IBM System/7 Functional Characteristics - All about the IBM 1130 ...

Example:Word in accumulator 0110 1100 0000 1111Word from storage 1100 0011 0000 1111Result in accumulator 1010 1111 0000 0000AND Register (PNR)O 5 8 15Op code1 1 1 1 1I 1 1RXXX1 1ModifierO 0 0 010 0 1 11 1 1 1 1 1 1F 8-F 0 3The contents of the accumulator are ANDed, bit by bit, with the contents of the register(R). The result replaces the contents of the accumulator. The contents of the addressedregister are not changed.If R=000, specifying the accumulator, the instruction is, in effect, a no-operationbecause the final contents of the accumulator are unchanged from the original contents.Any data ANDed with itself has a fmal result equal to the original data.The carry and overflow indicators are not changed. The result indicators are changedto reflect the fmal contents of the accumulator.ANDing occurs only between corresponding bits in the accumulator and in the indexregister: bit 0 is ANDed only with bit 0, bit 1 only with bit 1, and so on. The fourpossible ANDing combinations are:Bit Value from Bit Value from Result inIndex Register Accumulator Accumulator0 0 00 1 01 0 01Thus, a bit value of 1 will result in the accumulator only if a corresponding bit positionis set to a value of 1 in both the accumulator and the index register.Example:Word in accumulatorWord in index registerResult in accumulator0101 0000 1111 10101010 1111 1010 11110000 0000 1010 1010OR Register (POR)O 5 815Op code1 1 1 1 1lit!XRX X1ModifierO 0 0 0 1 0 1 0 01F 8-F 0 4The contents of the accumulator are ORed, bit by bit, with the contents of the register(R). The result replaces the contents of the accumulator. The contents of the addressedregister are not changed.11,1111./110! 0u0, 111111101101101111. 0 0110110