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2FSK- 包 络 检 波p10 = p(v1< v 2 )=∫0∞f (v∞1)dv1∫f (v 2 ) dv 2v 1=∫ ∞0vσ12nIoav(σ12n)exp[ −(v21+ a2) / 2σ2n]exp( −v21/ 2σ2n)dv1=∫ ∞ v 1 av21 −(2v+ a ) 2I o ( )exp[1 2/ 2σn02 2σ n σ n]dv12011-9-11 65
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