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3.8 The Maple Packages • 85> Limit((1 + 1/x)^x, x=infinity);limx→∞ (1 + 1 x )xRequest a hint for the next step of the computation.> Hint(%);Creating problem #3Rewrite the expression as an exponential to prepare forusing l‘Hopital’s rule[rewrite, (1 + 1 x )x = e (x ln(1+ 1 x )) ]Use the rule that is returned by Hint.> Rule[%](%%);limx→∞ (1 + 1 x )x = limx→∞ e(x ln(1+ 1 x ))> Hint(%);[exp]> Rule[%](%%);lim (1 + 1x→∞ x )x = e (lim x→∞ x ln(1+ 1 x ))> Hint(%);[lhopital , ln(1 + 1 x )]> Rule[%](%%);limx→∞ (1 + 1 x )x = e (lim x→∞xx+1 )

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