12.07.2015 Views

Feynman Diagrams For Pedestrians - Herbstschule Maria Laach

Feynman Diagrams For Pedestrians - Herbstschule Maria Laach

Feynman Diagrams For Pedestrians - Herbstschule Maria Laach

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

4.2 Trace Techniques• consider a matrix elementū(p)Γu(q) =• using the tensor productwe can writeū(p)Γu(q) =4∑ū k (p)Γ kl u l (q) =k,l=14∑Γ kl u l (q)ū k (p) (126)k,l=1⎛⎞u 1 (q)ū 1 (p) · · · u 1 (q)ū 4 (p)⎜u(q) ⊗ ū(p) = ⎝.. ..⎟ . ⎠ (127)u 4 (q)ū 1 (p) · · · u 4 (q)ū 4 (p)4∑Γ kl [u(q) ⊗ ū(p)] lk =k,l=1• using the trace of a matrixtr(A) =4∑(Γ[u(q) ⊗ ū(p)]) kk (128)k=14∑A kk (129)k=1we can express a matrix element equivalently as a traceū(p)Γu(p) = tr(Γ[u(p) ⊗ ū(p)]) (130)• independent of the concrete realization of the Dirac matrices, we can computetheir traces using their anti commutation relations (34) alonetr(1) = 4(131a)tr (/a/b) = 1 () (34)tr (/a/b) + tr (/b/a) = tr(1) · ab = 4 · ab (131b)2tr (/a 1 ) = tr (/a 1 /a 2 /a 3 ) = tr (/a 1 /a 2 · · · /a 2n+1 ) (γ 5γ 5 = 1)= 0 (131c)tr (/a 1 /a 2 · · · /a n ) = tr (/a n · · · /a 2 /a 1 )tr(γ 5 ) = tr(γ 5 /a) = tr(γ 5 /a/b) = tr(γ 5 /a/b/c) = 0tr(γ 5 /a/b/c/d) = 4i · ɛ(a, b, c, d)only (131d) depends on the existence of a charge conjugation matrix(131d)(131e)(131f)• also from the anti commutation relations alone, we can prove contraction formulae:γ µ /aγ µ = −2 · /aγ µ /a/b/cγ µ = −2 · /c/b/aγ µ γ µ = 4γ µ /a/bγ µ = 4 · ab(132a)(132b)(132c)(132d)25

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!