12.07.2015 Views

com www.GOALias.blogspot.com

com www.GOALias.blogspot.com

com www.GOALias.blogspot.com

SHOW MORE
SHOW LESS
  • No tags were found...

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

<strong>www</strong>.<strong>GOALias</strong>.<strong>blogspot</strong>.<strong>com</strong>Electrostatic Potentialand Capacitancewhere ˆr is the unit vector along the position vector OP.The electric potential of a dipole is then given by1 ˆV = pr g24 π ; (r >> a) (2.15)ε0rEquation (2.15) is, as indicated, approximately true only for distanceslarge <strong>com</strong>pared to the size of the dipole, so that higher order terms ina/r are negligible. For a point dipole p at the origin, Eq. (2.15) is, however,exact.From Eq. (2.15), potential on the dipole axis (θ = 0, π ) is given by1 pV =±2(2.16)4 π ε0r(Positive sign for θ = 0, negative sign for θ = π.) The potential in theequatorial plane (θ = π/2) is zero.The important contrasting features of electric potential of a dipolefrom that due to a single charge are clear from Eqs. (2.8) and (2.15):(i) The potential due to a dipole depends not just on r but also on theangle between the position vector r and the dipole moment vector p.(It is, however, axially symmetric about p. That is, if you rotate theposition vector r about p, keeping θ fixed, the points correspondingto P on the cone so generated will have the same potential as at P.)(ii) The electric dipole potential falls off, at large distance, as 1/r 2 , not as1/r, characteristic of the potential due to a single charge. (You canrefer to the Fig. 2.5 for graphs of 1/r 2 versus r and 1/r versus r,drawn there in another context.)2.5 POTENTIAL DUE TO A SYSTEM OF CHARGESConsider a system of charges q 1, q 2,…, q nwith position vectors r 1, r 2,…,r nrelative to some origin (Fig. 2.6). The potential V 1at P due to the chargeq 1is1 q1V1=4 πε0r1Pwhere r 1Pis the distance between q 1and P.Similarly, the potential V 2at P due to q 2andV 3due to q 3are given by1 q2V = 24 π ε r,1 q3V3=4 πε r0 2P0 3Pwhere r 2Pand r 3Pare the distances of P fromcharges q 2and q 3, respectively; and so on for thepotential due to other charges. By thesuperposition principle, the potential V at P dueto the total charge configuration is the algebraicsum of the potentials due to the individualchargesV = V 1+ V 2+ ... + V n(2.17)FIGURE 2.6 Potential at a point due to asystem of charges is the sum of potentialsdue to individual charges.57

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!