6.3 Exercises1. Determine the roots of the cubic x 3 − (a 2 + ab + b 2 )x + ab(a + b).2. Suppose x 1 ≠ x 2 <strong>and</strong> y i = x 3 1, y 2 = x 3 2. Write down the equation of the linethrough the points (x 1 , y 1 ), (x 2 , y 2 ) <strong>and</strong> prove that it cuts the graph of y = x 3at three points, two of which may coincide.3. Prove that the cubic y = x 3 is convex on (0, ∞), <strong>and</strong> concave on (−∞, 0).7 AppendixThis contains additional information about <strong>polynomials</strong> <strong>and</strong> some IMO-type problems.7.1 Some more facts1. The collection of polys is closed under addition, multiplication <strong>and</strong> composition.In other words, ifp(x) = a 0 + a 1 x + · · · + a n x n , q(x) = b 0 + b x + · · · + b m x m ,are polys of degree n, m then p + q, pq, p ◦ q, q ◦ p are polys <strong>and</strong>deg(p+q) ≤ max(deg p, deg q), deg(pq) = m+n, deg(p◦q) = deg(q ◦p) = mn.2. The following are special <strong>polynomials</strong>. Let a be a fixed complex number <strong>and</strong>n ∈ N:∑n−1n∑( nx n − a n , x n−k+1 a k , xk)n−k a k ,where( n=k)are the Binomial coefficients.Note thatk=0k=0{n!,(n−k)!k!if 0 ≤ k ≤ n,0, if k < 0 or k > n∑n−1x n − a n = (x − a) x n−k+1 a k , (x + a) n =k=0n∑k=0( nk)x n−k a k ,3. a is root (zero) of a poly p if p(a) = 0. If this is so, then we can factor p: thereis a poly q, with deg q = deg p − 1, such thatp(x) = (x − a)q(x).18
Note especially that if a is rational <strong>and</strong> all the coeffs of p are rational, thenthe coeffs of q are also rational.If b is another root of p, then q(b) = 0, <strong>and</strong> so we can factor q: q(x) =(x − b)r(x), deg r = deg q − 1. Thus p(x) = (x − a)(x − b)r(x), <strong>and</strong> so on: ifx 1 , x 2 , . . . , x n are roots of p, thenp(x) = c(x − x 1 )(x − x 2 ) · · · (x − x n ) = cn∏(x − x i ).4. Suppose p/q, with p, q ∈ Z, (p, q) = 1, q ≠ 0, is a rational root of a polyp(x) = a n x n + · · · + a 0 whose coeffs are integers. Then p|a 0 , q|a n .This is another theorem due to Gauss. It reduces the search for rational rootsof polys with integer coeffs to an examination of a finite number of possibilitieswhich arise by factorising the integers a 0 , a n .5. How are the roots of a poly related to its coeffs? If ax 2 + bx + c is a quadratic,so that a ≠ 0, <strong>and</strong> its roots are x 1 , x 2 , thenax 2 + bx + c = a(x − x 1 )(x − x 2 ) = a(x 2 − (x 1 + x 2 )x + x 1 x 2 ,i=1whencex 1 + x 2 = − b a , x 1x 2 = c a .If ax 3 + bx 2 + cx + d is a cubic, so that a ≠ 0, <strong>and</strong> its roots are x 1 , x 2 , x 3 , thenax 3 + bx 2 + cx + d = a(x − x 1 )(x − x 2 )(x − x 3 )whence= a(x 3 − (x 1 + x 2 + x 3 )x + (x 1 x 2 + x 2 x 3 + x 3 x 1 )x − x 1 x 2 x 3 ),x 1 + x 2 + x 3 = − b a , x 1x 2 + x 2 x 3 + x 3 x 1 = c a , x 1x 2 x 3 = − d a .Similar relations hold for higher degree <strong>polynomials</strong>.6. The poly x n − 1 has roots ω k , k = 0, 1, 2, . . . , n whereThusso that, if x is a real number, thenω = cos( 2π n ) + i sin(2π n ) = e i2πn .n−1∏x n − 1 = (x − ω k ),k=0n−1∏|x n − 1| 2 = (x 2 − 2x cos( 2kπn ) + 1).k=019
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