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Copulas: a Review and Recent Developments (2007)

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asymptotic result using u = F (x) <strong>and</strong>v = G(y) <strong>and</strong> relation C Xr:n;Y s:n= C Ur:n;V s:n:H Xr:n;Y s:n(x; y) ¼¯r;n¡r+1¡F (x)¢+ ¯s;n¡s+1¡G(y)¢¡ 1+© ½³© ¡1¡ 1 ¡ ¯r;n¡r+1¡F (x)¢¢; ©¡1 ¡ 1 ¡ ¯s;n¡s+1¡G(y)¢¢´:(5)It is worth to note that the copula of (U r:n ;V s:n ) is di®erent than the copula of(R u ;R v ).Now, we give an example of application of (5).Example. Consider the bivariate normal distribution with zero mean, unit variances<strong>and</strong> correlation coe±cient ¡0:5. Let us calculate P (X 9:10 · x; Y 10:10 · y). For x =1:5<strong>and</strong> y =1:8, we have F (x) =0:93319, G(y) =0:96406 <strong>and</strong> C ¡ F (x);G(y) ¢ =0:897319.By relation (4), the exact value of P (X 9:10 · x; Y 10:10 · y) isP (X 9:10 · x; Y 10:10 · y) =P (U 9:10 · u; V 10:10 · v)=P (U 9:10 · F (x);V 10:10 · G(y))=10 £ C ¡ F (x);G(y) ¢ 9£ ¡ ¢¤ ¡ ¢ 10G(y) ¡ C F (x);G(y) + C F (x);G(y)=0:5902:For our data we calculate½ ==C ¡ F (x);G(y) ¢ ¡ F (x)G(y)pF (x)G(y)(1 ¡ G(y))(1 ¡ F (x))0:897319 ¡ 0:93319 £ 0:96406p0:93319 £ 0:96406(1 ¡ 0:93319)(1 ¡ 0:96406)= ¡0:0504337<strong>and</strong> using (5) we obtain³H Xr:n ;Y s:n(x; y) ¼ © ½ © ¡1 ¡¯9;10¡9+1 (F (x)) ¢ ; © ¡1 ¡¯10;10¡10+1 ¢´(G(y))´= © ½³© ¡1 (0:85942); © ¡1 (0:69356)´=0:85942 + 0:69356 ¡ 1+© ½³© ¡1 (1 ¡ 0:85942); © ¡1 (1 ¡ 0:69356)=0:5922:As one can see, the asymptotic copula is easy to calculate <strong>and</strong> gives a good approximationeven when we use a small sample size.3.2 <strong>Copulas</strong> with multivariate marginalsSklar's theorem holds whenever the dimension n ¸ 2, so most of the results could beused. But, since it is much more convenient to work in dimension n = 2, practitioners22

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