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Practice of Kinetics (Comprehensive Chemical Kinetics, Volume 1)

Practice of Kinetics (Comprehensive Chemical Kinetics, Volume 1)

Practice of Kinetics (Comprehensive Chemical Kinetics, Volume 1)

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2 CONSISTENCY WITH EQNS. OF TYPE -d[A]/dt = k[A]"[BIb 365average<strong>of</strong>thetwotimest,-, andt,,,;i.e.,tj - t (t,-i+t,+,),andsothecontributions<strong>of</strong> all values <strong>of</strong> f(a) intermediate between the first and last are seriouslyunderweighted. Indeed, in the special case when the time intervals between successiveconcentration determinations are equal so that t, = 3 (tj-, + ti+ ,) the weightingfactor becomes zero for all values <strong>of</strong>j from 1 to (n- 1) inclusive. In this situation,none <strong>of</strong> the intermediate concentration terms contribute to the mean value<strong>of</strong> k and we obtainf(ao)- - 1 f(an))h-tn-1As far as this method <strong>of</strong> obtaining an average value <strong>of</strong> k is concerned, the intermediateconcentration determinations at equally spaced time intervals might aswell not have been made!The general conclusion to be drawn from this analysis is that there is littlepoint in performing the laborious operation <strong>of</strong> calculating individual k values fromsuccessive pairs <strong>of</strong> observations in order to obtain a mean value since this procedureplaces undue weight on the initial and final observations which in practice are<strong>of</strong>ten the least accurate.Method 2. Calculation <strong>of</strong> the rate coefficient using a graphical method.As we have already pointed out, each <strong>of</strong> the integrated forms <strong>of</strong> the rate equationmay be writtenf(ao)-f(a) = k'(t-to)where k' is proportional to the rate coefficient k. Clearly a plot <strong>of</strong> f(a) against(t- to) should be linear with an intercept equal to f(ao) at (t - to) = 0 and a slope,-k'. From the slope and the value <strong>of</strong> m, the rate coefficient follows at once. Weshall not consider at this point the arguments for and against constraining the lineto pass through f(ao) at (t - to) = 0. For the moment, we shall adopt this proceduresince the object <strong>of</strong> this section is merely to present some <strong>of</strong> the problems whicharise in the treatment <strong>of</strong> data; the recommended method is always to make use<strong>of</strong> the data <strong>of</strong> a number <strong>of</strong> experiments as described in the next section.In view <strong>of</strong> our previous discussion, it is clearly <strong>of</strong> importance to evaluate thecontribution <strong>of</strong> each experimental observation to the average value <strong>of</strong> k so obtained.This depends on the criterion according to which the straight line through thepoints is constructed. If we assume that the line is drawn so that the algebraic sum<strong>of</strong> the deviations, S, <strong>of</strong> the experimental points from the line is close to zero, wecan deduce the contribution <strong>of</strong> each point to the average value <strong>of</strong> k as follows.References p. 407

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