IBM System/7 Functional Characteristics - All about the IBM 1130 ...

Example: Assume that the BUL instruction is at storage locations 87 and 88.0 5 8 16 31BUL instruction Op code R Modifier Address0 1 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 1 01 1 I 1 II 1 1 1 1 1 1 1 I I I I I I 1 I I I I I 1 1 15 0 08 0 4 2 20IAR15BUL instruction (Decimal 89)is fetched 0 0 0 0 0 0 0 0 1 0 1 0 11 0 0 1I III I I 1 I III I 1 I0 0 5 9E1AR is notstored by a'a-BUL instruc-Eration:: • • : • : • ••••••••••••••••••• • • •••••0IAR15After BULinstruction execution(Decimal 1058)0 0 0 0 0 1 0 0 0 0 1 0 0 0 1 0I I I I i I I I 1 I 1 I I I I0 4 2 2The IAR contains the effective address of the next instruction to be executed; that is, theinstruction branched to, which is at location 1058. The branch to location 1058 is taken andexecution begins.Processor Instructions 4-37