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2FSK- 包 络 检 波变 量 代 换t=2vσn1,z=a2σn=r得2 ∞z tI ( zt)e12 22 2− ( t + z )− /2 0p = e dte1∫0tI zt t z σ2 2 2o( )exp[ − ( + ) / 2] 为n= 11 a∴ p = e r =2 2δ2−r/2e1 ,2的 广 义 瑞 利 分 布2011-9-11 66
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