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Symbiotic Fungi: Principles and Practice (Soil Biology)

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288 X.H. He et al.<br />

Table 17.1 Experimental design for two-way N transfer between N2-fixing <strong>and</strong> non-N2-fixing plants grown in two-chambered pots. Enriched 15 N compounds are supplied to the growth medium<br />

or the leaves of the N-donor plant. Time period of 15 N labeling (days to months) depends on<br />

physiological activity of plants species <strong>and</strong> experimental purposes<br />

Plant pair name Plant status Treatment<br />

status<br />

N-donor N-receiver Myc Nod<br />

Non-nodulated/non-mycorrhizal pairs N2-fixing Non-N2-fixing<br />

Non-N2-fixing N2-fixing Nodulated/non-mycorrhizal pairs N2-fixing Non-N2-fixing +<br />

Non-N2-fixing N2-fixing +<br />

Non-nodulated/mycorrhizal pairs N2-fixing Non-N2-fixing +<br />

Non-N2-fixing N2-fixing +<br />

Nodulated/mycorrhizal pairs N2-fixing Non-N2-fixing + +<br />

Non-N2-fixing N2-fixing + +<br />

Myc Mycorrhizal status; Nod Nodulation status<br />

17.3.1 Quantification of Nitrogen Transfer Between Plants<br />

Nitrogen transfer has been quantified in three ways: percentage of Ntransfer<br />

(% Ntransfer, (17.1–17.3)); amount of N transferred (mg plant 1 , (17.4); <strong>and</strong> percentage<br />

of NDFT (% NDFT, N in the N-receiver derived from transfer, (17.5) <strong>and</strong><br />

(17.6)) (Ledgard et al. 1985; Giller et al. 1991; Johansen <strong>and</strong> Jensen 1996).<br />

%Ntransfer ¼ 15 Ncontentreceiver 100=ð 15 Ncontentreceiverþ 15 NcontentdonorÞ ð17:1Þ<br />

where<br />

15 Ncontentplant ¼ atom% 15 N excessplant total Nplant=atom% 15 N excesslabeled N<br />

<strong>and</strong><br />

atom% 15 N excessplant ¼ atom% 15 Nplant after labeling<br />

ð17:2Þ<br />

atom% 15 Nplant background<br />

ð17:3Þ<br />

Ntransfer ¼ %Ntransfer total Ndonor=ð100 % NtransferÞ ð17:4Þ<br />

% NDFT ¼ Ntransfer 100=total Nreceiver ð17:5Þ<br />

In addition, % NDFT values can also be calculated as follows (Tomm et al. 1994):<br />

%NDFT ¼ðatom % 15 N excessreceiver=atom % 15 N excessdonorÞ 100 ð17:6Þ<br />

Equations (17.5) <strong>and</strong> (17.6) are equal if the 0.3663% 15 N of atmospheric N2 is<br />

subtracted from the measured atom % 15 N in (17.5).

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