May 2011 - Career Point
May 2011 - Career Point May 2011 - Career Point
9. Amongst the given options, the compound(s) inwhich all the atoms are in one plane in all thepossible conformations (if any), is (are)H HH(A) C–C(B) H–C≡C–CH 2 C CH 2CH 2(C) H 2 C=C=O (D) H 2 C=C=CH 2Ans. [B,C]Sol. Factual.10. The correct statement(s) pertaining to theadsorption of a gas on a solid surface is (are)(A) Adsorption is always exothermic(B) Physiosorption may transform intochemisorption at high temperature(C) Physiosorption increases with increasingtemperature but chemisorption decreaseswith increasing temperature(D) Chemisorption is more exothermic thanphysiosorption, however it is very slow dueto higher energy of activationAns. [A, B, D]Sol. Factual.11. According to kinetic theory of gases -(A) collisions are always elastic(B) heavier molecules transfer more momentumto the wall of the container(C) only a small number of molecules have veryhigh velocity(D) between collisions, the molecules move instraight lines with constant velocitiesAns. [A, D]Sol. Factual.SECTION – IIIParagraph TypeThis section contains 2 paragraphs. Based upon thefirst paragraph 3 multiple choice questions and basedupon the second paragraph 2 multiple choice questionshave to be answered. Each of these questions has fourchoices (A), (B), (C) and (D) out of which ONLY ONEis correct.Paragraph for Questions No. 12 to 14When a metal rod M is dipped into an aqueouscolourless concentrated solution of compound N,the solution turns light blue. Addition of aqueousNaCl to the blue solution gives a white precipitateO. Addition of aq. NH 3 dissolves O and gives anintense blue solution.12. The metal rod M is -(A) Fe(B) Cu(C) Ni(D) CoAns.Sol.[B]Metal rod M is Cu13. The compounds N is -(A) AgNO 3 (B) Zn(NO 3 ) 2(C) Al(NO 3 ) 3 (D) Pb(NO 3 ) 2Ans. [A]Sol. Cu + AgNO 3 (conc.) —→ Cu(NO 3 ) 2 + Aglight blue14. The final solution contains -(A) [Pb(NH 3 ) 4 ] 2+ and [CoCl 4 ] 2–(B) [Al(NH 3 ) 4 ] 3+ and [Cu(NH 3 ) 4 ] 2+(C) [Ag(NH 3 ) 2 ] + and [Cu(NH 3 ) 4 ] 2+(D) [Ag(NH 3 ) 2 ] + and [Ni(NH 3 ) 6 ] 2+Ans. [C]Sol. AgCl + NH 2 (aq) ⎯→ [Ag(NH 3 ) 2 ] +Cu +2 + NH 3 (aq) ⎯→ [Cu(NH 3 ) 4 ] +2Intense blueParagraph for Question No. 15 to 16An acyclic hydrocarbon P, having molecularformula C 6 H 10 , gave acetone as the only organicproduct through the following sequence ofreactions, in which Q is an intermediate organiccompound.(i) dil. H 2 SO 4 /HgSO 4P(ii) NaBH 4 /ethanol(C 6 H 10 ) (iii) dil. acidQ(i) conc. H 2 SO 4(catalytic amount)(–H 2 O)(ii) O 3(iii) Zn/H 2 O15. The structure of compound P is -(A) CH 3 CH 2 CH 2 CH 2 –C≡C–HAns.(B) H 3 CH 2 C–C≡C–CH 2 CH 3H 3 C(C) H–C–C≡C–CH 3H 3 CH 3 C(D) H 3 C–C–C ≡C–HH 3 C[D]O2 CH 3 C CH 3XtraEdge for IIT-JEE 64 MAY 2011
Sol.CH 3CH 3 –C–C≡C–HCH 3(P)(i) dil. H 2 SO 4 /HgSO 4(ii) NaBH 4(iii) dil. HClH 3 C–H 2 OCH 3CH 3 –C=C(i) conc. H 2 SO 4CH 3(ii) O 3 (iii) Zn/H 2 OCH 32 C=OCH 3H 3 C OHCH 3 –C–CH–CH 3CH 3(Q)Sol.O O⊕ Θ# ∗ ∗ Θ ⊕#NaO–S–S–S–S–ONaO OO.N. S * = 0O.N. S # = + 5∴ Difference = 519. The maximum number of electrons that can haveprincipal quantum number, n = 3 and spinquantum number, m s = – 1/2, is.Ans. [9]Sol. For n = 3, max e – = 2n 2 = 18Half of them can have m s = – 1/216. The structure of compound Q is -Ans.Sol.H 3 COH(A) H–C–C–CH 2 CH 3H 3 C HH 3 COH(B) H 3 C–C–C–CH 3H 3 C HH 3 C OH(C) H–C–CH 2 CHCH 3H 3 COH(D) CH 3 CH 2 CH 2 CHCH 2 CH 3[B]Factual.SECTION – IVNumerical Response TypeThis section contains. 