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<strong>www</strong>.<strong>GOALias</strong>.<strong>blogspot</strong>.<strong>com</strong>7.5 AC VOLTAGE APPLIED TO A CAPACITORFigure 7.8 shows an ac source ε generating ac voltage v = v msin ωtconnected to a capacitor only, a purely capacitive ac circuit.When a capacitor is connected to a voltage sourcein a dc circuit, current will flow for the short timerequired to charge the capacitor. As chargeaccumulates on the capacitor plates, the voltageacross them increases, opposing the current. That is,a capacitor in a dc circuit will limit or oppose thecurrent as it charges. When the capacitor is fullycharged, the current in the circuit falls to zero.When the capacitor is connected to an ac source,as in Fig. 7.8, it limits or regulates the current, butdoes not <strong>com</strong>pletely prevent the flow of charge. Thecapacitor is alternately charged and discharged asthe current reverses each half cycle. Let q be thecharge on the capacitor at any time t. The instantaneous voltage v acrossthe capacitor isqv = (7.15)CFrom the Kirchhoff’s loop rule, the voltage across the source and thecapacitor are equal,qvmsin ω t =CdqTo find the current, we use the relation i =dtdi = ( vmCsin ω t)= ωCvmcos( ωt)dtUsing the relation,⎛ π⎞cos( ωt) = sin ⎜ωt+ ⎟ , we have⎝ 2⎠ Alternating CurrentFIGURE 7.8 An ac sourceconnected to a capacitor.⎛ π⎞i = imsin ⎜ωt +⎝⎟2⎠(7.16)where the amplitude of the oscillating current is i m= ωCv m. We can rewriteit asvmim=(1/ ω C)Comparing it to i m= v m/R for a purely resistive circuit, we find that(1/ωC) plays the role of resistance. It is called capacitive reactance andis denoted by X c,X c= 1/ωC (7.17)so that the amplitude of the current isivmm=X(7.18)C241

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