iz'u cSad xf.kr

iz'u cSad xf.kr iz'u cSad xf.kr

12.07.2015 Views

11- cgqin 5x-4x 2 +3 dk eku D;k gksxk tc x= -1 gks \Find the value of 5x-4x 2 +3 when x = - 1(a) 6 (b) -6(c) 6 (d) -312- cgqinksa dk ;ksx ,oa varj dks iznf'kZr djrk gS &Which reprsents the sum and difference of polynomials(a) P(x)+q(x) (b) P(x)-q(x)(c)Both nksuksa (d) None dksbZ ugha13- nks cgqinksa dk xq.kuQy dks forj.k fu;e yxkdj ckn esa ;ksx ,oa O;odyugsrq /kkrksa okys inksa dk lewgu fd;k tkrk gS \The product of polynomials is obtained by distributive law and then by addingor subtracting in the which terms ?(a)(b)(c)(d)leku ?kkrksa dkslike termsvlkeu ?kkrksa dks dislike termsughadksbZ ughabothNone14- nks cgqinksa dk xq.kuQy dks forj.k fu;e yxkdj ckn esa ;ksx ,oa O;odyugsrq /kkrksa okys inksa dk lewgu fd;k tkrk gS \(49)

The product of polynomials is obtained by distributive law and then by addingor subtracting in the which terms ?(a)(b)(c)(d)leku ?kkrksa dkslike termsvlkeu ?kkrksa dks dislike termsughadksbZ ughabothNone15- 325 dk chtkad D;k gksxk \What will be the beejank of 125(a) 3 (b) 7(c) 8 (d) None16- dkSu lh fLFkfr cgqin ds xq.kkadks dk chtkad dh mÙkj dh iqf"V djrk gS &Which of the following condition prove that :(a)(b)(c)(d)cka;k i{k < nka;k i{kcka;k i{k > nka;k i{kcka;k i{k = nka;k i{kmiq;ZDr esa dksbzZ ughaLHS < RHSLHS > RHSLHS = RHSNone of the above17- fuEufyf[kr esa ls lR; dFku NkafV, &Select True statment of the following :(a)lw= Å/oZ&fr;Zd }kjk iz'u dk gy ck;sa ls nk;sa ;k nk;sa ls ck;sa fd;ktk ldrk gS AQuestion can be solved from left to right or right to left byurdharvtriyak formula(50)

The product of polynomials is obtained by distributive law and then by addingor subtracting in the which terms ?(a)(b)(c)(d)leku ?k<strong>kr</strong>ksa dkslike termsvlkeu ?k<strong>kr</strong>ksa dks dislike termsughadksbZ ughabothNone15- 325 dk chtkad D;k gksxk \What will be the beejank of 125(a) 3 (b) 7(c) 8 (d) None16- dkSu lh fLFkfr cgqin ds xq.kkadks dk chtkad dh mÙkj dh iqf"V djrk gS &Which of the following condition prove that :(a)(b)(c)(d)cka;k i{k < nka;k i{kcka;k i{k > nka;k i{kcka;k i{k = nka;k i{kmiq;ZDr esa dksbzZ ughaLHS < RHSLHS > RHSLHS = RHSNone of the above17- fuEufyf[<strong>kr</strong> esa ls lR; dFku NkafV, &Select True statment of the following :(a)lw= Å/oZ&fr;Zd }kjk <strong>iz'u</strong> dk gy ck;sa ls nk;sa ;k nk;sa ls ck;sa fd;ktk ldrk gS AQuestion can be solved from left to right or right to left byurdharvtriyak formula(50)

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