12.07.2015 Views

com www.GOALias.blogspot.com

com www.GOALias.blogspot.com

com www.GOALias.blogspot.com

SHOW MORE
SHOW LESS
  • No tags were found...

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

<strong>www</strong>.<strong>GOALias</strong>.<strong>blogspot</strong>.<strong>com</strong>Now, consider a different surface, which has the same boundary. Thisis a pot like surface [Fig. 8.1(b)] which nowhere touches the current, buthas its bottom between the capacitor plates; its mouth is the circularloop mentioned above. Another such surface is shaped like a tiffin box(without the lid) [Fig. 8.1(c)]. On applying Ampere’s circuital law to suchsurfaces with the same perimeter, we find that the left hand side ofEq. (8.1) has not changed but the right hand side is zero and not μ 0i,since no current passes through the surface of Fig. 8.1(b) and (c). So wehave a contradiction; calculated one way, there is a magnetic field at apoint P; calculated another way, the magnetic field at P is zero.Since the contradiction arises from our use of Ampere’s circuital law,this law must be missing something. The missing term must be suchthat one gets the same magnetic field at point P, no matter what surfaceis used.We can actually guess the missing term by looking carefully atFig. 8.1(c). Is there anything passing through the surface S between theplates of the capacitor? Yes, of course, the electric field! If the plates of thecapacitor have an area A, and a total charge Q, the magnitude of theelectric field E between the plates is (Q/A)/ε 0(see Eq. 2.41). The field isperpendicular to the surface S of Fig. 8.1(c). It has the same magnitudeover the area A of the capacitor plates, and vanishes outside it. So whatis the electric flux Φ Ethrough the surface S ? Using Gauss’s law, it is1 Q QΦE= E A = A =ε0 A ε(8.3)0Now if the charge Q on the capacitor plates changes with time, there is acurrent i = (dQ/dt), so that using Eq. (8.3), we havedΦd ⎛E Q⎞1 dQ=dt dt ⎜ =⎝ε⎟⎠ ε dt0 0This implies that for consistency,dΦEε ⎛0 ⎜⎞⎝⎟dt⎠ = i (8.4)This is the missing term in Ampere’s circuital law. If we generalisethis law by adding to the total current carried by conductors throughthe surface, another term which is ε 0times the rate of change of electricflux through the same surface, the total has the same value of current ifor all surfaces. If this is done, there is no contradiction in the value of Bobtained anywhere using the generalised Ampere’s law. B at the point Pis non-zero no matter which surface is used for calculating it. B at apoint P outside the plates [Fig. 8.1(a)] is the same as at a point M justinside, as it should be. The current carried by conductors due to flow ofcharges is called conduction current. The current, given by Eq. (8.4), is anew term, and is due to changing electric field (or electric displacement,an old term still used sometimes). It is, therefore, called displacementcurrent or Maxwell’s displacement current. Figure 8.2 shows the electricand magnetic fields inside the parallel plate capacitor discussed above.The generalisation made by Maxwell then is the following. The sourceof a magnetic field is not just the conduction electric current due to flowingElectromagneticWavesFIGURE 8.1 Aparallel platecapacitor C, as part ofa circuit throughwhich a timedependent currenti (t) flows, (a) a loop ofradius r, to determinemagnetic field at apoint P on the loop;(b) a pot-shapedsurface passingthrough the interiorbetween the capacitorplates with the loopshown in (a) as itsrim; (c) a tiffinshapedsurface withthe circular loop asits rim and a flatcircular bottom Sbetween the capacitorplates. The arrowsshow uniform electricfield between thecapacitor plates.271

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!