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Introduction to Sports Biomechanics: Analysing Human Movement ...

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INTRODUCTION TO SPORTS BIOMECHANICS<br />

188<br />

By similar reasoning, if you are prepared <strong>to</strong> accept that displacement of the jumper’s<br />

centre of mass equals the area between the horizontal zero-velocity line – the time axis<br />

of the graph – and the velocity curve from the start of the movement at 0 up <strong>to</strong> any<br />

particular time, and, again, that areas below the time axis are negative and those above<br />

positive, then several key points on the displacement–time graph follow.<br />

At time B in Figure 5.12(b), the area (−A 4) under the time axis and above the vertical<br />

velocity–time curve from 0 <strong>to</strong> B reaches its greatest negative value, so the vertical<br />

displacement of the jumper’s centre of mass also reaches its greatest negative value<br />

there, corresponding <strong>to</strong> a zero velocity. We can then sketch the displacement graph<br />

in Figure 5.12(c) up <strong>to</strong> B. Please note that this is the lowest point reached by the<br />

jumper’s centre of mass at full hip and knee flexion, before the jumper starts <strong>to</strong> rise.<br />

At time T in Figure 5.12(b), the area (A 5) under the velocity–time curve from B <strong>to</strong> T<br />

and above the time axis is positive so the vertical displacement becomes less negative.<br />

Now we can sketch the vertical displacement curve from B <strong>to</strong> T in Figure<br />

5.12(c). Note that the maximum displacement will occur after the person has left<br />

the force plate at the peak of the jump.<br />

Note again, as in Chapter 2, the trend of peaks or, more obviously in this case, troughs<br />

is acceleration then velocity then displacement.<br />

Quantitative evaluation of a force–time or acceleration–time pattern<br />

Our volleyball coach may wish <strong>to</strong> obtain, from this acceleration–time curve, values for<br />

the magnitude of the vertical velocity at take-off and the maximum height reached by<br />

the player’s centre of mass. The process of obtaining velocities and displacements from<br />

accelerations qualitatively was outlined in the previous section. The quantitative process<br />

for doing the same thing is referred <strong>to</strong>, mathematically, as integration; it can be performed<br />

graphically or numerically. If quantitative acceleration data are available – Figure<br />

5.12(a) with the numbers shown on the axes if you like – we can integrate the<br />

acceleration data <strong>to</strong> obtain the velocity–time graph, as in Figure 5.12(b), which can, in<br />

turn, be integrated <strong>to</strong> give the displacement–time graph of Figure 5.12(c). Most quantitative<br />

ways of doing these integrations basically involve determining areas as above, but<br />

for increasing, small time intervals from left <strong>to</strong> right. A very slow but accurate way of<br />

doing this is counting areas under the curves drawn on graph paper. The resulting<br />

graphs, but with numbered axes as in Figure 5.12, would be more accurate than the<br />

‘sketched’ qualitative ones but the shapes should be very similar if the qualitative analyst<br />

unders<strong>to</strong>od well the process of obtaining the velocity and displacement patterns. Our<br />

volleyball coach could now simply read the vertical take-off velocity (v t) for each player<br />

from graphs such as Figure 5.12(b) at take-off, T (see Study task 2). We can calculate<br />

the maximum height (h) reached by a player’s centre of mass by equating his or her<br />

take-off kinetic energy, ½ m v t 2 , <strong>to</strong> the potential energy at the peak of the jump, m g h,<br />

where m is the player’s mass and g is gravitational acceleration, so h = v t 2 /(2g).

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