22 N. H. Bingham <strong>and</strong> A. J. OstaszewskiProof. By definition, for t with ‖t‖ ≤ ε, we have‖γ‖ ε = sup ˆdT ‖t‖≤ε (γ(t), t) ≤ sup ‖t‖≤ε [ ˆd T (γ(t), e) + ˆd T (e, t)] ≤ sup ‖t‖≤ε ‖γ(t)‖ T + ε,‖γ(t)‖ T = ˆd T (γ(t), e) ≤ ˆd T (γ(t), t) + ˆd T (t, e)≤ ‖t‖ + ‖γ‖ ε ≤ ε + ‖γ‖ ε .Theorem 2.18 (Invariance of Norm Theorem – for (b) cf. [Klee]). (a) The group-normis abelian (<strong>and</strong> the metric is bi-invariant) ifffor all x, y, a, b, or equivalently,‖xy(ab) −1 ‖ ≤ ‖xa −1 ‖ + ‖yb −1 ‖,‖uabv‖ ≤ ‖uv‖ + ‖ab‖,for all x, y, u, v.(b) Hence a metric d on the group X is bi-invariant iff the Klee property holds:d(ab, xy) ≤ d(a, x) + d(b, y).(Klee)In particular, this holds if the group X is itself abelian.(c) The group-norm is abelian iff the norm is preserved under conjugacy (inner automorphisms).Proof. (a) If the group-norm is abelian, then by the triangle inequality‖xyb −1 · a −1 ‖ = ‖a −1 xyb −1 ‖≤ ‖a −1 x‖ + ‖yb −1 ‖.For the converse we demonstrate bi-invariance in the form ‖ba −1 ‖ = ‖a −1 b‖. In factit suffices to show that ‖yx −1 ‖ ≤ ‖x −1 y‖; for then bi-invariance follows, since takingx = a, y = b we get ‖ba −1 ‖ ≤ ‖a −1 b‖, whereas taking x = b −1 , y = a −1 we get the reverse‖a −1 b‖ ≤ ‖ba −1 ‖. As for the claim, we note that‖yx −1 ‖ ≤ ‖yx −1 yy −1 ‖ ≤ ‖yy −1 ‖ + ‖x −1 y‖ = ‖x −1 y‖.(b) Klee’s result is deduced as follows. If d is a bi-invariant metric, then ‖ · ‖ is abelian.Conversely, for d a metric, let ‖x‖ := d(e, x). Then ‖.‖ is a group-norm, asd(ee, xy) ≤ d(e, x) + d(e, y).Hence d is right-invariant <strong>and</strong> d(u, v) = ‖uv −1 ‖. Now we conclude that the group-normis abelian since‖xy(ab) −1 ‖ = d(xy, ab) ≤ d(x, a) + d(y, b) = ‖xa −1 ‖ + ‖yb −1 ‖.Hence d is also left-invariant.(c) Suppose the norm is abelian. Then for any g, by the cyclic property ‖g −1 bg‖ =‖gg −1 b‖ = ‖b‖. Conversely, if the norm is preserved under automorphism, then we havebi-invariance, since ‖ba −1 ‖ = ‖a −1 (ba −1 )a‖ = ‖a −1 b‖.
<strong>Normed</strong> <strong>groups</strong> 23Remark. Note that, taking b = v = e, we have the triangle inequality. Thus the result(a) characterizes maps ‖ · ‖ with the positivity property as group pre-norms which areabelian. In regard to conjugacy, see also the Uniformity Theorem for Conjugation (Th.12.4). We now state the following classical result.Theorem 2.19 (Normability Theorem for Groups – Birkhoff-Kakutani Theorem). LetX be a first-countable <strong>topological</strong> group <strong>and</strong> let V n be a symmetric local base at e X withV 4 n+1 ⊆ V n .Let r = ∑ ∞n=1 c n(r)2 −n be a terminating representation of the dyadic number r, <strong>and</strong> putA(r) := ∑ ∞n=1 c n(r)V n .Thenp(x) := inf{r : x ∈ A(r)}is a group-norm. If further X is locally compact <strong>and</strong> non-compact, then p may be arrangedsuch that p is unbounded on X, but bounded on compact sets.For a proof see that offered in [Ru] for Th. 1.24 (p. 18-19), which derives a metrizationof a <strong>topological</strong> vector space in the form d(x, y) = p(x − y) <strong>and</strong> makes no use of thescalar field (so note how symmetric neighbourhoods here replace the ‘balanced’ ones in a<strong>topological</strong> vector space). That proof may be rewritten verbatim with xy −1 substitutingfor the additive notation x − y (cf. Proposition 2.2).Remark. In fact, a close inspection of Kakutani’s metrizability proof in [Kak] (cf. [SeKu]§7.4) for <strong>topological</strong> <strong>groups</strong> yields the following characterization of normed <strong>groups</strong> – fordetails see [Ost-LB3].Theorem 2.19 ′ (Normability Theorem for right <strong>topological</strong> <strong>groups</strong> – Birkhoff-KakutaniTheorem). A first-countable right <strong>topological</strong> group X is a normed group iff inversion<strong>and</strong> multiplication are continuous at the identity.We close with some information concerning commutators, which arise in Theorems3.7, 6.3, 10.7 <strong>and</strong> 10.9.Definition. The right-sided <strong>and</strong> left-sided commutators are defined byAs[x, y] L : = xyx −1 y −1 .[x, y] R : = x −1 y −1 xy = [x −1 , y −1 ] L .xy = [x, y] L yx <strong>and</strong> xy = yx[x, y] R ,these express in terms of shifts the distortion arising from commuting factors, <strong>and</strong> sotheir continuity here is significant. Let [x, y] denote either a right or left commutator;
- Page 1 and 2: N. H. BINGHAM and A. J. OSTASZEWSKI
- Page 3 and 4: Normed groups 3ContentsContents . .
