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T - 厦门大学通信工程系

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2FSK- 同 步 检 波01 rpe1= ∫ f( z) dz=erfc( )2 2−∞同 理 可 求 pe2=1 rerfc( )2 2在 大 信 噪 比 时 , pe=12π re−r/22011-9-11 71

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