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XtraEdge for IIT-JEE 80 MAY 2011
IIT-JEE 2011PAPER-II (PAPER & SOLUTION)Time : 3 Hours Total Marks : 240Instructions : [Each subject contain]Section – I :Section – II :Multiple choice questions with only one correct answer. +3 marks will be awarded for correct answerand -1 mark for wrong answer. [No. of Ques. : 8]Multiple choice questions with multiple correct answer. +4 marks will be awarded for correct answerand No Negative marking for wrong answer. [No. of Ques. : 4]Section – III : Numerical Response Question (single digit Ans. type) +4 marks will be awarded for correct answerand No Negative marking for wrong answer. [No. of Ques. : 6]Section – IV : Column Matching type question +2 marks for each correctly matched row and No Negative markingfor wrong answer. [No. of Ques. : 2]CHEMISTRYSECTION – ISingle Correct Choice TypeThis section contains 8 multiple choice questions. Eachquestion has 4 choices (A), (B), (C) and (D), out ofwhich ONLY ONE is correct.1. Oxidation states of the metal in the mineralshaematite and magnetite respectively, are(A) II, III in haematile and III in magnetite(B) II, III in haematite and II in magnetite(C) II in haematite and II, III in magnetite(D) III in haematite and II, III in magnetiteAns. [D]+ 3Sol. Haematite is F e2O3+ 2+ 3Magnetite is Fe 3 O 4 or FeO. Fe2O32. The following carbohydrate isH OHH OHOHOOHH OHH H(A) a ketohexose (B) an aldohexose(C) an α-furanose (D) an α-pyranoseAns. [B]Sol. Aldohexose3. The major product of the following reaction isRCH 2 OHH + (anhydrous)O(A) a hemiacetal (B) an acetal(C) an ether(D) an esterAns.Sol.[B]OR- CH 2 –OH⊕H (anhydrous)OOCH 2 –RAcetal4. Amongst the compounds given, the one thatwould form a brilliant colored dye on treatmentwith NaNO 2 in dill. HCl followed by addition toan alkaline solution of β -naphthol isN(CH 3 ) 2NHCH 3(A)(B)Ans.Sol.(C)[C]H 3 CNH 2(D)NaNO 2 + HCl (dil.)CH 3 NH 2 CH 30–5°CCH 3Alkaline solutionN = NHOColoured dyeCH 2 NH 2N 2 ClOH5. The freezing point (in °C) of a solution containing0.1 g of K 3 [Fe(CN) 6 ] (mol. wt. 329) in 100 g ofwater (k f = 1.86 K kg mol –1 ) is(A) –2.3 × 10 –2 (B) –5.7 × 10 –2(C) –5.7 × 10 –3 (D) –1.2 × 10 –2XtraEdge for IIT-JEE 81 MAY 2011
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Volume - 6 Issue - 11May, 2011 (Mon
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Volume-6 Issue-11May, 2011 (Monthly
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KNOW IIT-JEEBy Previous Exam Questi
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60 cmK 1 K 2VB5. A solid sphere of
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∴ cos A ==cos B ==cos C ==b22+ c
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Physics Challenging ProblemsSet # 1
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PHYSICSStudents'ForumExpert’s Sol
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Q 1 = 1200 JEnginel = 21 cma = 6 cm
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PHYSICS FUNDAMENTAL FOR IIT-JEEElec
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the indivual forces. It's often hel
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Hence, E x = -∴∂V∂ xE = - ayi
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For (x - a) 2 + (y - b) 2 = r 2 , t
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(If the velocities are not along th
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Page 54 and 55: 7. If the equation 3x 4 - 16x 3 + 3
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Page 58 and 59: 17. A stone is projected from level
Page 60 and 61: 16. Half a mole of photon is used t
Page 62 and 63: 17. Ifsin 3θcos 2θ2-147137= 0Then
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Page 66 and 67: 9. Amongst the given options, the c
Page 68 and 69: 22. The total number of alkenes pos
Page 70 and 71: 1 2 × 8∆U = × [V - 0]22 2 + 81
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Page 74 and 75: 40. A block is moving on an incline
Page 76 and 77: MATHEMATICSSECTION - ISingle Correc
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Page 80 and 81: ⎡323 21× ⎤=⎡32 1⎤1 C2C21 C
Page 84 and 85: Ans. [A]Sol. ∆T = k f × m × i
Page 86 and 87: SECTION - IVMatrix match TypeThis s
Page 88 and 89: Ans.[D]m 1 = 0.01 kgvH = 5mm 2 = 0.
Page 90 and 91: 31. A series R-C circuit is connect
Page 92 and 93: P3PBAColumn-I(A) Pipe closed at one
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Page 96 and 97: So f(x) is monotonically decreasing
Page 98 and 99: (C)25 / 6πI = x dxn ∫sec πl 327
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May 2011 - Career Point

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