v2010.10.26 - Convex Optimization
v2010.10.26 - Convex Optimization v2010.10.26 - Convex Optimization
760 APPENDIX E. PROJECTION10 0 idist(P 2 X i , S n +)10 −10 2 4 6 8 10 12 14 16 18Figure 172: Distance (confer (2077)) between positive semidefinite cone anditerate (2080) in affine subset A (2073) for Laurent’s completion problem;initially, decreasing geometrically.Using this technique, we find a positive semidefinite completion for⎡⎢⎣4 3 ? 23 4 3 ?? 3 4 32 ? 3 4⎤⎥⎦ (2081)Initializing the unknown entries to 0, they all converge geometrically to1.5858 (rounded) after about 42 iterations.Laurent gives a problem for which no positive semidefinite completionexists: [236]⎡⎢⎣1 1 ? 01 1 1 ?? 1 1 10 ? 1 1⎤⎥⎦ (2082)Initializing unknowns to 0, by alternating projection we find the constrained
E.10. ALTERNATING PROJECTION 761matrix closest to the positive semidefinite cone,⎡⎢⎣1 1 0.5454 01 1 1 0.54540.5454 1 1 10 0.5454 1 1⎤⎥⎦ (2083)and we find the positive semidefinite matrix closest to the affine subset A(2073):⎡⎤1.0521 0.9409 0.5454 0.0292⎢ 0.9409 1.0980 0.9451 0.5454⎥⎣ 0.5454 0.9451 1.0980 0.9409 ⎦ (2084)0.0292 0.5454 0.9409 1.0521These matrices (2083) and (2084) attain the Euclidean distance dist(A , S+).nConvergence is illustrated in Figure 172.E.10.3Optimization and projectionUnique projection on the nonempty intersection of arbitrary convex sets tofind the closest point therein is a convex optimization problem. The firstsuccessful application of alternating projection to this problem is attributedto Dykstra [127] [62] who in 1983 provided an elegant algorithm that prevailstoday. In 1988, Han [178] rediscovered the algorithm and provided aprimal−dual convergence proof. A synopsis of the history of alternatingprojection E.21 can be found in [64] where it becomes apparent that Dykstra’swork is seminal.E.10.3.1Dykstra’s algorithmAssume we are given some point b ∈ R n and closed convex sets{C k ⊂ R n | k=1... L}. Let x ki ∈ R n and y ki ∈ R n respectively denote aprimal and dual vector (whose meaning can be deduced from Figure 173and Figure 174) associated with set k at iteration i . Initializey k0 = 0 ∀k=1... L and x 1,0 = b (2085)E.21 For a synopsis of alternating projection applied to distance geometry, see [353,3.1].
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- Page 787 and 788: Bibliography[1] Edwin A. Abbott. Fl
- Page 789 and 790: BIBLIOGRAPHY 789[23] Dror Baron, Mi
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- Page 805 and 806: BIBLIOGRAPHY 805[237] Monique Laure
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760 APPENDIX E. PROJECTION10 0 idist(P 2 X i , S n +)10 −10 2 4 6 8 10 12 14 16 18Figure 172: Distance (confer (2077)) between positive semidefinite cone anditerate (2080) in affine subset A (2073) for Laurent’s completion problem;initially, decreasing geometrically.Using this technique, we find a positive semidefinite completion for⎡⎢⎣4 3 ? 23 4 3 ?? 3 4 32 ? 3 4⎤⎥⎦ (2081)Initializing the unknown entries to 0, they all converge geometrically to1.5858 (rounded) after about 42 iterations.Laurent gives a problem for which no positive semidefinite completionexists: [236]⎡⎢⎣1 1 ? 01 1 1 ?? 1 1 10 ? 1 1⎤⎥⎦ (2082)Initializing unknowns to 0, by alternating projection we find the constrained