Colligative Properties PowerPoint

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Calculating Heat Exchange• c = specific heat capacity of thesubstance.• ΔT = the change in temperature of thesubstance.• Example: 50.0g of water warms by4.6°C as a salt dissolves in it.• How much heat has been released?
Calculating Heat Exchange• The specific heat of water is 4.18 J/g°C.• In other words, it takes 4.18 J of energyto make 1 g of water warm up by 1°C.• Calculating the heat change:• ΔH = 50.0g(4.18 J/g°C)4.6°C• = 960 J of heat.
Page 1 and 2: Colligative PropertiesThe Physical
Page 3 and 4: Molality• Molality measures the m
Page 5 and 6: Molality• Example:What is the mol
Page 7 and 8: Molality• Determine the molality
Page 9 and 10: Molality• Convert grams of solven
Page 11 and 12: Changes in Vapor Pressure• Animat
Page 13 and 14: Solution Vapor Pressure• But what
Page 15 and 16: Boiling Point Elevation• There is
Page 17 and 18: Freezing Solutions• Solutions typ
Page 19 and 20: Practical Applications• Antifreez
Page 21 and 22: The van’t Hoff Factor• We have
Page 23 and 24: The van’t Hoff Factor• ΔT b =
Page 25 and 26: Heat of Solution• Most materials
Page 27 and 28: Endothermic Heat of SolutionNH 4 Cl
Page 29 and 30: Exothermic Heat of SolutionCaCl 2 (
Page 31: Calculating Heat Exchange• A simp

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