- Page 5 and 6: 1. IntroductionGroup-norms, which b
- Page 7 and 8: Normed groups 3Topological complete
- Page 9 and 10: Normed groups 5abelian group has se
- Page 11 and 12: Normed groups 74 (Topological permu
- Page 13 and 14: Normed groups 9The following result
- Page 15 and 16: Normed groups 11Corollary 2.4. For
- Page 17 and 18: Normed groups 13More generally, for
- Page 19 and 20: Normed groups 15definitions, our pr
- Page 21 and 22: Normed groups 17so that fg is in th
- Page 23 and 24: Normed groups 19(iii) The ¯d H -to
- Page 25: Normed groups 21so‖αβ‖ ≤
- Page 29 and 30: Normed groups 25shows that [z n , y
- Page 31 and 32: Normed groups 27Denoting this commo
- Page 33 and 34: Normed groups 29Theorem 3.4 (Equiva
- Page 35 and 36: Normed groups 31argument as again p
- Page 37 and 38: Normed groups 33(ii) For α ∈ H u
- Page 39 and 40: Normed groups 35Definition. A group
- Page 41 and 42: Normed groups 37We now give an expl
- Page 43 and 44: Normed groups 39Theorem 3.19 (Abeli
- Page 45 and 46: Normed groups 412. Further recall t
- Page 47 and 48: Normed groups 43Theorem 3.22 (Lipsc
- Page 49 and 50: Normed groups 45Proof. Z γ = G (cf
- Page 51 and 52: Normed groups 47Theorem 3.30. Let G
- Page 53 and 54: Normed groups 49Remark. On the matt
- Page 55 and 56: Normed groups 51As for the conclusi
- Page 57 and 58: Normed groups 53By (C-adm), we may
- Page 59 and 60: Normed groups 55equipped with an in
- Page 61 and 62: Normed groups 57Proof. To apply Th.
- Page 63 and 64: Normed groups 59Definition. A point
- Page 65 and 66: Normed groups 61Proposition 3.46 (M
- Page 67 and 68: Normed groups 63Thus ω δ (s) ≤
- Page 69 and 70: Normed groups 65Remark. In the penu
- Page 71 and 72: Normed groups 67The result confirms
- Page 73 and 74: Normed groups 69Proof. By the Baire
- Page 75 and 76: Normed groups 715. Generic Dichotom
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Normed groups 73Returning to the cr
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Normed groups 75Examples. Here are
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Normed groups 77cf. [Eng, 4.3.23].)
- Page 83 and 84:
Normed groups 79Remarks. 1. See [Fo
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Normed groups 81Theorem 6.1 (Catego
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Normed groups 83is continuous at th
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Normed groups 85compact. Evidently,
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Normed groups 87j ∈ ω} which enu
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Normed groups 89The result below ge
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Normed groups 91left-shift, not in
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Normed groups 93As a corollary of t
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Normed groups 953. For X a normed g
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Normed groups 97Proof. Note that‖
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Normed groups 99Taking h(x) := ‖
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Normed groups 1019. The Semigroup T
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Normed groups 103Theorem 9.5 (Semig
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Normed groups 105By the Category Em
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Normed groups 107Proof. Say f is bo
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Normed groups 109Thus G is locally
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Normed groups 111Theorem 10.10 (Bar
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Normed groups 113K-analyticity was
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Normed groups 115Theorem 11.6 (Disc
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Normed groups 117restricted to X\M
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Normed groups 119groups need not be
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Normed groups 121Proof. In the meas
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Normed groups 123Hence, as t i n
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Normed groups 125The corresponding
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Normed groups 127(t, x) ✛✻Φ T
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Normed groups 129Fix s. Since s is
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Normed groups 131Hence,‖x‖ −
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Normed groups 133converging to the
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Normed groups 135Definition. Let {
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Normed groups 137However, whilst th
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Normed groups 139embeddable, 14enab
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Normed groups 141Bibliography[AL]J.
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Normed groups 143Series 378, 2010.[
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Normed groups 145abelian groups, Ma
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Normed groups 147[Kak] S. Kakutani,
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Normed groups 149fields. I. Basic p
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Normed groups 151[So]R. M. Solovay,