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3.6 Differential Equations: dsolve • 73> eval(y(x), soln);16000000 Heaviside(x − 2) 1x3 − Heaviside(x − 2)7500001+ Heaviside(x − 2) x5000001− Heaviside(x − 2) x210000001−6000000 Heaviside(x − 4) x3 + 1 Heaviside(x − 4)937501−125000 Heaviside(x − 4) x + 1Heaviside(x − 4) x250000011−15000000 x3 +1250000 x> y := unapply(%, x);y := x → 1 Heaviside(x − 2) x360000001−750000 Heaviside(x − 2) + 1Heaviside(x − 2) x5000001− Heaviside(x − 2) x210000001−6000000 Heaviside(x − 4) x3 + 1 Heaviside(x − 4)937501−125000 Heaviside(x − 4) x + 1Heaviside(x − 4) x250000011−15000000 x3 +1250000 xThis value of y satisfies the differential equation, the boundary conditions,and the initial value.> ode2;

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