Chapter 4: Activated Sludge Modelling - IqTMA-UVa
Chapter 4: Activated Sludge Modelling - IqTMA-UVa Chapter 4: Activated Sludge Modelling - IqTMA-UVa
Expression of SBiomass balance:VdX/dt = 0 = Q 0 X 0 - (Q e X e + Q w X w ) + Vr g (Q e X e + Q w X w ) - Q 0 X 0 = VµXFrom the definition of SRT:(Q e X e + Q w X w ) - Q 0 X 0 = (Q e X e + Q w X w )= VX/SRT 1/SRT = µµ = µ m S/(K s + S) – k dS = K s (1 + (k d )SRT)/(SRT(µ m – k d ) – 1)28
Expression of XX can be obtained from S mass balance:VdS/dt = Q 0 S 0 – (Q e S e + Q w S w ) + r su V = 0With the assumptions that S = S w = S e = S r (S = bsCOD) and since (Q e+ Q w) = Q 0 , this becomes:Q 0 (S 0 – S) = -r su VSince r g = -Yr su – k d X; r g = µX = X/SRT and HRT = V/QX = (SRT/HRT) Y(S 0 – S)/(1 + (k d )SRT)29
- Page 4 and 5: Solving the Exponential ModelBy sol
- Page 6 and 7: Endogenous decayIf part of the biom
- Page 8 and 9: Continuous Treatment in wellmixed r
- Page 10 and 11: ExerciseThe growth of a strain of L
- Page 12 and 13: Maximum Dilution Rate: DmaxCell con
- Page 14 and 15: Influence of nbVSSAn amount of non
- Page 16 and 17: Influence of nbVSSFraction of activ
- Page 18 and 19: Biomass retentionCell washout is mo
- Page 20 and 21: AerationSurfaceDiffused$$$ Aeration
- Page 22 and 23: Many configuration possible!The A2/
- Page 24 and 25: OverviewApplicationCostsAdvantagesD
- Page 26 and 27: Solid Retention Time (SRT)The SRT i
- Page 30 and 31: Total mixed liquor VSS (MLVSS)MLVSS
- Page 32 and 33: ..and if we have nitrification??P M
- Page 34 and 35: Processes for BOD Removal andNitrif
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- Page 44 and 45: Processes for Biological NitrogenRe
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- Page 58 and 59: Processes for BiologicalPhosphorous
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- Page 64 and 65: Activated Sludge ModelingASM nº164
- Page 66 and 67: Biological reaction kineticsMicroor
- Page 68 and 69: Model presentationMASS BALANCES:•
- Page 70 and 71: Components in ASM1Organic matter ch
- Page 72 and 73: Components in ASM172
- Page 74 and 75: Processes in ASM1Biological process
- Page 76 and 77: Organic Matter BiodegradationORGANI
Expression of SBiomass balance:VdX/dt = 0 = Q 0 X 0 - (Q e X e + Q w X w ) + Vr g (Q e X e + Q w X w ) - Q 0 X 0 = VµXFrom the definition of SRT:(Q e X e + Q w X w ) - Q 0 X 0 = (Q e X e + Q w X w )= VX/SRT 1/SRT = µµ = µ m S/(K s + S) – k dS = K s (1 + (k d )SRT)/(SRT(µ m – k d ) – 1)28
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