MSC 85/26/Add.2 ANNEX 3 RESOLUTION MSC.268(85) - US Coast ...

MSC 85/26/Add.2 ANNEX 3 RESOLUTION MSC.268(85) - US Coast ... MSC 85/26/Add.2 ANNEX 3 RESOLUTION MSC.268(85) - US Coast ...

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MSC 85/26/Add.2ANNEX 3Page 350.2 Definitions and data for calculations (see figure 1.3.4.2)- empty cylinder, mass in grams: A- cylinder with tamped sample, mass in grams: B- wet sample, mass in grams: CC = B – A- dry sample, mass in grams: D- water, mass in grams (equivalent to volume in cm 3 ): EE = C – DVolume of cylinder: 1000 cm 3.3 Calculation of main characteristics- density of solid material, g/cm 3 (t/m 3 ): d- dry bulk density, g/cm 3 (t/m 3 ): γDγ = 1000- net water content, volume %: e ve v = DE x 100 x d- void ratio: e (volume of voids divided by volume of solids)e =1000 − DD= λd = - 1- degree of saturation, percentage by volume: SeS = veI:\MSC\85\26-Add-2.doc

MSC 85/26/Add.2ANNEX 3Page 351- gross water content, percentage by mass: W 1W 1 = CE x 100- net water content, percentage by mass: WW =DE x 100.4 Presentation of the compaction testsFor each compaction test the calculated void ratio (e) value is plotted as theordinate in a diagram with net water content (e v ) and degree of saturation (S) asthe respective abscissa parameters.Figure 1.3.4.5.5 Compaction curveThe test sequence results in a specific compaction curve (see figure 1.3.4.5).The critical moisture content is indicated by the intersection of the compactioncurve and the line S = 70% degree of saturation. The transportable moisture limit(TML) is the critical moisture content.I:\MSC\85\26-Add-2.doc

<strong>MSC</strong> <strong>85</strong>/<strong>26</strong>/<strong>Add.2</strong><strong>ANNEX</strong> 3Page 350.2 Definitions and data for calculations (see figure 1.3.4.2)- empty cylinder, mass in grams: A- cylinder with tamped sample, mass in grams: B- wet sample, mass in grams: CC = B – A- dry sample, mass in grams: D- water, mass in grams (equivalent to volume in cm 3 ): EE = C – DVolume of cylinder: 1000 cm 3.3 Calculation of main characteristics- density of solid material, g/cm 3 (t/m 3 ): d- dry bulk density, g/cm 3 (t/m 3 ): γDγ = 1000- net water content, volume %: e ve v = DE x 100 x d- void ratio: e (volume of voids divided by volume of solids)e =1000 − DD= λd = - 1- degree of saturation, percentage by volume: SeS = veI:\<strong>MSC</strong>\<strong>85</strong>\<strong>26</strong>-Add-2.doc

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