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Unit 8 Benchmark/Test Review

Unit 8 Benchmark/Test Review

Unit 8 Benchmark/Test Review

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Chemistry 2012-2013 Name:__________________________ Period: __________<strong>Unit</strong> 8 Exam <strong>Review</strong>____1. In the reaction N 2 + 3H 2 → 2NH 3 , what is the mole ratio of nitrogen to ammonia?a. 1:1 c. 1:3b. 1:2 d. 2:3____ 2. For the reaction 2H 2 + O 2 → 2H 2 O, how many moles of water can be produced from6.0 mol of oxygen?a. 2.0 mol c. 12 molb. 6.0 mol d. 18 mol____ 3. For the reaction SO 3 + H 2 O → H 2 SO 4 , how many grams of sulfur trioxide arerequired to produce 4.00 mol of sulfuric acid?a. 80.0 g c. 240. gb. 160. g d. 320. g____ 4. For the reaction CH 4 + 2O 2 → CO 2 + 2H 2 O, how many moles of carbon dioxide areproduced from the combustion of 100. g of methane?a. 6.23 mol c. 12.5 molb. 10.8 mol d. 25 mol____5. For the reaction C + 2H 2 → CH 4 , how many moles of hydrogen are required toproduce 10 mol of methane, CH 4 ?a. 2 mol c. 10 molb. 4 mol d. 20 mol____6. In the reaction Zn + H 2 SO 4 → ZnSO 4 + H 2 , what is the mole ratio of zinc to sulfuricacid?a. 1:6 c. 1:2b. 1:1 d. 3:1____ 7. For the reaction C + 2H 2 → CH 4 , how many moles of hydrogen are required toproduce 10 mol of methane, CH 4 ?a. 2 mol c. 10 molb. 4 mol d. 20 mol_____8. What mass of oxygen is consumed by the complete combustion of 23.0 grams ofethylene (C 2 H 4 )?C 2 H 4 (g) + 3 O 2 (g) → 2 CO 2 (g) + 2 H 2 O(g)


a. 8.75 g c. 60.5 gb. 26.2 g d. 69.0 ge. 78.7 g____ 9. For the reaction SO 3 + H 2 O → H 2 SO 4 , calculate the percent yield if 500. g ofsulfur trioxide react with excess water to produce 575 g of sulfuric acid.a. 82.7% c. 91.2%b. 88.3% d. 93.9%____ 10. Aluminum reacts with oxygen to produce aluminum oxide.4 Al(s) + 3 O2(g) → 2 Al2O3(s)If 5.0 moles of Al react with excess O2, how many moles of Al2O3 can be formed?A. 1.0 mol C. 2.5 molB. 2.0 mol D. 5.0 molE. 10.0 mol____ 11. Dinitrogen trioxide, a blue solid, dissociates to form nitrogen monoxide and nitrogendioxide gases. What mass of nitrogen dioxide is formed from the decomposition of 13.1 g of N2O3?N 2 O 3 → NO + NO 2A. 5.17 g C. 6.55 gB. 7.93 g D. 12.8 gE. 21.6 g____ 12. Sodium carbonate reacts with hydrochloric acid as shown below in an unbalanced chemicalequation. What mass of CO2 is produced from the reaction of 2.94 g Na2CO3 with excess HCl?_____Na2CO3(s) + ____HCl(aq) → ____NaCl(aq) + ____CO2(g) + ____H2O(l)A. 1.22 g C. 2.94 gB. 2.44 g D. 5.88 gE. 7.08 g____ 13. Nitric oxide is made from the oxidation of ammonia. How many moles of nitric oxide canbe made from the reaction of 3.80 mol NH3 with 5.15 mol O2?4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)a. 3.80 mol c. 5.15 molb. 4.12 mol d. 6.44 mole. 8.95 mol____ 14. What volume would be occupied by two moles of propane gas, C 3 H 8 , at standard conditions(STP)?A. 11.2 litersB. 44.8 liters


C. 88 litersD. 22. 4 liters____ 15. How many moles of methane gas molecules, CH 4 , are in 11.2 liters of methane at standardconditions?A. 0.5 molesB. 11.2 molesC. 179.2 molesD. 27.2 moles____ 16. How many molecules are contained in 3 moles of water molecules, H 2 O?A. 6 moleculesB. 54 moleculesC. 1.8 x 10 24 moleculesD. 3 x 10 23 molecules____ 17. A sample of carbon dioxide gas (CO 2 ) contains 6 x 10 22 molecules. How many moles ofcarbon dioxide does this represent?A. 1/10 moleB. 4.4 molesC. 440 molesD. 10 molesAlso, study:Conversion charts. A copy will be provided for your use on the test.All <strong>Unit</strong> 8 Note Taking GuidesAll practice problem worksheets: Mole-Mole, Mole-Mass, Mass-Mass, % Yield,Volume-Moles, Moles-MoleculesNotes on Limiting and Excess ReactantsRead Chapter 9 in book.Remember when working with an assortment of stoichiometric calculations, identify whatyou’re given (G) and unknown (U). Choose the conversion that will use what your given (G)to end up with an answer for your unknown (U).IE: If you’re given a value in moles and are asked for an answer in grams: Moles→MassIf you’re given a value in grams and are asked for an answer in grams: Mass→MassIf you’re given molecules and asked for moles: Molecules→MolesETC….

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