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Introduction to Sports Biomechanics: Analysing Human Movement ...

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CAUSES OF MOVEMENT – FORCES AND TORQUES<br />

approach may seem <strong>to</strong> be somewhat limited in sport, in which the net, or resultant,<br />

effect of the forces acting is usually <strong>to</strong> cause the performer or object <strong>to</strong> accelerate, as in<br />

Figure 5.10(a). In this figure, the resultant force can be obtained by moving the ground<br />

reaction force, F, along its line of action, which passes through the centre of mass in this<br />

case, giving Figure 5.10(b). As the resultant force passes through the runner’s centre of<br />

mass, the runner can be represented as a point, the centre of mass, at which the entire<br />

runner’s mass is considered <strong>to</strong> be concentrated: only changes in linear motion will occur<br />

for such a force system. The resultant of F and G will be the net force acting on the<br />

runner. This net force equals the mass of the runner, m, multiplied by the acceleration,<br />

a, of the centre of mass. Symbolically, this is written as F + G = m a. This is one form of<br />

New<strong>to</strong>n’s second law of motion (see Box 5.2).<br />

More generally, as in Figure 5.10(c), the resultant force will not act through the<br />

centre of mass; a <strong>to</strong>rque – also called a moment of force – will then tend <strong>to</strong> cause the<br />

runner <strong>to</strong> rotate about his or her centre of mass. The magnitude of this <strong>to</strong>rque about a<br />

point – here the centre of mass – is the product of the force and its moment arm, which<br />

is the perpendicular distance of the line of action of the force from that point. Rotation<br />

will be considered in detail later in this chapter.<br />

It is possible <strong>to</strong> treat dynamic systems of forces, such as those represented in<br />

Figure 5.10, using the equations of static equilibrium. To do this, however, we need <strong>to</strong><br />

introduce an imaginary force in<strong>to</strong> the dynamic system, which is equal in magnitude<br />

<strong>to</strong> the resultant force but opposite in direction, <strong>to</strong> produce a quasi-static force system.<br />

Figure 5.10 Forces on a runner: (a) free body diagram of dynamic force system; (b) resultant force; (c) free body diagram with<br />

force not through centre of mass.<br />

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