7 questions. The answer to eachquestions is a single digit integer ranging from 0 to 9.The bubble corresponding to the correct answer is tobe darkened in the ORS.17. Reaction of Br 2 with Na 2 CO 3 in aq. solution givessodium bromide and sodium bromate withevolution of CO 2 gas. The number of sodiumbromide molecules involved in the balancedchemical equation is.Ans. [5]Sol. 3 Na 2 CO 3 + 3Br 2 → 5NaBr + NaBrO 3 + 3CO 218. The difference in the oxidation numbers of thetwo types of sulphur atoms in Na 2 S 4 O 6 is.Ans. [5]20. A decapeptide (mol. wt. 796) on completehydrolysis gives glycine (mol. wt. 75), alanineand phenylalanine. Glycine contributes 47.0% tothe total weight of the hydrolysed products. Thenumber of glycine units present in thedecapeptide is.Ans. [6]Sol.9 molecule⎯⎯⎯waterDecapeptide ⎯ → (x) glycine + (y)alanine + (z) phenylalanineMass of hydrolysed product = 796 + 18 × 947mass of glycine = 958 × = 450.26100450.26No. of glycine unit = = 67521. To an evacuated vessel with movable pistonunder external pressure of 1 atm., 0.1 mol of Heand 1.0 mol of an unknown compound (vapourpressure 0.68 atm, at 0ºC) are introduced.Considering the ideal gas behaviour, the totalvolume (in litre) of the gases at 0ºC is close to.Ans. [7]Sol.Pext = 1 atmHe +compoundsVapour pressure of compound = 0.68∴ P He = 1 – 0.68 = 0.32 ∴ By PV =nRT, for HenHe RT 0.1×0.0821×273V = =PHe0.32V ~ 7LXtraEdge for IIT-JEE 65 MAY 2011
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9. Amongst the given options, the compound(s) inwhich all the atoms are in one plane in all thepossible conformations (if any), is (are)H HH(A) C–C(B) H–C≡C–CH 2 C CH 2CH 2(C) H 2 C=C=O (D) H 2 C=C=CH 2Ans. [B,C]Sol. Factual.10. The correct statement(s) pertaining to theadsorption of a gas on a solid surface is (are)(A) Adsorption is always exothermic(B) Physiosorption may transform intochemisorption at high temperature(C) Physiosorption increases with increasingtemperature but chemisorption decreaseswith increasing temperature(D) Chemisorption is more exothermic thanphysiosorption, however it is very slow dueto higher energy of activationAns. [A, B, D]Sol. Factual.11. According to kinetic theory of gases -(A) collisions are always elastic(B) heavier molecules transfer more momentumto the wall of the container(C) only a small number of molecules have veryhigh velocity(D) between collisions, the molecules move instraight lines with constant velocitiesAns. [A, D]Sol. Factual.SECTION – IIIParagraph TypeThis section contains 2 paragraphs. Based upon thefirst paragraph 3 multiple choice questions and basedupon the second paragraph 2 multiple choice questionshave to be answered. Each of these questions has fourchoices (A), (B), (C) and (D) out of which ONLY ONEis correct.Paragraph for Questions No. 12 to 14When a metal rod M is dipped into an aqueouscolourless concentrated solution of compound N,the solution turns light blue. Addition of aqueousNaCl to the blue solution gives a white precipitateO. Addition of aq. NH 3 dissolves O and gives anintense blue solution.12. The metal rod M is -(A) Fe(B) Cu(C) Ni(D) CoAns.Sol.[B]Metal rod M is Cu13. The compounds N is -(A) AgNO 3 (B) Zn(NO 3 ) 2(C) Al(NO 3 ) 3 (D) Pb(NO 3 ) 2Ans. [A]Sol. Cu + AgNO 3 (conc.) —→ Cu(NO 3 ) 2 + Aglight blue14. The final solution contains -(A) [Pb(NH 3 ) 4 ] 2+ and [CoCl 4 ] 2–(B) [Al(NH 3 ) 4 ] 3+ and [Cu(NH 3 ) 4 ] 2+(C) [Ag(NH 3 ) 2 ] + and [Cu(NH 3 ) 4 ] 2+(D) [Ag(NH 3 ) 2 ] + and [Ni(NH 3 ) 6 ] 2+Ans. [C]Sol. AgCl + NH 2 (aq) ⎯→ [Ag(NH 3 ) 2 ] +Cu +2 + NH 3 (aq) ⎯→ [Cu(NH 3 ) 4 ] +2Intense blueParagraph for Question No. 15 to 16An acyclic hydrocarbon P, having molecularformula C 6 H 10 , gave acetone as the only organicproduct through the following sequence ofreactions, in which Q is an intermediate organiccompound.(i) dil. H 2 SO 4 /HgSO 4P(ii) NaBH 4 /ethanol(C 6 H 10 ) (iii) dil. acidQ(i) conc. H 2 SO 4(catalytic amount)(–H 2 O)(ii) O 3(iii) Zn/H 2 O15. The structure of compound P is -(A) CH 3 CH 2 CH 2 CH 2 –C≡C–HAns.(B) H 3 CH 2 C–C≡C–CH 2 CH 3H 3 C(C) H–C–C≡C–CH 3H 3 CH 3 C(D) H 3 C–C–C ≡C–HH 3 C[D]O2 CH 3 C CH 3XtraEdge for IIT-JEE 64 MAY <strong>2011</strong>
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