12.07.2015 Views

Normed versus topological groups: Dichotomy and duality

Normed versus topological groups: Dichotomy and duality

Normed versus topological groups: Dichotomy and duality

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

28 N. H. Bingham <strong>and</strong> A. J. OstaszewskiLemma 3.2. If inversion is right-to-right continuous, thenx → R a iff a −1 x → R e.Proof. For x → R a, we have d R (e, a −1 x) = d R (x −1 , a −1 ) → 0, assuming continuity.Conversely, for a −1 x → R e we have d R (a −1 x, e) → 0, i.e. d R (x −1 , a −1 ) → 0. So sinceinversion is assumed to be right-continuous <strong>and</strong> (x −1 ) −1 = x, etc, we have d R (x, a) → 0.We now exp<strong>and</strong> this.Theorem 3.3. The following are equivalent:(i) inversion is right-to-right continuous,(ii) left-open sets are right-open,(iii) for each g the conjugacy γ g is right-to-right continuous at e, i.e. for every ε > 0there is δ > 0 such thatgB(δ)g −1 ⊂ B(ε),(iv) left-shifts are right-continuous.Proof. We show that (i)⇐⇒(ii)⇐⇒(iii)⇐⇒(iv).Assume (i). For any a <strong>and</strong> any ε > 0, by continuity of inversion at a, there is δ > 0 suchthat, for x with d R (x, a) < δ, we have d R (x −1 , a −1 ) < ε, i.e. d L (x, a) < ε. ThusB(δ)a = B R (a, δ) ⊂ B L (a, ε) = aB(ε),(incl)i.e. left-open sets are right-open, giving (ii). For the converse, we just reverse the lastargument. Let ε > 0. As a ∈ B L (a, ε) <strong>and</strong> B L (a, ε) is left open, it is right open <strong>and</strong> sothere is δ > 0 such thatB R (a, δ) ⊂ B L (a, ε).Thus for x with d R (x, a) < δ, we have d L (x, a) < ε, i.e. d R (x −1 , a −1 ) < ε, i.e. inversionis right-to-right continuous, giving (i).To show that (ii)⇐⇒(iii) note that the inclusion (incl) is equivalent toi.e. toa −1 B(δ)a ⊂ B(ε),γa−1 [B(δ)] ⊂ B(ε),that is, to the assertion that γ a (x) is continuous at x = e (<strong>and</strong> so continuous, by Lemma3.1). The property (iv) is equivalent to (iii) since the right-shift is right-continuous <strong>and</strong>γ a (x)a = λ a (x) is equivalent to γ a (x) = λ a (x)a −1 .We saw in the Birkhoff-Kakutani Theorem (Th. 2.19) that metrizable <strong>topological</strong><strong>groups</strong> are normable (equivalently, have a right-invariant metric); we now formulate aconverse, showing when the right-invariant metric derived from a group-norm equips itsgroup with a <strong>topological</strong> group structure. As this is a characterization of metric <strong>topological</strong><strong>groups</strong>, we will henceforth refer to them synonymously as normed <strong>topological</strong> <strong>groups</strong>.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!