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Hadronic production of a Higgs boson in association with two jets at ...

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3.2. The cut-constructible parts 78This leaves Fig.3.5(c), which has a far richer structure than those previouslystudied. Each loop helicity is unconstra<strong>in</strong>ed, which means th<strong>at</strong> fermions as well asgluons can propag<strong>at</strong>e around the loop. In addition, there are now <strong>two</strong> contribut<strong>in</strong>gtopologies which we label D (c)g,+ and D (c)g,− the subscript <strong>in</strong>dic<strong>at</strong><strong>in</strong>g the species andhelicity <strong>of</strong> l 1 <strong>in</strong> the φ conta<strong>in</strong><strong>in</strong>g amplitude.D (c)g,+ = A (0)n−1(φ, l + 1 , (n − 1)+ , . . .,m − , . . .,3 + , l − 2 )A(0) 3 (l + 2 , 2+ , l − 3 )×A (0)3 (l+ 3 , 1− , l − 4 )A(0) 3 (l+ 4 , n+ , l − 1 ), (3.26)D (c)g,− = A (0)n−1(φ, l − 1 , (n − 1) + , . . .,m − , . . .,3 + , l + 2 )A (0)3 (l − 2 , 2 + , l + 3 )×A (0)3 (l− 3 , 1− , l + 4 )A(0) 3 (l− 4 , n+ , l + 1 ). (3.27)There are <strong>two</strong> diagrams which have the same topology as (c), one <strong>with</strong> p 1 ∈ P i,j andone <strong>with</strong> p m ∈ P i,j (P i,j represents the massive leg). For convenience we consideronly the case where p m ∈ P i,j explicitly, s<strong>in</strong>ce it is trivial to obta<strong>in</strong> the rema<strong>in</strong><strong>in</strong>gdiagram from this one. The momentum constra<strong>in</strong>ts are as follows,and the <strong>two</strong> specific solutions for l arel µ (1) = [1n]2[n2] 〈1|γµ |2] andl 2 = l + p 2 (3.28)l 3 = l (3.29)l 4 = l − p 1 (3.30)l 1 = l 4 − p n (3.31)l µ (2) = 〈1n〉2〈2n〉 〈2|γµ |1]. (3.32)Once aga<strong>in</strong> the solution associ<strong>at</strong>ed <strong>with</strong> l (1) does not contribute and we are left <strong>with</strong>only l → l (2) . We comb<strong>in</strong>e the <strong>two</strong> helicity solutions (eqs. (3.26)-(3.27))D (c)g =〈m|l 1 |n] 4 〈1|l 3 |2] 4 + 〈m|l 2 |2] 4 〈1|l 4 |n] 4γ〈l 2 l 1 〉〈l 1 (n − 1)〉〈l 2 3〉〈l 3 l 4 〉〈l 3 1〉〈l 4 1〉[l 3 l 2 ][l 4 l 1 ][nl 1 ][nl 4 ][2l 2 ][2l 3 ] . (3.33)Here we have <strong>in</strong>troduced γ = ∏ 4α=n−1〈α(α − 1)〉 to simplify the formula. Next weuse the momentum constra<strong>in</strong>ts to remove l 1 and l 2 from the numer<strong>at</strong>or.D (c)g =〈m|l 4 |n] 4 〈1|l 3 |2] 4 + 〈m|l 3 |2] 4 〈1|l 4 |n] 4γ〈l 2 l 1 〉〈l 1 (n − 1)〉〈l 2 3〉〈l 3 l 4 〉〈l 3 1〉〈l 4 1〉[l 3 l 2 ][l 4 l 1 ][nl 1 ][nl 4 ][2l 2 ][2l 3 ] .

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