 , HClgives diazonium chloride(r) Treatment ofCH 3 I (excess)followed by AgOH;heat gives out alkene(D) NH 2(s) Treatment of HCl,heat gives dealkylation(t) Treatment with CHCl 3 /Alc.KOH gives isocyanide20. Match the following :Column-IColumn-II−OH ,Br2 (1 eq)(A) C 6 H 5 CH 2 CHO⎯⎯⎯⎯⎯→(p) Redox products(B) CH 3 CHO(C) CH 3 CH 2 –CH = OOH⎯⎯ − → (q) Enantiomeric(0−5ºC)products−OH ⎯⎯→(25ºC)Conc. OH→ −(D) CH 3 – CH – C – H|CH 3 O | |⎯⎯⎯⎯(r)K D⎯ αKαH⎯ → < 1(Primaryisotopic effect)(s) Diastereomericproducts(t) DisproportionationMATHEMATICSSECTION – IStraight Objective TypeThis section contains 8 multiple choice questions. Eachquestion has 4 choices (A), (B), (C) and (D), out ofwhich ONLY ONE is correct.XtraEdge for IIT-JEE 55APRIL 2010