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T - 厦门大学通信工程系

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2ASK- 同 步 检 波求 最 佳 门 限 : f (*) x = f (*) x0 1可 求 得 归 一 化 门 限 b* = r/201pe= erfc( r /2),21大 信 噪 比 r >> 1, pe= eπ r−r/42011-9-11 58

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