May 2011 - Career Point

aBased on New PatternIIT-JEE 2012XtraEdge Test Series # 1Time : 3 HoursSyllabus : Physics : Essential Mathematics, Vector, Units & Dimension, Motion in One dimension, Projectilemotion, Circular motion, Electrostatics & Gauss's Law, Capacitance, Current electricity, Alternating Current,Magnetic Field, E.M.I. Chemistry : Mole Concept, Chemical Bonding, Atomic Structure, Periodic Table, ChemicalKinetics, Electro Chemistry, Solid state, Solutions, Surface Chemistry, Nuclear Chemistry. Mathematics:Trigonometric Ratios, Trigonmetrical Equation, Inverse Trigonmetrical Functions, Properties of Triangle, Radii ofCircle, Function, Limit, Continiuty, Differentiation, Application of Differentiation (Tangent & Normal,Monotonicity, Maxima & Minima)Instructions : [Each subject contain]Section – I : Question 1 to 7 are multiple choice questions with only one correct answer. +3 marks will beawarded for correct answer and -1 mark for wrong answer.Section – II : Question 8 to 11 are multiple choice questions with multiple correct answer. +4 marks will beawarded for correct answer and No Negative marks for wrong answer.Section – III : Question 12 to 16 are passage based single correct type questions. +3 marks will be awarded forcorrect answer and -1 mark for wrong answer.Section – IV : Question 17 to 23 are Numerical Response Question (single digit Ans. type) +4 marks will beawarded for correct answer and No Negative marks for wrong answer.PHYSICSQuestion 1 to 7 are multiple choice questions. Eachquestions has four choices (A), (B), (C) and (D), out ofwhich ONLY ONE is correct.1. A rectangular piece of aluminum is 5.10 ± 0.01 cmlong and 1.90 ± 0.01 cm wide. The area of therectangle is written as -(A) (9.69 ± 0.03) cm 2 (B) (9.69 ± 0.01) cm 2(C) (9.69 ± 0.02) cm 2 (D) (9.69 ± 0.07) cm 22. One body fall freely from a point P at a heightH + h as shown in figure whilst another body isprojected upwards with an initial velocity v 0 . frompoint R at the same time as the first body begins tofall and second body meet at a point Q at a height h.The maximum height attained by of the secondbody for the given initial velocity is -P(A) H + h(C)(H + h)4H2HhQR(B)(D)(H + h)4h2(H + h)h23. The velocity of a car is given byv = (10 m/s 2 )t – (5 m/s 2 ) t 2Initially car at x = 0 at t = 0. Time taken by the carto reach its maximum positive x-coordinates is -(A) 0 s(B) 1 s(C) 2 s(D) 1.5 s4. For the circuit shown here keys k 1 and k 3 are closedfor 1 second. Key k 2 is closed at the instant k 1 andk 3 are opened. Maximum charge on the capacitorafter key k 2 is closed is –2V k 1⎛ 1 ⎞(A) 2⎜1–⎟Cb⎝ e ⎠⎛ 1 ⎞(C) 8⎜1–⎟Cb⎝ e ⎠2F4 V2 H2 Ω0.5 Ωk 2k 3⎛ 1 ⎞(B) 4 2⎜1–⎟Cb⎝ e ⎠(D) zeroXtraEdge for IIT-JEE 46 MAY 2011