104 N. H. Bingham <strong>and</strong> A. J. Ostaszewskiwhere the equations over G are soluble (compare also [Lyn1]).2. In an arbitrary group, say that a subset C is 1 2-convex if, for all x, yx, y ∈ C =⇒ √ xy ∈ C,where √ xy signifies some element z with z 2 = xy. We recall the following results.Theorem 10.1 (Eberlein-McShane Theorem, [Eb], [McSh, Cor. 10]). Let X be a 2-divisible <strong>topological</strong> group of second category. Then any 1 2-convex non-meagre Baire sethas a non-empty interior. If X is abelian <strong>and</strong> each sequence defined by x 2 n+1 = x n convergesto e X then the interior of a 1 2-convex set C is dense in C.Definition. We say that the function h : G → R is 1 2 -convex on the 1 2–convex set C if,for x, y ∈ C,with √ xy as above.h( √ xy) ≤ 1 (h(x) + h(y)) ,2Example. For G = R+ ∗ the function h(x) = x is 1 2-convex on G, since2xy ≤ x 2 + y 2 .Theorem 10.2 (Convex Minorant Theorem, [McSh]). Let X be 2-divisible abelian <strong>topological</strong>group. Let f <strong>and</strong> g be real-valued functions defined on a non-meagre subset C withf 1 2 -convex <strong>and</strong> g Baire such that f(x) ≤ g(x), for x ∈ C.Then f is continuous on the interior of C.Lemma 10.3 (Averaging Lemma). In a normed <strong>topological</strong> group, a non-meagre set T is‘averaging’, that is, for any given point u ∈ T <strong>and</strong> for any sequence {u n } → u, there arev ∈ G (a right-averaging translator) <strong>and</strong> {v n } ⊆ T such that, for infinitely many n ∈ ω,we haveu 2 n = v n v.There is likewise a left-averaging translator such that for some {w n } ⊆ T for infinitelymany n ∈ ω, we haveu 2 n = ww n .Proof. Define null sequences byz n = u n u −1 , <strong>and</strong> ˜z n = u −1 u n . We are to solve u 2 nv −1 =v n ∈ T, oru˜z n z n uv −1 = v n ∈ T, equivalently ˜z n z n uv −1 = u −1 v n ∈ T ′ = u −1 T.Now put ψ n (x) := ˜z n z n x; thend(x, ˜z n z n x) = d(e, ˜z n z n ) = ‖˜z n z n ‖ ≤ ‖˜z n ‖ + ‖z n ‖ → 0.
<strong>Normed</strong> <strong>groups</strong> 105By the Category Embedding Theorem (Th. 6.1), for some λ ∈ T ′ = u −1 T, we have withλ = u −1 t <strong>and</strong> for infinitely many nsou −1 v n : = ˜z n z n λ ∈ T ′ = u −1 T,u˜z n z n λ = v n ∈ T, or u˜z n z n uu −1 λ = v n ∈ T,u 2 nu −1 λ = v n ∈ T, or u 2 n = v n λ −1 u = v n v(with v = λ −1 u = t −1 u 2 ∈ T −1 u 2 ).As for the remaining assertion, note that u −1n → u −1 , vn−1 ∈ T −1 <strong>and</strong>u −2n= v −1 v −1n .Thus noting that T −1 is non-meagre (since inversion is a homeomorphism) <strong>and</strong> replacingT −1 by T we obtain the required assertion by a right-averaging translator.Note the connection between the norms of the null sequences is only by way of theconjugate metrics:‖z n ‖ = d(e, u n u −1 ) = d(u, u n ), <strong>and</strong> ‖˜z n ‖ = d(e, u −1 u n ) = d(u −1n , u −1 ) = ˜d(u n , u).Whilst we may make no comparisons between them, both norms nevertheless convergeto zero.Definitions. For G, H normed <strong>groups</strong>, we say that f : G → H is locally Lipschitz at gif, for some neighbourhood N g of g <strong>and</strong> for some constants K g <strong>and</strong> all x, y in N g ,∣ ∣ ∣f(x)f(y) −1∣ ∣ ∣ ∣H≤ K g ‖xy −1 ‖ G .We say that f : G → H is locally bi-Lipschitz at g if, for some neighbourhood N g of g<strong>and</strong> for some positive constants K g , κ g , <strong>and</strong> all x, y in N g ,κ g ‖xy −1 ‖ G ≤ ∣ ∣ ∣ ∣f(x)f(y) −1∣ ∣ ∣ ∣H≤ K g ‖xy −1 ‖ G .If f : G → H is invertible, this asserts that both f <strong>and</strong> its inverse f −1 are locally Lipschitzat g <strong>and</strong> f(g) respectively.We say that the norm on G is n-Lipschitz if the function f n (x) := x n from G to G islocally Lipschitz at all g ≠ e, i.e. for each there is a neighbourhood N g of g <strong>and</strong> positiveconstants κ g , K g so thatκ g ‖xy −1 ‖ G ≤ ∣ ∣ ∣ ∣ x n y −n∣ ∣ ∣ ∣G≤ K g ‖xy −1 ‖ G .In an abelian context the power function is a homomorphism; we note that [HJ, p.381] refers to a semigroup being modular when each f n (defined as above) is an injectivehomomorphism. The condition on the right with K = n is automatic, <strong>and</strong> so one needrequire only that for some positive constant κκ‖g‖ ≤ ‖g n ‖.Note that, in the general context of an n-Lipschitz norm, if x n = y n , then as (x n y −n ) = e,we have κ g ‖xy −1 ‖ G ≤ ||x n y −n || G= ‖e‖ = 0, <strong>and</strong> so ‖xy −1 ‖ G = 0, i.e. the power function
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N. H. BINGHAM and A. J. OSTASZEWSKI
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Normed groups 3ContentsContents . .
