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The Continuum Hypothesis - Logic at Harvard

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3.3 <strong>The</strong> CaseNevertheless, if one supplements large cardinal axioms then Ω-complete theoriesare forthcoming. This is the centerpiece of the case against CH.<strong>The</strong>orem 3.12 (Woodin). Assume th<strong>at</strong> there is a proper class of Woodincardinals and th<strong>at</strong> the Strong Ω Conjecture holds.(1) <strong>The</strong>re is an axiom A such th<strong>at</strong>(i) ZFC+A is Ω-s<strong>at</strong>isfiable and(ii) ZFC+A is Ω-complete for the structure H(ω 2 ).(2) Any such axiom A has the fe<strong>at</strong>ure th<strong>at</strong>ZFC+A |= Ω “H(ω 2 ) |= ¬CH”.Let us rephrase this as follows: For each A s<strong>at</strong>isfying (1), letT A = {ϕ | ZFC+A |= Ω “H(ω 2 ) |= ¬ϕ”}.<strong>The</strong> theorem says th<strong>at</strong> if there is a proper class of Woodin cardinals and theΩ Conjecture holds, then there are (non-trivial) Ω-complete theories T A ofH(ω 2 ) and all such theories contain ¬CH.It is n<strong>at</strong>ural to ask whether there is gre<strong>at</strong>er agreement among the Ω-complete theories T A . Ideally, there would be just one. A recent result(building on <strong>The</strong>orem 5.5) shows th<strong>at</strong> if there is one such theory then thereare many such theories.<strong>The</strong>orem 3.13 (Koellner and Woodin). Assume th<strong>at</strong> there is a proper classof Woodin cardinals. Suppose th<strong>at</strong> A is an axiom such th<strong>at</strong>(i) ZFC+A is Ω-s<strong>at</strong>isfiable and(ii) ZFC+A is Ω-complete for the structure H(ω 2 ).<strong>The</strong>n there is an axiom B such th<strong>at</strong>(i ′ ) ZFC+B is Ω-s<strong>at</strong>isfiable and(ii ′ ) ZFC+B is Ω-complete for the structure H(ω 2 )18

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