v2010.10.26 - Convex Optimization

v2010.10.26 - Convex Optimization v2010.10.26 - Convex Optimization

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208 CHAPTER 2. CONVEX GEOMETRYwhich is simply a restatement of optimality conditions (460) for conic problem(454). Suitable f(z) is the quadratic objective from convex problem1minimizez 2 zT Bz + q T zsubject to z ≽ 0(467)which means B ∈ S n + should be (symmetric) positive semidefinite for solutionof (465) by this method. Then (465) has solution iff (467) does. 2.13.10.1.5 Exercise. Optimality for equality constrained conic problem.Consider a conic optimization problem like (454) having real differentiableconvex objective function f(x) : R n →Rminimize f(x)xsubject to Cx = dx ∈ K(468)minimized over convex cone K but, this time, constrained to affine setA = {x | Cx = d}. Show, by means of first-order optimality condition(352) or (452), that necessary and sufficient optimality conditions are:(confer (460))x ⋆ ∈ KCx ⋆ = d∇f(x ⋆ ) + C T ν ⋆ ∈ K ∗(469)〈∇f(x ⋆ ) + C T ν ⋆ , x ⋆ 〉 = 0where ν ⋆ is any vector 2.83 satisfying these conditions.2.13.11 Proper nonsimplicial K , dual, X fat full-rankSince conically dependent columns can always be removed from X toconstruct K or to determine K ∗ [Wıκımization], then assume we are givena set of N conically independent generators (2.10) of an arbitrary properpolyhedral cone K in R n arranged columnar in X ∈ R n×N such that N > n(fat) and rankX = n . Having found formula (420) to determine the dual ofa simplicial cone, the easiest way to find a vertex-description of proper dual2.83 an optimal dual variable, these optimality conditions are equivalent to the KKTconditions [61,5.5.3].

2.13. DUAL CONE & GENERALIZED INEQUALITY 209cone K ∗ is to first decompose K into simplicial parts K i so that K = ⋃ K i . 2.84Each component simplicial cone in K corresponds to some subset of nlinearly independent columns from X . The key idea, here, is how theextreme directions of the simplicial parts must remain extreme directions ofK . Finding the dual of K amounts to finding the dual of each simplicial part:2.13.11.0.1 Theorem. Dual cone intersection. [330,2.7]Suppose proper cone K ⊂ R n equals the union of M simplicial cones K i whoseextreme directions all coincide with those of K . Then proper dual cone K ∗is the intersection of M dual simplicial cones K ∗ i ; id est,M⋃M⋂K = K i ⇒ K ∗ = K ∗ i (470)i=1Proof. For X i ∈ R n×n , a complete matrix of linearly independentextreme directions (p.145) arranged columnar, corresponding simplicial K i(2.12.3.1.1) has vertex-descriptionNow suppose,K =K =i=1K i = {X i c | c ≽ 0} (471)M⋃K i =i=1M⋃{X i c | c ≽ 0} (472)i=1The union of all K i can be equivalently expressed⎧⎡ ⎤⎪⎨[ X 1 X 2 · · · X M ] ⎢⎣⎪⎩aḅ.c⎥⎦ | a , b ... c ≽ 0 ⎫⎪ ⎬⎪ ⎭(473)Because extreme directions of the simplices K i are extreme directions of Kby assumption, then2.84 That proposition presupposes, of course, that we know how to perform simplicialdecomposition efficiently; also called “triangulation”. [303] [173,3.1] [174,3.1] Existenceof multiple simplicial parts means expansion of x∈ K , like (411), can no longer be uniquebecause number N of extreme directions in K exceeds dimension n of the space.⋄

2.13. DUAL CONE & GENERALIZED INEQUALITY 209cone K ∗ is to first decompose K into simplicial parts K i so that K = ⋃ K i . 2.84Each component simplicial cone in K corresponds to some subset of nlinearly independent columns from X . The key idea, here, is how theextreme directions of the simplicial parts must remain extreme directions ofK . Finding the dual of K amounts to finding the dual of each simplicial part:2.13.11.0.1 Theorem. Dual cone intersection. [330,2.7]Suppose proper cone K ⊂ R n equals the union of M simplicial cones K i whoseextreme directions all coincide with those of K . Then proper dual cone K ∗is the intersection of M dual simplicial cones K ∗ i ; id est,M⋃M⋂K = K i ⇒ K ∗ = K ∗ i (470)i=1Proof. For X i ∈ R n×n , a complete matrix of linearly independentextreme directions (p.145) arranged columnar, corresponding simplicial K i(2.12.3.1.1) has vertex-descriptionNow suppose,K =K =i=1K i = {X i c | c ≽ 0} (471)M⋃K i =i=1M⋃{X i c | c ≽ 0} (472)i=1The union of all K i can be equivalently expressed⎧⎡ ⎤⎪⎨[ X 1 X 2 · · · X M ] ⎢⎣⎪⎩aḅ.c⎥⎦ | a , b ... c ≽ 0 ⎫⎪ ⎬⎪ ⎭(473)Because extreme directions of the simplices K i are extreme directions of Kby assumption, then2.84 That proposition presupposes, of course, that we know how to perform simplicialdecomposition efficiently; also called “triangulation”. [303] [173,3.1] [174,3.1] Existenceof multiple simplicial parts means expansion of x∈ K , like (411), can no longer be uniquebecause number N of extreme directions in K exceeds dimension n of the space.⋄

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