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Hadronic production of a Higgs boson in association with two jets at ...

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2.4. Sp<strong>in</strong>or <strong>in</strong>tegr<strong>at</strong>ion 47+ 2π[˜λη] (1− δ(〈λ|P |η])g(λ) +〈λ|P |˜λ]〈λ|P |η]k∑j=1)δ(〈λB j 〉)g(λ)〈λB j 〉 . (2.56)Th<strong>at</strong> is we sum over the poles com<strong>in</strong>g from g(λ) and the denom<strong>in</strong><strong>at</strong>or 〈λ|P |λ]〈λ|P |η].At first glance one might expect to see a piece proportional to δ(〈λ|P |λ]), howeverone cannot s<strong>at</strong>isfy the vanish<strong>in</strong>g <strong>of</strong> the 〈λ| and the conjug<strong>at</strong>ion rel<strong>at</strong>ion simultaneously,so there is no pole here. Upon <strong>in</strong>tegr<strong>at</strong>ion over λ the first term vanishes suchth<strong>at</strong> the <strong>in</strong>tegral is localised by the rema<strong>in</strong><strong>in</strong>g δ functions. This allows to write thesp<strong>in</strong>or <strong>in</strong>tegral <strong>of</strong> our function g(λ) as,∫P 2I = 〈λ, dλ〉[˜λ, d˜λ]〈λ|P |λ] 2g(λ)= − 1k∑P 2g(λ P) +j=1[B j η]〈B j |P |B j ]〈B j |P |η]∏ ki=1 〈B jA i 〉∏l≠j 〈B jB l 〉(2.57)where |λ P 〉 = |P |η]. Knowledge <strong>of</strong> the <strong>in</strong>tegral <strong>of</strong> the function g(λ) allows us totrivially determ<strong>in</strong>e the double cut <strong>of</strong> a bubble <strong>in</strong>tegral, g(λ) = 1,∆I 2 = −1. (2.58)We can also <strong>in</strong>vestig<strong>at</strong>e the cut <strong>of</strong> a three mass triangle,∫∆I 3 = d 4 lδ(l 2 )δ(l − K 1 ) 2 1(l + K 3 ) 2∫ ∞∫= t dt 〈λ, dλ〉[˜λ, d˜λ] δ(K2 1 − t〈λ|K 1 |˜λ])0K3 2 + t〈λ|K 3|˜λ]∫K12 〈λ|K 1 |λ]= 〈λ, dλ〉[˜λ, d˜λ]〈λ|K 1 |˜λ] 2 K3 2〈λ|K 1|˜λ] + K∫1 2〈λ|K 3|˜λ]1= 〈λ, dλ〉[˜λ, d˜λ]〈λ|K 1 |˜λ]〈λ|Q|˜λ] , (2.59)where Q µ = K2 3K µ K1 2 1 + Kµ 3 . We can further simplify this by <strong>in</strong>troduc<strong>in</strong>g a Feynmanparameter x which comb<strong>in</strong>es the <strong>two</strong> denom<strong>in</strong><strong>at</strong>ors <strong>at</strong> the cost <strong>of</strong> one extra<strong>in</strong>tegr<strong>at</strong>ion,∫11〈λ|K 1 |˜λ]〈λ|Q|˜λ] = 1dx(2.60)〈λ|R|˜λ] 2<strong>with</strong> R = (1 − x)K + xQ. As a result <strong>of</strong> this transform<strong>at</strong>ion the <strong>in</strong>tegral over λ isequal to th<strong>at</strong> <strong>of</strong> the scalar bubble which leaves only the x <strong>in</strong>tegr<strong>at</strong>ion,∆I 3= −0∫ 10dx 1 R2. (2.61)

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