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2ASK- 同 步 检 波1 b−ap = p( x< b) = ∫ f ( x) dx= 1 − [1 −erf( )]2 2δe1 1−∞1 bp = p( x> b) = ∫ f ( x) dx= [1 −erf( )]2 2δe2 0bb∞2n2np = p(1) P + p(0)Pe e1 e21 b−a 1 b= [1 + erf ( )] + [1 −erf( )]4 2δ4 2δ2 2nn2011-9-11 57
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