12.07.2015 Views

v2010.10.26 - Convex Optimization

v2010.10.26 - Convex Optimization

v2010.10.26 - Convex Optimization

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

6.8. DUAL EDM CONE 531Proof. First, we observe membership of H −P S N+(V H V ) to K 2 because()P S N+(V H V ) − H = P S N+(V H V ) − V H V + (V H V − H) (1254)The term P S N+(V H V ) − V H V necessarily belongs to the (dual) positivesemidefinite cone by Theorem E.9.2.0.1. V 2 = V , hence()−V H −P S N+(V H V ) V ≽ 0 (1255)by Corollary A.3.1.0.5.Next, we requireExpanding,〈P K2 H −H , P K2 H 〉 = 0 (1256)〈−P S N+(V H V ) , H −P S N+(V H V )〉 = 0 (1257)〈P S N+(V H V ) , (P S N+(V H V ) − V H V ) + (V H V − H)〉 = 0 (1258)〈P S N+(V H V ) , (V H V − H)〉 = 0 (1259)Product V H V belongs to the geometric center subspace; (E.7.2.0.2)V H V ∈ S N c = {Y ∈ S N | N(Y )⊇1} (1260)Diagonalize V H V QΛQ T (A.5) whose nullspace is spanned bythe eigenvectors corresponding to 0 eigenvalues by Theorem A.7.3.0.1.Projection of V H V on the PSD cone (7.1) simply zeroes negativeeigenvalues in diagonal matrix Λ . ThenN(P S N+(V H V )) ⊇ N(V H V ) (⊇ N(V )) (1261)from which it follows:P S N+(V H V ) ∈ S N c (1262)so P S N+(V H V ) ⊥ (V H V −H) because V H V −H ∈ S N⊥c .Finally, we must have P K2 H −H =−P S N+(V H V )∈ K ∗ 2 .From6.6.1we know dual cone K ∗ 2 =−F ( S N + ∋V ) is the negative of the positivesemidefinite cone’s smallest face that contains auxiliary matrix V . ThusP S N+(V H V )∈ F ( S N + ∋V ) ⇔ N(P S N+(V H V ))⊇ N(V ) (2.9.2.3) which wasalready established in (1261).

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!