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1. IntroductionGroup-norms, which b
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Normed groups 3Topological complete
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Normed groups 5abelian group has se
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Normed groups 74 (Topological permu
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Normed groups 9The following result
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Normed groups 11Corollary 2.4. For
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Normed groups 13More generally, for
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Normed groups 15definitions, our pr
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Normed groups 17so that fg is in th
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Normed groups 19(iii) The ¯d H -to
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Normed groups 21so‖αβ‖ ≤
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Normed groups 23Remark. Note that,
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Normed groups 25shows that [z n , y
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Normed groups 27Denoting this commo
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Normed groups 29Theorem 3.4 (Equiva
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Normed groups 31argument as again p
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Normed groups 33(ii) For α ∈ H u
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Normed groups 35Definition. A group
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Normed groups 37We now give an expl
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Normed groups 39Theorem 3.19 (Abeli
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Normed groups 412. Further recall t
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Normed groups 43Theorem 3.22 (Lipsc
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Normed groups 45Proof. Z γ = G (cf
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Normed groups 47Theorem 3.30. Let G
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Normed groups 49Remark. On the matt
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Normed groups 51As for the conclusi
- Page 57 and 58: Normed groups 53By (C-adm), we may
- Page 59 and 60: Normed groups 55equipped with an in
- Page 61 and 62: Normed groups 57Proof. To apply Th.
- Page 63 and 64: Normed groups 59Definition. A point
- Page 65 and 66: Normed groups 61Proposition 3.46 (M
- Page 67 and 68: Normed groups 63Thus ω δ (s) ≤
- Page 69 and 70: Normed groups 65Remark. In the penu
- Page 71 and 72: Normed groups 67The result confirms
- Page 73 and 74: Normed groups 69Proof. By the Baire
- Page 75 and 76: Normed groups 715. Generic Dichotom
- Page 77 and 78: Normed groups 73Returning to the cr
- Page 79 and 80: Normed groups 75Examples. Here are
- Page 81 and 82: Normed groups 77cf. [Eng, 4.3.23].)
- Page 83 and 84: Normed groups 79Remarks. 1. See [Fo
- Page 85 and 86: Normed groups 81Theorem 6.1 (Catego
- Page 87 and 88: Normed groups 83is continuous at th
- Page 89 and 90: Normed groups 85compact. Evidently,
- Page 91 and 92: Normed groups 87j ∈ ω} which enu
- Page 93 and 94: Normed groups 89The result below ge
- Page 95 and 96: Normed groups 91left-shift, not in
- Page 97 and 98: Normed groups 93As a corollary of t
- Page 99 and 100: Normed groups 953. For X a normed g
- Page 101 and 102: Normed groups 97Proof. Note that‖
- Page 103 and 104: Normed groups 99Taking h(x) := ‖
- Page 105 and 106: Normed groups 1019. The Semigroup T
- Page 107: Normed groups 103Theorem 9.5 (Semig
- Page 111 and 112: Normed groups 107Proof. Say f is bo
- Page 113 and 114: Normed groups 109Thus G is locally
- Page 115 and 116: Normed groups 111Theorem 10.10 (Bar
- Page 117 and 118: Normed groups 113K-analyticity was
- Page 119 and 120: Normed groups 115Theorem 11.6 (Disc
- Page 121 and 122: Normed groups 117restricted to X\M
- Page 123 and 124: Normed groups 119groups need not be
- Page 125 and 126: Normed groups 121Proof. In the meas
- Page 127 and 128: Normed groups 123Hence, as t i n
- Page 129 and 130: Normed groups 125The corresponding
- Page 131 and 132: Normed groups 127(t, x) ✛✻Φ T
- Page 133 and 134: Normed groups 129Fix s. Since s is
- Page 135 and 136: Normed groups 131Hence,‖x‖ −
- Page 137 and 138: Normed groups 133converging to the
- Page 139 and 140: Normed groups 135Definition. Let {
- Page 141 and 142: Normed groups 137However, whilst th
- Page 143 and 144: Normed groups 139embeddable, 14enab
- Page 145 and 146: Normed groups 141Bibliography[AL]J.
- Page 147 and 148: Normed groups 143Series 378, 2010.[
- Page 149 and 150: Normed groups 145abelian groups, Ma
- Page 151 and 152: Normed groups 147[Kak] S. Kakutani,
- Page 153 and 154: Normed groups 149fields. I. Basic p
- Page 155: Normed groups 151[So]R. M. Solovay,