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Normed versus topological groups: Dichotomy and duality

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56 N. H. Bingham <strong>and</strong> A. J. OstaszewskiTheorem 3.39. A Darboux-normed group is a <strong>topological</strong> group.Proof. Fix x. By Theorem 3.4 we must show that γ x is continuous at e. By Darboux’stheorem (Th. 11.22), it suffices to show that γ x is bounded in some ball B 1/n (e). Supposenot: then there is w n ∈ B ε(n) (e) with ε(n) = 2 −n <strong>and</strong>‖γ x (w n )‖ ≥ n.Thus w n is null. We may solve the equation w n = z n−1 zn−1by taking z 0 = e <strong>and</strong> inductivelyIndeed z n is null, sincez n = w −1nApplying the triangle inequality twice,as ‖z n ‖ ≤ 1. So for all n, we havez n−1 = wn−1 wn−1 −1 ...w−1 1 .‖z n ‖ ≤ 2 −(1+2+...+n) → 0.d(xz n , xz m ) ≤ d(xz n , e) + d(e, xz m )= ‖xz n ‖ + ‖xz m ‖ ≤ 2(‖x‖ + 1),for n = 1, 2, ... with z n null,‖xw n+1 x −1 ‖ = ‖x n z n z −1n−1 x−1 ‖ ≤ d(x n z n , x n−1 z n−1 ) ≤ 2(‖x‖ + 1).This contradicts the unboundedness of ‖γ x (w n )‖.Two more results on the effects of automatic continuity both come from the Banach-Mehdi Theorem on Homomorphism Continuity (Th. 11.11) or its generalization, theSouslin Graph Theorem (Th. 11.12), both of which belong properly to a later circle ofideas considered in Section 11 <strong>and</strong> employ the Baire property.Theorem 3.40. For X a <strong>topological</strong>ly complete, separable, normed group, if each automorphismγ g (x) = gxg −1 is Baire, then X is a <strong>topological</strong> group.Proof. We work under d R . Fix g. As X is separable <strong>and</strong> γ g Baire, γ g is Baire-continuous(Th. 11.8) <strong>and</strong> so by the Banach-Mehdi Theorem (Th. 11.11) is continuous. As g isarbitrary, we deduce from Th. 3.4 that X is <strong>topological</strong>.Remark. Here by assumption (X, d R ) is a Polish space. In such a context, ab<strong>and</strong>oningthe Axiom of Choice, one may consistently assume that all functions are Baire <strong>and</strong> sothat all <strong>topological</strong>ly complete separable normed <strong>groups</strong> are <strong>topological</strong>. (See the modelsof set theory due to Solovay [So] <strong>and</strong> to Shelah [She].)Theorem 3.41 (On Borel/analytic inversion). For X a <strong>topological</strong>ly complete, separablenormed group, if the inversion x → x −1 regarded as a map from (X, d R ) to (X, d R ) is aBorel function, or more generally has an analytic graph, then X is a <strong>topological</strong> group.

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